我在玩苹果的新Swift编程语言，遇到了一些问题…
目前我试图读取一个plist文件，在Objective-C中，我会做以下工作来获取内容作为NSDictionary:
NSString *filePath = [[NSBundle mainBundle] pathForResource:@"Config" ofType:@"plist"];
NSDictionary *dict = [[NSDictionary alloc] initWithContentsOfFile:filePath];
我如何得到一个plist作为一个字典在Swift?
我假设我可以得到路径到plist:
let path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist")
当这工作(如果它是正确的?):我如何获得内容作为一个字典?
还有一个更普遍的问题:
是否可以使用默认的NS*类?我想是的……还是我遗漏了什么?据我所知，默认框架NS*类仍然有效，可以使用吗?
当前回答
我使用swift字典，但在我的文件管理器类中转换它们和nsdictionary，如下所示:
func writePlist(fileName:String, myDict:Dictionary<String, AnyObject>){
let docsDir:String = dirPaths[0] as String
let docPath = docsDir + "/" + fileName
let thisDict = myDict as NSDictionary
if(thisDict.writeToFile(docPath, atomically: true)){
NSLog("success")
} else {
NSLog("failure")
}
}
func getPlist(fileName:String)->Dictionary<String, AnyObject>{
let docsDir:String = dirPaths[0] as String
let docPath = docsDir + "/" + fileName
let thisDict = NSDictionary(contentsOfFile: docPath)
return thisDict! as! Dictionary<String, AnyObject>
}
这似乎是最不麻烦的读写方式，但让我的其余代码保持尽可能快。
其他回答
斯威夫特3.0
if let path = Bundle.main.path(forResource: "config", ofType: "plist") {
let dict = NSDictionary(contentsOfFile: path)
// use dictionary
}
在我看来，这是最简单的方法。
Swift 2.0:访问信息。Plist
我有一个名为CoachMarksDictionary的字典，在信息中具有布尔值。Plist。我想访问bool值并使其为真。
let path = NSBundle.mainBundle().pathForResource("Info", ofType: "plist")!
let dict = NSDictionary(contentsOfFile: path) as! [String: AnyObject]
if let CoachMarksDict = dict["CoachMarksDictionary"] {
print("Info.plist : \(CoachMarksDict)")
var dashC = CoachMarksDict["DashBoardCompleted"] as! Bool
print("DashBoardCompleted state :\(dashC) ")
}
写给Plist:
自定义Plist:- Make from File-New-File-Resource-PropertyList。增加了三个字符串:DashBoard_New, DashBoard_Draft, DashBoard_Completed)
func writeToCoachMarksPlist(status:String?,keyName:String?)
{
let path1 = NSBundle.mainBundle().pathForResource("CoachMarks", ofType: "plist")
let coachMarksDICT = NSMutableDictionary(contentsOfFile: path1!)! as NSMutableDictionary
var coachMarksMine = coachMarksDICT.objectForKey(keyName!)
coachMarksMine = status
coachMarksDICT.setValue(status, forKey: keyName!)
coachMarksDICT.writeToFile(path1!, atomically: true)
}
该方法可以调用为
self.writeToCoachMarksPlist(" true - means user has checked the marks",keyName: "the key in the CoachMarks dictionary").
访问plist文件的简单结构(Swift 2.0)
struct Configuration {
static let path = NSBundle.mainBundle().pathForResource("Info", ofType: "plist")!
static let dict = NSDictionary(contentsOfFile: path) as! [String: AnyObject]
static let someValue = dict["someKey"] as! String
}
用法:
print("someValue = \(Configuration.someValue)")
通过尼克的回答转换成一个方便的扩展:
extension Dictionary {
static func contentsOf(path: URL) -> Dictionary<String, AnyObject> {
let data = try! Data(contentsOf: path)
let plist = try! PropertyListSerialization.propertyList(from: data, options: .mutableContainers, format: nil)
return plist as! [String: AnyObject]
}
}
用法:
let path = Bundle.main.path(forResource: "plistName", ofType: "plist")!
let url = URL(fileURLWithPath: path)
let dict = Dictionary<String, AnyObject>.contentsOf(path: url)
我敢打赌，它也可以为数组创建类似的扩展
在我的情况下，我创建了一个NSDictionary称为appSettings并添加所有需要的键。对于这种情况，解决方案是:
if let dict = NSBundle.mainBundle().objectForInfoDictionaryKey("appSettings") {
if let configAppToken = dict["myKeyInsideAppSettings"] as? String {
}
}
