我怎样才能得到字符串的第n个字符?我尝试了括号([])访问器,没有运气。
var string = "Hello, world!"
var firstChar = string[0] // Throws error
错误:'下标'是不可用的:不能下标String与Int,请参阅文档注释讨论
我怎样才能得到字符串的第n个字符?我尝试了括号([])访问器,没有运气。
var string = "Hello, world!"
var firstChar = string[0] // Throws error
错误:'下标'是不可用的:不能下标String与Int,请参阅文档注释讨论
当前回答
斯威夫特5.1
这可能是所有答案中最简单的一个。
添加这个扩展:
extension String {
func retrieveFirstCharacter() -> String? {
guard self.count > 0 else { return nil }
let numberOfCharacters = self.count
return String(self.dropLast(numberOfCharacters - 1))
}
}
其他回答
在Swift 5中,不扩展字符串:
var str = "ABCDEFGH"
for char in str {
if(char == "C") { }
}
以上Swift代码与Java代码相同:
int n = 8;
var str = "ABCDEFGH"
for (int i=0; i<n; i++) {
if (str.charAt(i) == 'C') { }
}
斯威夫特4.2
这个答案是理想的,因为它在一个扩展中扩展了String及其所有子序列(Substring)
public extension StringProtocol {
public subscript (i: Int) -> Element {
return self[index(startIndex, offsetBy: i)]
}
public subscript (bounds: CountableClosedRange<Int>) -> SubSequence {
let start = index(startIndex, offsetBy: bounds.lowerBound)
let end = index(startIndex, offsetBy: bounds.upperBound)
return self[start...end]
}
public subscript (bounds: CountableRange<Int>) -> SubSequence {
let start = index(startIndex, offsetBy: bounds.lowerBound)
let end = index(startIndex, offsetBy: bounds.upperBound)
return self[start..<end]
}
public subscript (bounds: PartialRangeUpTo<Int>) -> SubSequence {
let end = index(startIndex, offsetBy: bounds.upperBound)
return self[startIndex..<end]
}
public subscript (bounds: PartialRangeThrough<Int>) -> SubSequence {
let end = index(startIndex, offsetBy: bounds.upperBound)
return self[startIndex...end]
}
public subscript (bounds: CountablePartialRangeFrom<Int>) -> SubSequence {
let start = index(startIndex, offsetBy: bounds.lowerBound)
return self[start..<endIndex]
}
}
使用
var str = "Hello, playground"
print(str[5...][...5][0])
// Prints ","
在Swift 3中,没有对String类的扩展,就像我能做的那样简单!
let myString = "abcedfg"
let characterLocationIndex = myString.index(myString.startIndex, offsetBy: 3)
let myCharacter = myString[characterLocationIndex]
本例中的myCharacter为“3”。
Swift的String类型没有提供characterAtIndex方法,因为Unicode字符串有几种编码方式。你要用UTF8, UTF16,还是别的?
您可以通过检索String来访问CodeUnit集合。utf8和String。utf16属性。您还可以通过检索String来访问UnicodeScalar集合。unicodeScalars财产。
在NSString实现的精神中,我返回一个unichar类型。
extension String
{
func characterAtIndex(index:Int) -> unichar
{
return self.utf16[index]
}
// Allows us to use String[index] notation
subscript(index:Int) -> unichar
{
return characterAtIndex(index)
}
}
let text = "Hello Swift!"
let firstChar = text[0]
一个类似蟒蛇的解决方案,允许你使用负下标,
var str = "Hello world!"
str[-1] // "!"
可能是:
extension String {
subscript (var index:Int)->Character{
get {
let n = distance(self.startIndex, self.endIndex)
index %= n
if index < 0 { index += n }
return self[advance(startIndex, index)]
}
}
}
顺便说一下,调换整个python的切片符号可能是值得的