使用os.walk()在Python中递归遍历目录

我想从根目录导航到所有其他目录，并打印相同的内容。

这是我的代码:

#!/usr/bin/python

import os
import fnmatch

for root, dir, files in os.walk("."):
        print root
        print ""
        for items in fnmatch.filter(files, "*"):
                print "..." + items
        print ""

这是我的O/P:

.

...Python_Notes
...pypy.py
...pypy.py.save
...classdemo.py
....goutputstream-J9ZUXW
...latest.py
...pack.py
...classdemo.pyc
...Python_Notes~
...module-demo.py
...filetype.py

./packagedemo

...classdemo.py
...__init__.pyc
...__init__.py
...classdemo.pyc

以上,。和。/packagedemo是目录。

不过，我需要以下列方式列印订单:

A
---a.txt
---b.txt
---B
------c.out

上面，A和B是目录，其余是文件。

当前回答

#!/usr/bin/python

import os 

def tracing(a):
    global i>
    for item in os.listdir(a):
        if os.path.isfile(item):
            print i + item 
        else:
            print i + item 
            i+=i
            tracing(item)

i = "---"
tracing(".")

2014-09-25 04:41:25

其他回答

这是最好的办法吗

import os

def traverse_dir_recur(directory):
    l = os.listdir(directory)
    for d in l:
        if os.path.isdir(directory + d):
            traverse_dir_recur(directory +  d +"/")
        else:
            print(directory + d)

2019-06-07 09:30:24

这是对文件夹名称的处理:

def printFolderName(init_indent, rootFolder):
    fname = rootFolder.split(os.sep)[-1]
    root_levels = rootFolder.count(os.sep)
    # os.walk treats dirs breadth-first, but files depth-first (go figure)
    for root, dirs, files in os.walk(rootFolder):
        # print the directories below the root
        levels = root.count(os.sep) - root_levels
        indent = ' '*(levels*2)
        print init_indent + indent + root.split(os.sep)[-1]

2014-06-24 18:17:23

#!/usr/bin/python

import os 

def tracing(a):
    global i>
    for item in os.listdir(a):
        if os.path.isfile(item):
            print i + item 
        else:
            print i + item 
            i+=i
            tracing(item)

i = "---"
tracing(".")

2014-09-25 04:41:25

/home/parent_dir
├── 0_N
├── 1_M
├── 2_P
├── 3_R
└── 4_T

下面是你可以估计每个子目录中#文件相对于父目录中#文件总数的大致百分比:

from os import listdir as osl
from os import walk as osw
from os.path import join as osj

def subdir_summary(parent_dir):
    parent_dir_len = sum([len(files) for _, _, files in osw(parent_dir)])
    print(f"Total files in parent: {parent_dir_len}")
    for subdir in sorted(osl(parent_dir)):
        subdir_files_len = len(osl(osj(parent_dir, subdir)))
        print(subdir, subdir_files_len, f"{int(100*(subdir_files_len / parent_dir_len))}%")

subdir_summary("/home/parent_dir")

它将在终端中打印如下:

Total files in parent: 5876
0_N 3254 55%
1_M 509 8%
2_P 1187 20%
3_R 594 10%
4_T 332 5%

2022-08-09 06:27:31

试试这个吧;简单的

 #!/usr/bin/python
 import os
 # Creating an empty list that will contain the already traversed paths
 donePaths = []
 def direct(path):
       for paths,dirs,files in os.walk(path):
             if paths not in donePaths:
                    count = paths.count('/')
                    if files:
                          for ele1 in files:
                                print '---------' * (count), ele1
                    if dirs:
                          for ele2 in dirs:
                                print '---------' * (count), ele2
                                absPath = os.path.join(paths,ele2)
              # recursively calling the direct function on each directory
                                direct(absPath)
                   # adding the paths to the list that got traversed 
                                donePaths.append(absPath)

 path = raw_input("Enter any path to get the following Dir Tree ...\n")
 direct(path)

输出= = = = = = = = = = = = = = = =

 /home/test
 ------------------ b.txt
 ------------------ a.txt
 ------------------ a
 --------------------------- a1.txt
 ------------------ b
 --------------------------- b1.txt
 --------------------------- b2.txt
 --------------------------- cde
 ------------------------------------ cde.txt
 ------------------------------------ cdeDir
 --------------------------------------------- cdeDir.txt
 ------------------ c
 --------------------------- c.txt
 --------------------------- c1
 ------------------------------------ c1.txt
 ------------------------------------ c2.txt

2015-10-16 17:19:22

使用os.walk()在Python中递归遍历目录

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