你可以通过以下几个Request字段来检查url:

Imagine your application is listening on the following application root: http://www.example.com/myapplication And a user requests the following URI: http://www.example.com/myapplication/foo/page.html?x=y In this case the values of the above mentioned attributes would be the following: path /foo/page.html full_path /foo/page.html?x=y script_root /myapplication base_url http://www.example.com/myapplication/foo/page.html url http://www.example.com/myapplication/foo/page.html?x=y url_root http://www.example.com/myapplication/

您可以使用适当的分割轻松地提取宿主部分。

使用这个的例子:

from flask import request

@app.route('/')
def index():
    return request.base_url

你应该试试:

request.url 

它应该总是工作，甚至在localhost(刚刚做了)。

另一个例子:

要求:

curl -XGET http://127.0.0.1:5000/alert/dingding/test?x=y

然后:

request.method:              GET
request.url:                 http://127.0.0.1:5000/alert/dingding/test?x=y
request.base_url:            http://127.0.0.1:5000/alert/dingding/test
request.url_charset:         utf-8
request.url_root:            http://127.0.0.1:5000/
str(request.url_rule):       /alert/dingding/test
request.host_url:            http://127.0.0.1:5000/
request.host:                127.0.0.1:5000
request.script_root:
request.path:                /alert/dingding/test
request.full_path:           /alert/dingding/test?x=y

request.args:                ImmutableMultiDict([('x', 'y')])
request.args.get('x'):       y

如果你正在使用Python，我建议通过探索请求对象:

dir(请求)

因为对象支持dict方法:

request.__dict__

它可以被打印或保存。我用它来记录Flask中的404代码:

@app.errorhandler(404)
def not_found(e):
    with open("./404.csv", "a") as f:
        f.write(f'{datetime.datetime.now()},{request.__dict__}\n')
    return send_file('static/images/Darknet-404-Page-Concept.png', mimetype='image/png')