Xcode 3.2在Build菜单下提供了一个很棒的新功能,“Build and Archive”,它可以生成一个适合Ad Hoc分发的。ipa文件。你也可以打开管理器,选择“存档应用程序”和“向iTunesConnect提交应用程序”。

有没有办法从命令行(作为构建脚本的一部分)使用“构建和存档”?我假设xcodebuild会以某种方式涉及到,但手册页似乎没有说任何关于这方面的内容。

Michael Grinich要求澄清;以下是你不能用命令行构建的功能,这些功能你只能在“构建和存档”之后用Xcode的管理器实现。

You can click "Share Application..." to share your IPA with beta testers. As Guillaume points out below, due to some Xcode magic, this IPA file does not require a separately distributed .mobileprovision file that beta testers need to install; that's magical. No command-line script can do it. For example, Arrix's script (submitted May 1) does not meet that requirement. More importantly, after you've beta tested a build, you can click "Submit Application to iTunes Connect" to submit that EXACT same build to Apple, the very binary you tested, without rebuilding it. That's impossible from the command line, because signing the app is part of the build process; you can sign bits for Ad Hoc beta testing OR you can sign them for submission to the App Store, but not both. No IPA built on the command-line can be beta tested on phones and then submitted directly to Apple.

我希望有人能来证明我是错的:这两个功能在Xcode GUI中都很好用,不能从命令行复制。


当前回答

尝试xctool,它是苹果xcodebuild的替代品,可以更容易地构建和测试iOS和Mac产品。它对持续集成特别有帮助。它有一些额外的功能:

运行与Xcode.app相同的测试。 构建和测试结果的结构化输出。 人性化的,ansi彩色输出。

3号非常有用。我不知道是否有人能读懂xcodebuild的控制台输出,我不能,通常它给了我一行5000+字符。比论文还难读。

xctool: https://github.com/facebook/xctool

其他回答

我已经给出了一个简单的步骤描述,并在使用下面的终端生成ipa时传递参数:

Go to the folder which contains the MyApp.xcodeproject file in terminal By using the command given below you will get all the Targets of the application /usr/bin/xcodebuild -list After the above command is executed, you will get a list of targets of which you should select a specific target you need to generate .ipa /usr/bin/xcodebuild -target $TARGET -sdk iphoneos -configuration Release The above command builds the project and creates a .app file.The path to locate the .app file is ./build/Release-iphoneos/MyApp.app After Build gets succeeded then execute the following command to generate .ipa of the application using Developer Name and Provisioning Profile using the syntax below: /usr/bin/xcrun -sdk iphoneos PackageApplication -v “${TARGET}.app” -o “${OUTDIR}/${TARGET}.ipa” –sign “${IDENTITY}” –embed “${PROVISONING_PROFILE}”

以上语法中每个参数的解释:

${TARGET}.app                == Target path (ex :/Users/XXXXXX/desktop/Application/build/Release-iphoneos/MyApp.app)
${OUTDIR}                    == Select the output directory(Where you want to save .ipa file)
${IDENTITY}                   == iPhone Developer: XXXXXXX (XXXXXXXXXX)(which can be obtained from Keychain access)
${PROVISONING_PROFILE}   == Path to the provisioning profile(/Users/XXXXXX/Library/MobileDevice/Provisioning Profiles/XXXXXXXX-XXXX-XXXX-XXXX-XXXXXXXXXXXX.mobileprovision”)

ipa将生成在选定的输出目录"${OUTDIR}"

为了改进Vincent的回答,我写了一个脚本:xcodearchive 它允许您通过命令行存档(生成ipa)您的项目。 可以把它看作xcodebuild命令的姐妹,但用于归档。

代码可在github: http://github.com/gcerquant/xcodearchive

该脚本的一个选项是启用dSYM符号在时间戳存档中的存档。没有理由不再保留这些符号,也没有理由不再标记以后可能收到的崩溃日志。

在Xcode 4.2中,你可以使用-scheme标志来做到这一点:

xcodebuild -scheme <SchemeName> archive

执行此命令后,档案文件将显示在Xcode管理器中。

实际上,你可以像XCode一样重新编译,这样你就可以测试和发布相同的二进制代码。例如,在我的脚本中(类似于上面的脚本),我以AdHoc构建的形式构建了我的发布版本,然后我将其归档为IPA进行测试,然后使用我的分发证书并创建一个zip文件,这是我发送给苹果的文件。相关的台词是:

codesign -f -vv -s "$DistributionIdentity" "$APPDIR"

进入你的项目根目录,然后:

xcodebuild -project projectname -activetarget -activeconfiguration archive