django在执行makemigrations命令时没有检测到要迁移的内容有多种可能的原因。

migration folder You need a migrations package in your app. INSTALLED_APPS You need your app to be specified in the INSTALLED_APPS .dict Verbosity start by running makemigrations -v 3 for verbosity. This might shed some light on the problem. Full path In INSTALLED_APPS it is recommended to specify the full module app config path 'apply.apps.MyAppConfig' --settings you might want to make sure the correct settings file is set: manage.py makemigrations --settings mysite.settings specify app name explicitly put the app name in manage.py makemigrations myapp - that narrows down the migrations for the app alone and helps you isolate the problem. model meta check you have the right app_label in your model meta Debug django debug django core script. makemigrations command is pretty much straight forward. Here's how to do it in pycharm. change your script definition accordingly (ex: makemigrations --traceback myapp)

多个数据库:

当使用django的Db Router时，Router类(你的自定义Router类)需要实现allow_syncdb方法。

Makemigrations总是为模型更改创建迁移，但是如果 allow_migrate()返回False，

我这样解决了这个问题:

Erase the "db.sqlite3" file. The issue here is that your current data base will be erased, so you will have to remake it again. Inside the migrations folder of your edited app, erase the last updated file. Remember that the first created file is: "0001_initial.py". For example: I made a new class and register it by the "makemigrations" and "migrate" procedure, now a new file called "0002_auto_etc.py" was created; erase it. Go to the "pycache" folder (inside the migrations folder) and erase the file "0002_auto_etc.pyc". Finally, go to the console and use "python manage.py makemigrations" and "python manage.py migrate".

当向django api应用程序添加新模型并运行python manage.py makemigrations时，工具没有检测到任何新模型。

奇怪的是，旧模型确实被makemigrations选中了，但这是因为它们在urlpatterns链中被引用，而工具以某种方式检测到了它们。所以要注意这种行为。

这个问题是因为与models包对应的目录结构有子包，并且所有__init__.py文件都是空的。它们必须显式地在每个子文件夹和__init__.py模型中导入所有必需的类，以便Django使用makemigrationations工具来获取它们。

models
  ├── __init__.py          <--- empty
  ├── patient
  │   ├── __init__.py      <--- empty
  │   ├── breed.py
  │   └── ...
  ├── timeline
  │   ├── __init__.py      <-- empty
  │   ├── event.py
  │   └── ...

我忘记写正确的论点了

class LineInOffice(models.Model):   # here
    addressOfOffice = models.CharField("Корхоная жош",max_length= 200)   #and here
    ...

在models.py 然后就不那么烦人了

在应用程序“myApp”中未检测到任何变化

我有一个属性与我试图用makemigrations添加的字段同名。

我读过很多关于这个问题的答案，通常都是简单地用其他方式进行移民。但对我来说，问题在于模型的Meta子类。

我有一个应用程序配置，说label = <应用程序名称>(在apps.py文件，旁边的models.py, views.py等)。如果你的元类没有与应用标签相同的标签(例如，因为你把一个太大的应用拆分成多个)，就不会检测到任何变化(也不会有任何有用的错误消息)。所以在我的模型类中，我现在有:

class ModelClassName(models.Model):

    class Meta:
        app_label = '<app name>' # <-- this label was wrong before.

    field_name = models.FloatField()
    ...

运行Django 1.10。