from collections import Counter

y = Counter(y)
x = Counter(x)

print(list(x-y))

list1 = ['a', 'c', 'a', 'b', 'k'] 
list2 = ['a', 'a', 'a', 'a', 'b', 'c', 'c', 'd', 'e', 'f'] 
for e in list1: 
    try: 
        list2.remove(e) 
    except ValueError: 
        print(f'{e} not in list') 
list2 
# ['a', 'a', 'c', 'd', 'e', 'f']

这将改变list2。如果你想保护list2，只需复制它，并在这段代码中使用list2的副本。

使用集合差

>>> z = list(set(x) - set(y))
>>> z
[0, 8, 2, 4, 6]

或者你可以让x和y是集合所以你不需要做任何转换。

试试这个。

def subtract_lists(a, b):
    """ Subtracts two lists. Throws ValueError if b contains items not in a """
    # Terminate if b is empty, otherwise remove b[0] from a and recurse
    return a if len(b) == 0 else [a[:i] + subtract_lists(a[i+1:], b[1:]) 
                                  for i in [a.index(b[0])]][0]

>>> x = [1,2,3,4,5,6,7,8,9,0]
>>> y = [1,3,5,7,9]
>>> subtract_lists(x,y)
[2, 4, 6, 8, 0]
>>> x = [1,2,3,4,5,6,7,8,9,0,9]
>>> subtract_lists(x,y)
[2, 4, 6, 8, 0, 9]     #9 is only deleted once
>>>

如果重复和订购项目是问题:

[i为a中的i，如果不是b中的i或b中的i，删除(i)]

a = [1,2,3,3,3,3,4]
b = [1,3]
result: [2, 3, 3, 3, 4]

@aaronasterling提供的答案看起来不错，但是，它与列表的默认接口不兼容:x = MyList(1,2,3,4) vs x = MyList([1,2,3,4])。因此，下面的代码可以用作更友好的python列表:

class MyList(list):
    def __init__(self, *args):
        super(MyList, self).__init__(*args)

    def __sub__(self, other):
        return self.__class__([item for item in self if item not in other])

例子:

x = MyList([1, 2, 3, 4])
y = MyList([2, 5, 2])
z = x - y