是的，GPS设置不能再通过编程改变了，因为它们是隐私设置，我们必须检查它们是否从程序中打开，如果它们没有打开，我们就处理它。 你可以通知用户GPS被关闭，如果你愿意，可以使用类似这样的东西向用户显示设置屏幕。

检查位置提供程序是否可用

    String provider = Settings.Secure.getString(getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
    if(provider != null){
        Log.v(TAG, " Location providers: "+provider);
        //Start searching for location and update the location text when update available
        startFetchingLocation();
    }else{
        // Notify users and show settings if they want to enable GPS
    }

如果用户想启用GPS，你可以这样显示设置屏幕。

Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
startActivityForResult(intent, REQUEST_CODE);

在onActivityResult中，你可以看到用户是否启用了它

    protected void onActivityResult(int requestCode, int resultCode, Intent data){
        if(requestCode == REQUEST_CODE && resultCode == 0){
            String provider = Settings.Secure.getString(getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
            if(provider != null){
                Log.v(TAG, " Location providers: "+provider);
                //Start searching for location and update the location text when update available. 
// Do whatever you want
                startFetchingLocation();
            }else{
                //Users did not switch on the GPS
            }
        }
    }

这是一种方法，我希望它能有所帮助。 如果我做错了什么，请告诉我。

在android中，我们可以很容易地检查GPS是否在设备中启用或使用LocationManager。

这里有一个简单的程序来检查。

是否启用GPS:- 将AndroidManifest.xml中的以下用户权限行添加到访问位置

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />

您的java类文件应该是

public class ExampleApp extends Activity {
    /** Called when the activity is first created. */
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        LocationManager locationManager = (LocationManager) getSystemService(LOCATION_SERVICE);

        if (locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER)){
            Toast.makeText(this, "GPS is Enabled in your devide", Toast.LENGTH_SHORT).show();
        }else{
            showGPSDisabledAlertToUser();
        }
    }

    private void showGPSDisabledAlertToUser(){
        AlertDialog.Builder alertDialogBuilder = new AlertDialog.Builder(this);
        alertDialogBuilder.setMessage("GPS is disabled in your device. Would you like to enable it?")
        .setCancelable(false)
        .setPositiveButton("Goto Settings Page To Enable GPS",
                new DialogInterface.OnClickListener(){
            public void onClick(DialogInterface dialog, int id){
                Intent callGPSSettingIntent = new Intent(
                        android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS);
                startActivity(callGPSSettingIntent);
            }
        });
        alertDialogBuilder.setNegativeButton("Cancel",
                new DialogInterface.OnClickListener(){
            public void onClick(DialogInterface dialog, int id){
                dialog.cancel();
            }
        });
        AlertDialog alert = alertDialogBuilder.create();
        alert.show();
    }
}

输出将如下所示

在LocationListener中，实现onProviderEnabled和onProviderDisabled事件处理程序。当你调用requestLocationUpdates(…)时，如果手机上的GPS是禁用的，onProviderDisabled将被调用;如果用户启用GPS, onProviderEnabled将被调用。

以下是步骤:

步骤1:创建在后台运行的服务。

步骤2:在Manifest文件中也需要以下权限:

android.permission.ACCESS_FINE_LOCATION

步骤3:编写代码:

 final LocationManager manager = (LocationManager)context.getSystemService    (Context.LOCATION_SERVICE );

if ( !manager.isProviderEnabled( LocationManager.GPS_PROVIDER ) )
  Toast.makeText(context, "GPS is disabled!", Toast.LENGTH_LONG).show(); 
else
  Toast.makeText(context, "GPS is enabled!", Toast.LENGTH_LONG).show();

第四步:或者你可以简单地使用:

LocationManager manager = (LocationManager) getSystemService(Context.LOCATION_SERVICE );
boolean statusOfGPS = manager.isProviderEnabled(LocationManager.GPS_PROVIDER);

步骤5:持续运行服务以监控连接。

是的，GPS设置不能再通过编程改变了，因为它们是隐私设置，我们必须检查它们是否从程序中打开，如果它们没有打开，我们就处理它。 你可以通知用户GPS被关闭，如果你愿意，可以使用类似这样的东西向用户显示设置屏幕。

检查位置提供程序是否可用

    String provider = Settings.Secure.getString(getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
    if(provider != null){
        Log.v(TAG, " Location providers: "+provider);
        //Start searching for location and update the location text when update available
        startFetchingLocation();
    }else{
        // Notify users and show settings if they want to enable GPS
    }

如果用户想启用GPS，你可以这样显示设置屏幕。

Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
startActivityForResult(intent, REQUEST_CODE);

在onActivityResult中，你可以看到用户是否启用了它

    protected void onActivityResult(int requestCode, int resultCode, Intent data){
        if(requestCode == REQUEST_CODE && resultCode == 0){
            String provider = Settings.Secure.getString(getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
            if(provider != null){
                Log.v(TAG, " Location providers: "+provider);
                //Start searching for location and update the location text when update available. 
// Do whatever you want
                startFetchingLocation();
            }else{
                //Users did not switch on the GPS
            }
        }
    }

这是一种方法，我希望它能有所帮助。 如果我做错了什么，请告诉我。

在Kotlin:如何检查GPS是否启用

 val manager = getSystemService(Context.LOCATION_SERVICE) as LocationManager
        if (!manager.isProviderEnabled(LocationManager.GPS_PROVIDER)) {
            checkGPSEnable()
        } 

 private fun checkGPSEnable() {
        val dialogBuilder = AlertDialog.Builder(this)
        dialogBuilder.setMessage("Your GPS seems to be disabled, do you want to enable it?")
                .setCancelable(false)
                .setPositiveButton("Yes", DialogInterface.OnClickListener { dialog, id
                    ->
                    startActivity(Intent(android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS))
                })
                .setNegativeButton("No", DialogInterface.OnClickListener { dialog, id ->
                    dialog.cancel()
                })
        val alert = dialogBuilder.create()
        alert.show()
    }