如果您使用的是相对较新的Python版本，也可以使用上下文管理器，例如：

from __future__ import with_statement
from grizzled.os import working_directory

with working_directory(path_to_directory):
    # code in here occurs within the directory

# code here is in the original directory

更新

如果你喜欢自己动手：

import os
from contextlib import contextmanager

@contextmanager
def working_directory(directory):
    owd = os.getcwd()
    try:
        os.chdir(directory)
        yield directory
    finally:
        os.chdir(owd)

os.chdir（）是cd的Python版本。

如果您使用spyder和love GUI，只需单击屏幕右上角的文件夹按钮，即可浏览您希望作为当前目录的文件夹/目录。完成此操作后，您可以转到spyder IDE中窗口的文件资源管理器选项卡，您可以看到那里存在的所有文件/文件夹。检查当前工作目录转到spyder IDE的控制台，只需键入

pwd

它将打印与您之前选择的路径相同的路径。

os.chdir（）是正确的方法。

import os

abs_path = 'C://a/b/c'
rel_path = './folder'

os.chdir(abs_path)
os.chdir(rel_path)

您可以将两者与os.chdir（abs_path）或os.chdir（rel_path）一起使用，不需要调用os.getcwd（）来使用相对路径。

更改脚本进程的当前目录很简单。我认为问题实际上是如何更改调用python脚本的命令窗口的当前目录，这非常困难。Windows中的Bat脚本或Bash shell中的Bash脚本可以使用普通的cd命令执行此操作，因为shell本身就是解释器。在Windows和Linux中，Python都是一个程序，任何程序都不能直接更改其父环境。然而，将一个简单的shell脚本与一个Python脚本相结合来完成大部分困难的工作，可以获得所需的结果。例如，为了制作一个带有向后/向前/选择重新访问遍历历史的扩展cd命令，我编写了一个由简单的bat脚本调用的相对复杂的Python脚本。遍历列表存储在文件中，目标目录位于第一行。当python脚本返回时，bat脚本读取文件的第一行，并将其作为cd的参数

if _%1 == _. goto cdDone
if _%1 == _? goto help
if /i _%1 NEQ _-H goto doCd
:help
echo d.bat and dSup.py 2016.03.05. Extended chdir.
echo -C = clear traversal list.
echo -B or nothing = backward (to previous dir).
echo -F or - = forward (to next dir).
echo -R = remove current from list and return to previous.
echo -S = select from list.
echo -H, -h, ? = help.
echo . = make window title current directory.
echo Anything else = target directory.
goto done

:doCd
%~dp0dSup.py %1
for /F %%d in ( %~dp0dSupList ) do (
    cd %%d
    if errorlevel 1 ( %~dp0dSup.py -R )
    goto cdDone
)
:cdDone
title %CD%
:done

python脚本dSup.py是：

import sys, os, msvcrt

def indexNoCase ( slist, s ) :
    for idx in range( len( slist )) :
        if slist[idx].upper() == s.upper() :
            return idx
    raise ValueError

# .........main process ...................
if len( sys.argv ) < 2 :
    cmd = 1 # No argument defaults to -B, the most common operation
elif sys.argv[1][0] == '-':
    if len(sys.argv[1]) == 1 :
        cmd = 2 # '-' alone defaults to -F, second most common operation.
    else :
        cmd = 'CBFRS'.find( sys.argv[1][1:2].upper())
else :
    cmd = -1
    dir = os.path.abspath( sys.argv[1] ) + '\n'

# cmd is -1 = path, 0 = C, 1 = B, 2 = F, 3 = R, 4 = S

fo = open( os.path.dirname( sys.argv[0] ) + '\\dSupList', mode = 'a+t' )
fo.seek( 0 )
dlist = fo.readlines( -1 )
if len( dlist ) == 0 :
    dlist.append( os.getcwd() + '\n' ) # Prime new directory list with current.

if cmd == 1 : # B: move backward, i.e. to previous
    target = dlist.pop(0)
    dlist.append( target )
elif cmd == 2 : # F: move forward, i.e. to next
    target = dlist.pop( len( dlist ) - 1 )
    dlist.insert( 0, target )
elif cmd == 3 : # R: remove current from list. This forces cd to previous, a
                # desireable side-effect
    dlist.pop( 0 )
elif cmd == 4 : # S: select from list
# The current directory (dlist[0]) is included essentially as ESC.
    for idx in range( len( dlist )) :
        print( '(' + str( idx ) + ')', dlist[ idx ][:-1])
    while True :
        inp = msvcrt.getche()
        if inp.isdigit() :
            inp = int( inp )
            if inp < len( dlist ) :
                print( '' ) # Print the newline we didn't get from getche.
                break
        print( ' is out of range' )
# Select 0 means the current directory and the list is not changed. Otherwise
# the selected directory is moved to the top of the list. This can be done by
# either rotating the whole list until the selection is at the head or pop it
# and insert it to 0. It isn't obvious which would be better for the user but
# since pop-insert is simpler, it is used.
    if inp > 0 :
        dlist.insert( 0, dlist.pop( inp ))

elif cmd == -1 : # -1: dir is the requested new directory.
# If it is already in the list then remove it before inserting it at the head.
# This takes care of both the common case of it having been recently visited
# and the less common case of user mistakenly requesting current, in which
# case it is already at the head. Deleting and putting it back is a trivial
# inefficiency.
    try:
        dlist.pop( indexNoCase( dlist, dir ))
    except ValueError :
        pass
    dlist = dlist[:9] # Control list length by removing older dirs (should be
                      # no more than one).
    dlist.insert( 0, dir ) 

fo.truncate( 0 )
if cmd != 0 : # C: clear the list
    fo.writelines( dlist )

fo.close()
exit(0)