我正在使用python3.3,当我试图pickle一个简单的字典时,我有一个神秘的错误。

代码如下:

import os
import pickle
from pickle import *
os.chdir('c:/Python26/progfiles/')

def storvars(vdict):      
    f = open('varstor.txt','w')
    pickle.dump(vdict,f,)
    f.close()
    return

mydict = {'name':'john','gender':'male','age':'45'}
storvars(mydict)

得到:

Traceback (most recent call last):
  File "C:/Python26/test18.py", line 31, in <module>
    storvars(mydict)
  File "C:/Python26/test18.py", line 14, in storvars
    pickle.dump(vdict,f,)
TypeError: must be str, not bytes

当前回答

输出文件需要以二进制方式打开:

f = open('varstor.txt','w')

需要:

f = open('varstor.txt','wb')

其他回答

我也有同样的问题。在Python 3中,必须指定二进制模式'wb', 'rb',而在Python 2x中,不需要它们。当你遵循基于Python 2x的教程时,这就是你在这里的原因。

import pickle

class MyUser(object):
    def __init__(self,name):
        self.name = name

user = MyUser('Peter')

print("Before serialization: ")
print(user.name)
print("------------")
serialized = pickle.dumps(user)
filename = 'serialized.native'

with open(filename,'wb') as file_object:
    file_object.write(serialized)

with open(filename,'rb') as file_object:
    raw_data = file_object.read()

deserialized = pickle.loads(raw_data)


print("Loading from serialized file: ")
user2 = deserialized
print(user2.name)
print("------------")

输出文件需要以二进制方式打开:

f = open('varstor.txt','w')

需要:

f = open('varstor.txt','wb')

Pickle使用二进制协议,因此只接受二进制文件。正如文档的第一句所说,“pickle模块实现了用于序列化和反序列化的二进制协议”。