方法下面检索七天，并返回短名称的天在列表数组在Kotlin，你可以重新格式化然后在Java格式，只是提出想法日历可以返回短名称

private fun getDayDisplayName():List<String>{
        val calendar = Calendar.getInstance()
        val dates= mutableListOf<String>()
        dates.clear()
        val s=   calendar.getDisplayName(DAY_OF_WEEK, SHORT, Locale.US)
        dates.add(s)
        for(i in 0..5){
            calendar.roll( Calendar.DATE, -1)
            dates.add(calendar.getDisplayName(DAY_OF_WEEK, SHORT, Locale.US))
        }
        return dates.toList()
    }

结果是这样的

I/System.out: Wed
    Tue
    Mon
    Sun
I/System.out: Sat
    Fri
    Thu

private String getDay(Date date){

    SimpleDateFormat simpleDateFormat = new SimpleDateFormat("EEEE");
    //System.out.println("DAY "+simpleDateFormat.format(date).toUpperCase());                       
    return simpleDateFormat.format(date).toUpperCase();
}

private String getDay(String dateStr){
    //dateStr must be in DD-MM-YYYY Formate
    Date date = null;
    String day=null;

    try {
        date = new SimpleDateFormat("DD-MM-YYYY").parse(dateStr);

        SimpleDateFormat simpleDateFormat = new SimpleDateFormat("EEEE");
        //System.out.println("DAY "+simpleDateFormat.format(date).toUpperCase());
        day = simpleDateFormat.format(date).toUpperCase();


    } catch (ParseException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }


    return day;
}

有一个关于hackerrank Java日期和时间的挑战

就我个人而言，我更喜欢LocalDate类。

进口java.time.LocalDate 使用“of”方法检索localDate，该方法包含3个参数 “int”格式。 最后，使用“getDayOfWeek”方法获取当天的名称。

有一个关于这个挑战的视频。

Java日期和时间Hackerrank解决方案

我希望它会有所帮助:)

是的。根据具体情况:

You can use java.util.Calendar: Calendar c = Calendar.getInstance(); c.setTime(yourDate); int dayOfWeek = c.get(Calendar.DAY_OF_WEEK); if you need the output to be Tue rather than 3 (Days of week are indexed starting at 1 for Sunday, see Calendar.SUNDAY), instead of going through a calendar, just reformat the string: new SimpleDateFormat("EE").format(date) (EE meaning "day of week, short version") if you have your input as string, rather than Date, you should use SimpleDateFormat to parse it: new SimpleDateFormat("dd/M/yyyy").parse(dateString) you can use joda-time's DateTime and call dateTime.dayOfWeek() and/or DateTimeFormat. edit: since Java 8 you can now use java.time package instead of joda-time

添加了另一种完全符合OP要求的方法，而不使用最新的内置方法:

public static String getDay(String inputDate) {
    String dayOfWeek = null;
    String[] days = new String[]{"Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun"};

    try {
        SimpleDateFormat format1 = new SimpleDateFormat("dd/MM/yyyy");
        Date dt1 = format1.parse(inputDate);
        dayOfWeek = days[dt1.getDay() - 1];
    } catch(Exception e) {
        System.out.println(e);
    }

    return dayOfWeek;
}

对于Java 8或更高版本，Localdate更可取

import java.time.LocalDate;

public static String findDay(int month, int day, int year) {

    LocalDate localDate = LocalDate.of(year, month, day);

    java.time.DayOfWeek dayOfWeek = localDate.getDayOfWeek();
    System.out.println(dayOfWeek);

    return dayOfWeek.toString();
}

注意:如果输入是字符串/用户定义的，那么你应该把它解析成int。