如何让git diff只显示两次提交之间的差异,而不包括中间的其他提交?


当前回答

检查完整的更改:

  git diff <commit_Id_1> <commit_Id_2>

仅检查更改/添加/删除的文件:

  git diff <commit_Id_1> <commit_Id_2> --name-only

注意:对于检查中间没有提交的diff,你不需要输入提交id。

其他回答

直接在GitHub上查看差异;您可以- https://github.com/<username>/<reponame>/compare/<commit1>..<commit2> .

commit1和commit2可以是分支名或commit哈希值

为例:

比较gs/add-explicit-paths-to-js-files分支和gs/add-history-helper - https://github.com/twbs/bootstrap/compare/gs/add-explicit-paths-to-js-files..gs/add-history-helper 比较commit 75e09b1c0f5ae5f51078c7a25fe36d892c5cfcfe和585146a6a7aa70faf25442d7d28636ce57e29588 - https://github.com/twbs/bootstrap/compare/75e09b1c0f5ae5f51078c7a25fe36d892c5cfcfe..585146a6a7aa70faf25442d7d28636ce57e29588

在比较提交中阅读更多信息

美元git日志

commit-1(new/latest/recent commit)
commit-2
commit-3
commit-4
*
*
commit-n(first commit)

$git diff commit-2

显示commit-2到commit-1之间的所有变化(仅仅是commit-1的补丁,相当于git diff HEAD~1 HEAD)

类似的 $git diff commit-4 commit-1

显示commit-4到commit-1之间的所有更改(commit-1的补丁, 一起提交2号和3号。相当于git差头~3头)

$git diff commit-1 commit-2

通过改变订单提交ID,可以获得恢复补丁。 ("$git diff commit-1 commit-2 > revert_patch_of_commit-1.diff")

我的别名设置在~/。ZSHRC文件git diff:

alias gdf='git diff HEAD{'^',}' # diff between your recent tow commits

谢谢 @Jinmiao罗


git差别头~2头

在最近的第二次提交和当前之间完成更改。

HEAD方便

我的别名设置在~/。git的Bashrc文件:

alias gdca='git diff --cached' # diff between your staged file and the last commit
alias gdcc='git diff HEAD{,^}' # diff between your latest two commits

你可以简单地将2个提交传递给git diff,就像这样:

-> git diff 0da94be  59ff30c > my.patch
-> git apply my.patch