我在不可变字符串上写了下面的代码。

public class ImmutableStrings {

    public static void main(String[] args) {
        testmethod();
    }

    private static void testmethod() {
        String a = "a";
        System.out.println("a 1-->" + a);
        a = "ty";
        System.out.println("a 2-->" + a);
    }
}

输出:

a 1-->a  
a 2-->ty

这里变量a的值被改变了(尽管许多人说不可变对象的内容不能被改变)。但是说字符串是不可变的到底是什么意思呢?你能给我解释一下这个话题吗?

来源:https://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html


当前回答

不可变对象是创建后状态不能修改的对象。

a = "ABC" <——immutable object。"a"保存对对象的引用。 并且,a = "DEF" <——另一个不可变对象,"a"现在保存着对它的引用。

一旦你分配了一个字符串对象,该对象就不能在内存中被改变。

总之,您所做的就是将“a”的引用更改为一个新的字符串对象。

其他回答

你实际上得到了一个新字符串的引用,字符串本身没有被改变,因为它是不可变的。这是相关的。

See

维基百科上的不可变对象

你不是在改变赋值语句中的对象,而是用另一个不可变对象替换了一个不可变对象。Object String("a")不会变成String("ty"),它会被丢弃,对ty的引用会被写入a中。

相反,StringBuffer表示一个可变对象。你可以这样做:

StringBuffer b = new StringBuffer("Hello");
System.out.writeln(b);
b.append(", world!");
System.out.writeln(b);

在这里,您没有重新分配b:它仍然指向相同的对象,但该对象的内容已经更改。

If some object bar holds a reference to a mutable object foo and encapsulates some of its state in mutable aspects of foo's state, that will allow code which can change those aspects of foo to change the corresponding aspects of bar's state without actually touching bar or even knowing of its existence. Generally, this means that objects which encapsulate their own state using mutable objects must ensure that no references to those objects are exposed to any code which might unexpectedly mutate them. By contrast, if bar holds a reference to an object moo and only uses immutable aspects of moo other than identity to encapsulate its state, then bar can freely expose moo to outside code without worrying about anything the outside code might do to it.

可能上面提供的每个答案都是正确的,但我的答案是特定于使用hashCode()方法,以证明诸如,字符串…一旦创建就不能修改,修改后会在不同的内存位置产生新的值。

public class ImmutabilityTest {

    private String changingRef = "TEST_STRING";

    public static void main(String a[]) {

        ImmutabilityTest dn = new ImmutabilityTest();

        System.out.println("ChangingRef for TEST_STRING OLD : "
                + dn.changingRef.hashCode());

        dn.changingRef = "NEW_TEST_STRING";
        System.out.println("ChangingRef for NEW_TEST_STRING : "
                + dn.changingRef.hashCode());

        dn.changingRef = "TEST_STRING";
        System.out.println("ChangingRef for TEST_STRING BACK : "
                + dn.changingRef.hashCode());

        dn.changingRef = "NEW_TEST_STRING";
        System.out.println("ChangingRef for NEW_TEST_STRING BACK : "
                + dn.changingRef.hashCode());

        String str = new String("STRING1");
        System.out.println("String Class STRING1 : " + str.hashCode());

        str = new String("STRING2");
        System.out.println("String Class STRING2 : " + str.hashCode());

        str = new String("STRING1");
        System.out.println("String Class STRING1 BACK : " + str.hashCode());

        str = new String("STRING2");
        System.out.println("String Class STRING2 BACK : " + str.hashCode());

    }
}

输出

ChangingRef for TEST_STRING OLD : 247540830
ChangingRef for NEW_TEST_STRING : 970356767
ChangingRef for TEST_STRING BACK : 247540830
ChangingRef for NEW_TEST_STRING BACK : 970356767
String Class STRING1 : -1163776448
String Class STRING2 : -1163776447
String Class STRING1 BACK : -1163776448
String Class STRING2 BACK : -1163776447

在这里看到的

class ImmutableStrings {

    public static void main(String[] args) {
        testmethod();
    }

    private static void testmethod() {
    String a="a";
    System.out.println("a 1-->"+a);
    System.out.println("a 1 address-->"+a.hashCode());

    a = "ty";
    System.out.println("a 2-->"+a);

       System.out.println("a 2 address-->"+a.hashCode());
    }
}

输出:

a 1-->a
a 1 address-->97
a 2-->ty
a 2 address-->3717

这表明无论何时修改不可变字符串对象a的内容都会创建一个新对象。也就是说,你不允许改变不可变对象的内容。这就是为什么两个对象的地址是不同的。