如何POST JSON数据与PHP卷曲?

这是我的代码，

$url = 'url_to_post';
$data = array(
    "first_name" => "First name",
    "last_name" => "last name",
    "email"=>"email@gmail.com",
    "addresses" => array (
        "address1" => "some address",
        "city" => "city",
        "country" => "CA",
        "first_name" =>  "Mother",
        "last_name" =>  "Lastnameson",
        "phone" => "555-1212",
        "province" => "ON",
        "zip" => "123 ABC"
    )
);
$data_string = json_encode($data);
$ch=curl_init($url);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string));
curl_setopt($ch, CURLOPT_HEADER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER,
    array(
        'Content-Type:application/json',
        'Content-Length: ' . strlen($data_string)
    )
);

$result = curl_exec($ch);
curl_close($ch);

在另一页，我正在检索post数据。

    print_r ($_POST);

输出是

HTTP/1.1 200 OK
Date: Mon, 18 Jun 2012 07:58:11 GMT
Server: Apache
X-Powered-By: PHP/5.3.6
Vary: Accept-Encoding
Connection: close
Content-Type: text/html

Array ( )

因此，即使在我自己的服务器上，我也得不到正确的数据，它是空数组。我想在http://docs.shopify.com/api/customer#create使用json实现REST

当前回答

你不正确地发布了json——但即使它是正确的，你也不能使用print_r($_POST)进行测试(阅读这里的原因)。相反，在第二个页面上，您可以使用file_get_contents("php://input")获取传入请求，其中将包含post json。要以更可读的格式查看接收到的数据，请尝试以下方法:

echo '<pre>'.print_r(json_decode(file_get_contents("php://input")),1).'</pre>';

在您的代码中，您指示Content-Type:application/json，但您没有对所有POST数据进行json编码——只对“customer”POST字段的值进行json编码。相反，你可以这样做:

$ch = curl_init( $url );
# Setup request to send json via POST.
$payload = json_encode( array( "customer"=> $data ) );
curl_setopt( $ch, CURLOPT_POSTFIELDS, $payload );
curl_setopt( $ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json'));
# Return response instead of printing.
curl_setopt( $ch, CURLOPT_RETURNTRANSFER, true );
# Send request.
$result = curl_exec($ch);
curl_close($ch);
# Print response.
echo "<pre>$result</pre>";

旁注:您可能会受益于使用第三方库，而不是直接自己与Shopify API接口。

2013-03-26 17:26:44

其他回答

取代

curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string));

$data_string = json_encode(array("customer"=>$data));
//Send blindly the json-encoded string.
//The server, IMO, expects the body of the HTTP request to be in JSON
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);

我不明白你说的“其他页面”是什么意思，我希望它是在:'url_to_post'的页面。如果该页面是用PHP编写的，那么你刚刚发布的JSON将以以下方式读取:

$jsonStr = file_get_contents("php://input"); //read the HTTP body.
$json = json_decode($jsonStr);

2012-06-18 08:34:09

echo '<pre>'.print_r(json_decode(file_get_contents("php://input")),1).'</pre>';

在您的代码中，您指示Content-Type:application/json，但您没有对所有POST数据进行json编码——只对“customer”POST字段的值进行json编码。相反，你可以这样做:

$ch = curl_init( $url );
# Setup request to send json via POST.
$payload = json_encode( array( "customer"=> $data ) );
curl_setopt( $ch, CURLOPT_POSTFIELDS, $payload );
curl_setopt( $ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json'));
# Return response instead of printing.
curl_setopt( $ch, CURLOPT_RETURNTRANSFER, true );
# Send request.
$result = curl_exec($ch);
curl_close($ch);
# Print response.
echo "<pre>$result</pre>";

旁注:您可能会受益于使用第三方库，而不是直接自己与Shopify API接口。

2013-03-26 17:26:44

请试试这个代码:-

$url = 'url_to_post';

$data = array("first_name" => "First name","last_name" => "last name","email"=>"email@gmail.com","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" =>  "Mother","last_name" =>  "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );

$data_string = json_encode(array("customer" =>$data));

$ch = curl_init($url);

curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);

curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json'));

curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

$result = curl_exec($ch);

curl_close($ch);

echo "$result";

2018-03-06 13:09:50

试着这样做:

$url = 'url_to_post';
// this is only part of the data you need to sen
$customer_data = array("first_name" => "First name","last_name" => "last name","email"=>"email@gmail.com","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" =>  "Mother","last_name" =>  "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );
// As per your API, the customer data should be structured this way
$data = array("customer" => $customer_data);
// And then encoded as a json string
$data_string = json_encode($data);
$ch=curl_init($url);

curl_setopt_array($ch, array(
    CURLOPT_POST => true,
    CURLOPT_POSTFIELDS => $data_string,
    CURLOPT_HEADER => true,
    CURLOPT_HTTPHEADER => array('Content-Type:application/json', 'Content-Length: ' . strlen($data_string)))
));

$result = curl_exec($ch);
curl_close($ch);

您忘记的关键是json_encode您的数据。但是您也可能会发现，通过传递一个数组，使用curl_setopt_array一次性设置所有curl选项是很方便的。

2012-06-18 08:38:37

试试这个例子。

<?php 
 $url = 'http://localhost/test/page2.php';
    $data = array("first_name" => "First name","last_name" => "last name","email"=>"email@gmail.com","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" =>  "Mother","last_name" =>  "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );
    $ch=curl_init($url);
    $data_string = urlencode(json_encode($data));
    curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
    curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string));


    $result = curl_exec($ch);
    curl_close($ch);

    echo $result;
?>

你的page2.php代码

<?php
$datastring = $_POST['customer'];
$data = json_decode( urldecode( $datastring));

?>

2012-06-18 09:05:03

如何POST JSON数据与PHP卷曲?

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