Xcode 3.2在Build菜单下提供了一个很棒的新功能,“Build and Archive”,它可以生成一个适合Ad Hoc分发的。ipa文件。你也可以打开管理器,选择“存档应用程序”和“向iTunesConnect提交应用程序”。

有没有办法从命令行(作为构建脚本的一部分)使用“构建和存档”?我假设xcodebuild会以某种方式涉及到,但手册页似乎没有说任何关于这方面的内容。

Michael Grinich要求澄清;以下是你不能用命令行构建的功能,这些功能你只能在“构建和存档”之后用Xcode的管理器实现。

You can click "Share Application..." to share your IPA with beta testers. As Guillaume points out below, due to some Xcode magic, this IPA file does not require a separately distributed .mobileprovision file that beta testers need to install; that's magical. No command-line script can do it. For example, Arrix's script (submitted May 1) does not meet that requirement. More importantly, after you've beta tested a build, you can click "Submit Application to iTunes Connect" to submit that EXACT same build to Apple, the very binary you tested, without rebuilding it. That's impossible from the command line, because signing the app is part of the build process; you can sign bits for Ad Hoc beta testing OR you can sign them for submission to the App Store, but not both. No IPA built on the command-line can be beta tested on phones and then submitted directly to Apple.

我希望有人能来证明我是错的:这两个功能在Xcode GUI中都很好用,不能从命令行复制。


当前回答

我发现了如何从命令行自动化构建和归档过程,我刚刚写了一篇博客文章来解释如何实现这一点。

你必须使用的命令是xcrun:

/usr/bin/xcrun -sdk iphoneos PackageApplication \
-v "${RELEASE_BUILDDIR}/${APPLICATION_NAME}.app" \
-o "${BUILD_HISTORY_DIR}/${APPLICATION_NAME}.ipa" \
--sign "${DEVELOPER_NAME}" \
--embed "${PROVISONING_PROFILE}"

你可以在文章中找到所有的细节。如果你有任何问题,不要犹豫,尽管问。

其他回答

用Xcode 9和Swift更新我的答案

存档

xcodebuild -workspace <ProjectName>/<ProjectName>.xcworkspace \
  -scheme <schemeName> clean archive -configuration release \
  -sdk iphoneos -archivePath <ProjectName>.xcarchive

IPA输出(请注意输出选项plist)

xcodebuild -exportArchive -archivePath  <ProjectName>.xcarchive \
  -exportOptionsPlist  <ProjectName>/exportOptions.plist \
  -exportPath  <ProjectName>.ipa

对于那些不了解exportOptions.plist的人, https://blog.bitrise.io/post/new-export-options-plist-in-xcode-9


那些在CI/CD工具(如teamcity/jenkins)中使用此工具构建项目的人,请确保您在构建代理中安装了正确的Xcode用于存档和导出。

您可以使用以下两个选项中的任何一个。

使用xcodebuild的完整路径,

/Applications/Xcode 9.3.1.app/Contents/Developer/usr/bin/xcodebuild

使用xcode-select,

xcode-select -switch /Applications/Xcode 9.3.1.app

以下是我以前的回答

下面是创建存档和IPA示例的命令行脚本。 我有一个iPhone xcode项目,位于Desktop/MyiOSApp文件夹。

依次执行以下命令:

cd /Users/username/Desktop/MyiOSApp/

xcodebuild -scheme MyiOSApp archive \
  -archivePath /Users/username/Desktop/MyiOSApp.xcarchive

xcodebuild -exportArchive -exportFormat ipa \
  -archivePath "/Users/username/Desktop/MyiOSApp.xcarchive" \
  -exportPath "/Users/username/Desktop/MyiOSApp.ipa" \
  -exportProvisioningProfile "MyCompany Distribution Profile"

这是用Xcode 5测试的,对我来说工作很好。

我已经给出了一个简单的步骤描述,并在使用下面的终端生成ipa时传递参数:

Go to the folder which contains the MyApp.xcodeproject file in terminal By using the command given below you will get all the Targets of the application /usr/bin/xcodebuild -list After the above command is executed, you will get a list of targets of which you should select a specific target you need to generate .ipa /usr/bin/xcodebuild -target $TARGET -sdk iphoneos -configuration Release The above command builds the project and creates a .app file.The path to locate the .app file is ./build/Release-iphoneos/MyApp.app After Build gets succeeded then execute the following command to generate .ipa of the application using Developer Name and Provisioning Profile using the syntax below: /usr/bin/xcrun -sdk iphoneos PackageApplication -v “${TARGET}.app” -o “${OUTDIR}/${TARGET}.ipa” –sign “${IDENTITY}” –embed “${PROVISONING_PROFILE}”

以上语法中每个参数的解释:

${TARGET}.app                == Target path (ex :/Users/XXXXXX/desktop/Application/build/Release-iphoneos/MyApp.app)
${OUTDIR}                    == Select the output directory(Where you want to save .ipa file)
${IDENTITY}                   == iPhone Developer: XXXXXXX (XXXXXXXXXX)(which can be obtained from Keychain access)
${PROVISONING_PROFILE}   == Path to the provisioning profile(/Users/XXXXXX/Library/MobileDevice/Provisioning Profiles/XXXXXXXX-XXXX-XXXX-XXXX-XXXXXXXXXXXX.mobileprovision”)

ipa将生成在选定的输出目录"${OUTDIR}"

你是指验证/共享/提交选项吗?我认为这些都是Xcode特有的,不适合命令行构建工具。

如果有点聪明的话,我打赌你可以编写一个脚本来为你做这件事。看起来它们只是存储在~/Library/MobileDevice/Archived Applications/中,有一个uuddi和一个plist。我也无法想象反向工程验证器会有那么难。

我感兴趣的自动化过程是将构建版本发送给beta测试人员。(因为App Store很少提交,所以我不介意手动完成,特别是因为我经常需要添加新的描述文本。)通过使用Xcode的CLI执行伪Build+Archive,我可以从每次代码提交中触发自动构建,创建带有嵌入式配置文件的IPA文件,并将其通过电子邮件发送给测试人员。

我发现这里的其他一些答案很难展开。这篇文章为我做到了。有些路径可能需要是绝对的,正如在其他答案中提到的那样。

命令:

xcrun -sdk iphoneos PackageApplication \
    "/path/to/build/MyApp.app" \
    -o "output/path/to/MyApp.ipa" \
    --sign "iPhone Distribution: My Company" \
    --embed "/path/to/something.mobileprovision"

如果您使用下一个工具:https://github.com/nomad/shenzhen

那么这个任务就很简单了:

which ipa 1>/dev/null 2>&1 || echo 'no shenzhen. to install use: sudo gem install shenzhen --no-ri --no-rdoc'
ipa build --verbose --scheme "${schemeName}"