也许是时间的问题,也许是我淹没在稀疏的文档中,无法理解Mongoose中的更新概念:)

事情是这样的:

我有一个联系模式和模型(缩短属性):

var mongoose = require('mongoose'),
    Schema = mongoose.Schema;

var mongooseTypes = require("mongoose-types"),
    useTimestamps = mongooseTypes.useTimestamps;


var ContactSchema = new Schema({
    phone: {
        type: String,
        index: {
            unique: true,
            dropDups: true
        }
    },
    status: {
        type: String,
        lowercase: true,
        trim: true,
        default: 'on'
    }
});
ContactSchema.plugin(useTimestamps);
var Contact = mongoose.model('Contact', ContactSchema);

我从客户端收到一个请求,包含我需要的字段,然后使用我的模型:

mongoose.connect(connectionString);
var contact = new Contact({
    phone: request.phone,
    status: request.status
});

现在问题来了:

If I call contact.save(function(err){...}) I'll receive an error if the contact with the same phone number already exists (as expected - unique) I can't call update() on contact, since that method does not exist on a document If I call update on the model: Contact.update({phone:request.phone}, contact, {upsert: true}, function(err{...}) I get into an infinite loop of some sorts, since the Mongoose update implementation clearly doesn't want an object as the second parameter. If I do the same, but in the second parameter I pass an associative array of the request properties {status: request.status, phone: request.phone ...} it works - but then I have no reference to the specific contact and cannot find out its createdAt and updatedAt properties.

因此,我的底线是:给定一个文档联系人,如果它存在,我如何更新它,如果它不存在,我如何添加它?

谢谢你的时间。


当前回答

如果生成器可用,这将变得更加简单:

var query = {'username':this.req.user.username};
this.req.newData.username = this.req.user.username;
this.body = yield MyModel.findOneAndUpdate(query, this.req.newData).exec();

其他回答

这个coffeescript为我与节点工作-技巧是_id获取剥离了它的ObjectID包装时,发送和返回从客户端,所以这需要替换为更新(当没有_id提供,保存将恢复到插入和添加一个)。

app.post '/new', (req, res) ->
    # post data becomes .query
    data = req.query
    coll = db.collection 'restos'
    data._id = ObjectID(data._id) if data._id

    coll.save data, {safe:true}, (err, result) ->
        console.log("error: "+err) if err
        return res.send 500, err if err

        console.log(result)
        return res.send 200, JSON.stringify result
//Here is my code to it... work like ninj

router.param('contractor', function(req, res, next, id) {
  var query = Contractors.findById(id);

  query.exec(function (err, contractor){
    if (err) { return next(err); }
    if (!contractor) { return next(new Error("can't find contractor")); }

    req.contractor = contractor;
    return next();
  });
});

router.get('/contractors/:contractor/save', function(req, res, next) {

    contractor = req.contractor ;
    contractor.update({'_id':contractor._id},{upsert: true},function(err,contractor){
       if(err){ 
            res.json(err);
            return next(); 
            }
    return res.json(contractor); 
  });
});


--

这对我很管用。

App.put ('/student/:id', (req, res) => { Student.findByIdAndUpdate (req.params。id,点播。Body (err, user) => { 如果(err) { 返回res .status (500) .send({错误:“失败”}) }; res.send({成功:“成功”}); }); });

我只是在一段时间后回到这个问题上,并决定基于Aaron Mast的答案发布一个插件。

https://www.npmjs.com/package/mongoose-recursive-upsert

将其作为猫鼬插件使用。它设置一个静态方法,递归地合并传入的对象。

Model.upsert({unique: 'value'}, updateObject});

在阅读了上面的文章之后,我决定使用下面的代码:

    itemModel.findOne({'pid':obj.pid},function(e,r){
        if(r!=null)
        {
             itemModel.update({'pid':obj.pid},obj,{upsert:true},cb);
        }
        else
        {
            var item=new itemModel(obj);
            item.save(cb);
        }
    });

如果r为空,则创建新项。否则,在update中使用upsert,因为update不会创建新项。