我有两个表格日期:
Start Date: 2007-03-24
End Date: 2009-06-26
现在我需要通过以下形式找到这两者之间的区别:
2 years, 3 months and 2 days
如何在PHP中执行此操作?
我有两个表格日期:
Start Date: 2007-03-24
End Date: 2009-06-26
现在我需要通过以下形式找到这两者之间的区别:
2 years, 3 months and 2 days
如何在PHP中执行此操作?
当前回答
查看小时、分钟和秒。。
$date1 = "2008-11-01 22:45:00";
$date2 = "2009-12-04 13:44:01";
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
$hours = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60));
$minuts = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60)/ 60);
$seconds = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60 - $minuts*60));
printf("%d years, %d months, %d days, %d hours, %d minuts\n, %d seconds\n", $years, $months, $days, $hours, $minuts, $seconds);
其他回答
简单的功能
function time_difference($time_1, $time_2, $limit = null)
{
$val_1 = new DateTime($time_1);
$val_2 = new DateTime($time_2);
$interval = $val_1->diff($val_2);
$output = array(
"year" => $interval->y,
"month" => $interval->m,
"day" => $interval->d,
"hour" => $interval->h,
"minute" => $interval->i,
"second" => $interval->s
);
$return = "";
foreach ($output AS $key => $value) {
if ($value == 1)
$return .= $value . " " . $key . " ";
elseif ($value >= 1)
$return .= $value . " " . $key . "s ";
if ($key == $limit)
return trim($return);
}
return trim($return);
}
像这样使用
回波时间差($time_1,$time_2,“天”);
将返回2年8个月2天
使用date_diff()尝试这个非常简单的答案,这是经过测试的。
$date1 = date_create("2017-11-27");
$date2 = date_create("2018-12-29");
$diff=date_diff($date1,$date2);
$months = $diff->format("%m months");
$years = $diff->format("%y years");
$days = $diff->format("%d days");
echo $years .' '.$months.' '.$days;
输出为:
1 years 1 months 2 days
<?php
$today = strtotime("2011-02-03 00:00:00");
$myBirthDate = strtotime("1964-10-30 00:00:00");
printf("Days since my birthday: ", ($today - $myBirthDate)/60/60/24);
?>
这将尝试检测是否给定了时间戳,并将返回未来的日期/时间作为负值:
<?php
function time_diff($start, $end = NULL, $convert_to_timestamp = FALSE) {
// If $convert_to_timestamp is not explicitly set to TRUE,
// check to see if it was accidental:
if ($convert_to_timestamp || !is_numeric($start)) {
// If $convert_to_timestamp is TRUE, convert to timestamp:
$timestamp_start = strtotime($start);
}
else {
// Otherwise, leave it as a timestamp:
$timestamp_start = $start;
}
// Same as above, but make sure $end has actually been overridden with a non-null,
// non-empty, non-numeric value:
if (!is_null($end) && (!empty($end) && !is_numeric($end))) {
$timestamp_end = strtotime($end);
}
else {
// If $end is NULL or empty and non-numeric value, assume the end time desired
// is the current time (useful for age, etc):
$timestamp_end = time();
}
// Regardless, set the start and end times to an integer:
$start_time = (int) $timestamp_start;
$end_time = (int) $timestamp_end;
// Assign these values as the params for $then and $now:
$start_time_var = 'start_time';
$end_time_var = 'end_time';
// Use this to determine if the output is positive (time passed) or negative (future):
$pos_neg = 1;
// If the end time is at a later time than the start time, do the opposite:
if ($end_time <= $start_time) {
$start_time_var = 'end_time';
$end_time_var = 'start_time';
$pos_neg = -1;
}
// Convert everything to the proper format, and do some math:
$then = new DateTime(date('Y-m-d H:i:s', $$start_time_var));
$now = new DateTime(date('Y-m-d H:i:s', $$end_time_var));
$years_then = $then->format('Y');
$years_now = $now->format('Y');
$years = $years_now - $years_then;
$months_then = $then->format('m');
$months_now = $now->format('m');
$months = $months_now - $months_then;
$days_then = $then->format('d');
$days_now = $now->format('d');
$days = $days_now - $days_then;
$hours_then = $then->format('H');
$hours_now = $now->format('H');
$hours = $hours_now - $hours_then;
$minutes_then = $then->format('i');
$minutes_now = $now->format('i');
$minutes = $minutes_now - $minutes_then;
$seconds_then = $then->format('s');
$seconds_now = $now->format('s');
$seconds = $seconds_now - $seconds_then;
if ($seconds < 0) {
$minutes -= 1;
$seconds += 60;
}
if ($minutes < 0) {
$hours -= 1;
$minutes += 60;
}
if ($hours < 0) {
$days -= 1;
$hours += 24;
}
$months_last = $months_now - 1;
if ($months_now == 1) {
$years_now -= 1;
$months_last = 12;
}
// "Thirty days hath September, April, June, and November" ;)
if ($months_last == 9 || $months_last == 4 || $months_last == 6 || $months_last == 11) {
$days_last_month = 30;
}
else if ($months_last == 2) {
// Factor in leap years:
if (($years_now % 4) == 0) {
$days_last_month = 29;
}
else {
$days_last_month = 28;
}
}
else {
$days_last_month = 31;
}
if ($days < 0) {
$months -= 1;
$days += $days_last_month;
}
if ($months < 0) {
$years -= 1;
$months += 12;
}
// Finally, multiply each value by either 1 (in which case it will stay the same),
// or by -1 (in which case it will become negative, for future dates).
// Note: 0 * 1 == 0 * -1 == 0
$out = new stdClass;
$out->years = (int) $years * $pos_neg;
$out->months = (int) $months * $pos_neg;
$out->days = (int) $days * $pos_neg;
$out->hours = (int) $hours * $pos_neg;
$out->minutes = (int) $minutes * $pos_neg;
$out->seconds = (int) $seconds * $pos_neg;
return $out;
}
示例用法:
<?php
$birthday = 'June 2, 1971';
$check_age_for_this_date = 'June 3, 1999 8:53pm';
$age = time_diff($birthday, $check_age_for_this_date)->years;
print $age;// 28
Or:
<?php
$christmas_2020 = 'December 25, 2020';
$countdown = time_diff($christmas_2020);
print_r($countdown);
最好的做法是使用PHP的DateTime(和DateInterval)对象。每个日期都封装在DateTime对象中,然后可以在两者之间进行区别:
$first_date = new DateTime("2012-11-30 17:03:30");
$second_date = new DateTime("2012-12-21 00:00:00");
DateTime对象将接受strtotime()的任何格式。如果需要更具体的日期格式,则可以使用DateTime::createFromFormat()创建DateTime对象。
两个对象实例化后,使用DateTime::diff()从另一个对象中减去一个对象。
$difference = $first_date->diff($second_date);
$difference现在保存一个包含差异信息的DateInterval对象。var_dump()如下所示:
object(DateInterval)
public 'y' => int 0
public 'm' => int 0
public 'd' => int 20
public 'h' => int 6
public 'i' => int 56
public 's' => int 30
public 'invert' => int 0
public 'days' => int 20
要格式化DateInterval对象,我们需要检查每个值,如果值为0,则将其排除:
/**
* Format an interval to show all existing components.
* If the interval doesn't have a time component (years, months, etc)
* That component won't be displayed.
*
* @param DateInterval $interval The interval
*
* @return string Formatted interval string.
*/
function format_interval(DateInterval $interval) {
$result = "";
if ($interval->y) { $result .= $interval->format("%y years "); }
if ($interval->m) { $result .= $interval->format("%m months "); }
if ($interval->d) { $result .= $interval->format("%d days "); }
if ($interval->h) { $result .= $interval->format("%h hours "); }
if ($interval->i) { $result .= $interval->format("%i minutes "); }
if ($interval->s) { $result .= $interval->format("%s seconds "); }
return $result;
}
现在剩下的就是调用$differenceDateInterval对象上的函数:
echo format_interval($difference);
我们得到了正确的结果:
20天6小时56分30秒
用于实现目标的完整代码:
/**
* Format an interval to show all existing components.
* If the interval doesn't have a time component (years, months, etc)
* That component won't be displayed.
*
* @param DateInterval $interval The interval
*
* @return string Formatted interval string.
*/
function format_interval(DateInterval $interval) {
$result = "";
if ($interval->y) { $result .= $interval->format("%y years "); }
if ($interval->m) { $result .= $interval->format("%m months "); }
if ($interval->d) { $result .= $interval->format("%d days "); }
if ($interval->h) { $result .= $interval->format("%h hours "); }
if ($interval->i) { $result .= $interval->format("%i minutes "); }
if ($interval->s) { $result .= $interval->format("%s seconds "); }
return $result;
}
$first_date = new DateTime("2012-11-30 17:03:30");
$second_date = new DateTime("2012-12-21 00:00:00");
$difference = $first_date->diff($second_date);
echo format_interval($difference);