这在Oracle中是有效的:

insert into pager (PAG_ID,PAG_PARENT,PAG_NAME,PAG_ACTIVE)
          select 8000,0,'Multi 8000',1 from dual
union all select 8001,0,'Multi 8001',1 from dual

这里要记住的是使用from对偶语句。

每当我需要这样做的时候，我用一个本地过程构建一个简单的PL/SQL块:

declare
   procedure ins
   is
      (p_exch_wh_key INTEGER, 
       p_exch_nat_key INTEGER, 
       p_exch_date DATE, exch_rate NUMBER, 
       p_from_curcy_cd VARCHAR2, 
       p_to_curcy_cd VARCHAR2, 
       p_exch_eff_date DATE, 
       p_exch_eff_end_date DATE, 
       p_exch_last_updated_date DATE);
   begin
      insert into tmp_dim_exch_rt 
      (exch_wh_key, 
       exch_nat_key, 
       exch_date, exch_rate, 
       from_curcy_cd, 
       to_curcy_cd, 
       exch_eff_date, 
       exch_eff_end_date, 
       exch_last_updated_date) 
      values
      (p_exch_wh_key, 
       p_exch_nat_key, 
       p_exch_date, exch_rate, 
       p_from_curcy_cd, 
       p_to_curcy_cd, 
       p_exch_eff_date, 
       p_exch_eff_end_date, 
       p_exch_last_updated_date);
   end;
begin
   ins (1, 1, '28-AUG-2008', 109.49, 'USD', 'JPY', '28-AUG-2008', '28-AUG-2008', '28-AUG-2008'),
   ins (2, 1, '28-AUG-2008', .54, 'USD', 'GBP', '28-AUG-2008', '28-AUG-2008', '28-AUG-2008'),
   ins (3, 1, '28-AUG-2008', 1.05, 'USD', 'CAD', '28-AUG-2008', '28-AUG-2008', '28-AUG-2008'),
   ins (4, 1, '28-AUG-2008', .68, 'USD', 'EUR', '28-AUG-2008', '28-AUG-2008', '28-AUG-2008'),
   ins (5, 1, '28-AUG-2008', 1.16, 'USD', 'AUD', '28-AUG-2008', '28-AUG-2008', '28-AUG-2008'),
   ins (6, 1, '28-AUG-2008', 7.81, 'USD', 'HKD', '28-AUG-2008', '28-AUG-2008', '28-AUG-2008');
end;
/

使用SQL *加载程序。这需要一点设置，但如果这不是唯一的，它是值得的。

创建表

SQL> create table ldr_test (id number(10) primary key, description varchar2(20));
Table created.
SQL>

创建CSV

oracle-2% cat ldr_test.csv
1,Apple
2,Orange
3,Pear
oracle-2% 

创建Loader控制文件

oracle-2% cat ldr_test.ctl 
load data

 infile 'ldr_test.csv'
 into table ldr_test
 fields terminated by "," optionally enclosed by '"'              
 ( id, description )

oracle-2% 

执行SQL*Loader命令

oracle-2% sqlldr <username> control=ldr_test.ctl
Password:

SQL*Loader: Release 9.2.0.5.0 - Production on Wed Sep 3 12:26:46 2008

Copyright (c) 1982, 2002, Oracle Corporation.  All rights reserved.

Commit point reached - logical record count 3

确认插入

SQL> select * from ldr_test;

        ID DESCRIPTION
---------- --------------------
         1 Apple
         2 Orange
         3 Pear

SQL>

SQL*Loader有很多选项，并且可以将几乎任何文本文件作为输入。如果需要，您甚至可以将数据内联到控制文件中。

这里有一个页面，有更多的细节-> SQL*Loader

在我的例子中，我能够使用一个简单的插入语句批量插入许多行到TABLE_A中，只使用TABLE_B中的一列，并在其他地方获取其他数据(序列和硬编码的值):

INSERT INTO table_a (
    id,
    column_a,
    column_b
)
    SELECT
        table_a_seq.NEXTVAL,
        b.name,
        123
    FROM
        table_b b;

结果:

ID: NAME: CODE:
1, JOHN, 123
2, SAM, 123
3, JESS, 123

etc

如果已经有想要插入到另一个表中的值，那么可以从选择语句中插入。

INSERT INTO a_table (column_a, column_b) SELECT column_a, column_b FROM b_table;

否则，您可以列出一堆单行插入语句，并批量提交几个查询，以节省在Oracle和MySQL中同时工作的时间。

@Espo的解决方案也是一个很好的解决方案，如果你的数据还没有在一个表中，它可以在Oracle和MySQL中工作。

下面是一个非常有用的在Oracle中插入多行的指南:

https://livesql.oracle.com/apex/livesql/file/content_BM1LJQ87M5CNIOKPOWPV6ZGR3.html

最后一步:

INSERT ALL
/* Everyone is a person, so insert all rows into people */
WHEN 1=1 THEN
INTO people (person_id, given_name, family_name, title)
VALUES (id, given_name, family_name, title)
/* Only people with an admission date are patients */
WHEN admission_date IS NOT NULL THEN
INTO patients (patient_id, last_admission_date)
VALUES (id, admission_date)
/* Only people with a hired date are staff */
WHEN hired_date IS NOT NULL THEN
INTO staff (staff_id, hired_date)
VALUES (id, hired_date)
  WITH names AS (
    SELECT 4 id, 'Ruth' given_name, 'Fox' family_name, 'Mrs' title,
           NULL hired_date, DATE'2009-12-31' admission_date
    FROM   dual UNION ALL
    SELECT 5 id, 'Isabelle' given_name, 'Squirrel' family_name, 'Miss' title ,
           NULL hired_date, DATE'2014-01-01' admission_date
    FROM   dual UNION ALL
    SELECT 6 id, 'Justin' given_name, 'Frog' family_name, 'Master' title,
           NULL hired_date, DATE'2015-04-22' admission_date
    FROM   dual UNION ALL
    SELECT 7 id, 'Lisa' given_name, 'Owl' family_name, 'Dr' title,
           DATE'2015-01-01' hired_date, NULL admission_date
    FROM   dual
  )
  SELECT * FROM names