如何确定脚本本身中的Bash脚本文件的名称?
就像如果我的脚本在文件runme.sh中,那么我如何让它显示“您正在运行runme.sh”消息而不硬编码?
如何确定脚本本身中的Bash脚本文件的名称?
就像如果我的脚本在文件runme.sh中,那么我如何让它显示“您正在运行runme.sh”消息而不硬编码?
当前回答
使用bash >= 3,以下工作:
$ ./s
0 is: ./s
BASH_SOURCE is: ./s
$ . ./s
0 is: bash
BASH_SOURCE is: ./s
$ cat s
#!/bin/bash
printf '$0 is: %s\n$BASH_SOURCE is: %s\n' "$0" "$BASH_SOURCE"
其他回答
在所有情况下获取脚本或源脚本的“真实路径”:
fullname=$(readlink $0) # Take care of symbolic links
dirname=${fullname%/*} # Get (most of the time) the dirname
realpath=$(dirname $BASH_SOURCE) # TO handle sourced scripts
[ "$realpath" = '.' ] && realpath=${dirname:-.}
下面是要生成的bash脚本(在新创建的“workdir”子目录中,在当前目录的“mytest”中),该bash脚本将派生另一个脚本,该脚本将调用bash定义的函数....测试了许多方法来启动它们:
#!/bin/bash
##############################################################
ret=0
fullname=$(readlink $0) # Take care of symbolic links
dirname=${fullname%/*} # Get (most of the time) the dirname
realpath=$(dirname $BASH_SOURCE) # TO handle sourced scripts
[ "$realpath" = '.' ] && realpath=${dirname:-.}
fullname_withoutextension=${fullname%.*}
mkdir -p workdir
cat <<'EOD' > workdir/_script_.sh
#!/bin/bash
##############################################################
ret=0
fullname=$(readlink $0) # Take care of symbolic links
dirname=${fullname%/*} # Get (most of the time) the dirname
realpath=$(dirname $BASH_SOURCE) # TO handle sourced scripts
[ "$realpath" = '.' ] && realpath=${dirname:-.}
fullname_withoutextension=${fullname%.*}
echo
echo "# ------------- RESULTS ------------- #"
echo "# path to me (\$0)-----------> ${0} "
echo "# arguments called with ----> ${@} "
echo "# \$1 -----------------------> $1 "
echo "# \$2 -----------------------> $2 "
echo "# path to me (\$fullname)----> ${fullname} "
echo "# parent path(\${0%/*})------> ${0%/*} "
echo "# parent path(\$dirname)-----> ${dirname} "
echo "# my name ----\${0##*/}------> ${0##*/} "
echo "# my source -\${BASH_SOURCE}-> ${BASH_SOURCE} "
echo "# parent path(from BASH_SOURCE) -> $(dirname $BASH_SOURCE)"
echo "# my function name -\${FUNCNAME[0]}------> ${FUNCNAME[0]}"
echo "# my source or script real path (realpath)------------------> $realpath"
echo
[ "$realpath" = "workdir" ] || ret=1
[ $ret = 0 ] || echo "*******************************************************"
[ $ret = 0 ] || echo "*********** ERROR **********************************"
[ $ret = 0 ] || echo "*******************************************************"
show_params () {
echo
echo "# --- RESULTS FROM show_params() ---- #"
echo "# path to me (\$0)-----------> ${0} "
echo "# arguments called with ----> ${@} "
echo "# \$1 -----------------------> $1 "
echo "# \$2 -----------------------> $2 "
echo "# path to me (\$fullname)----> ${fullname} "
echo "# parent path(\${0%/*})------> ${0%/*} "
echo "# parent path(\$dirname)-----> ${dirname} "
echo "# my name ----\${0##*/}------> ${0##*/} "
echo "# my source -\${BASH_SOURCE}-> ${BASH_SOURCE} "
echo "# parent path(from BASH_SOURCE) -> $(dirname $BASH_SOURCE)"
echo "# my function name -\${FUNCNAME[0]}------> ${FUNCNAME[0]}"
echo "# my source or script real path (realpath)------------------> $realpath"
echo
[ "$realpath" = "workdir" ] || ret=1
[ $ret = 0 ] || echo "*******************************************************"
[ $ret = 0 ] || echo "*********** ERROR **********************************"
[ $ret = 0 ] || echo "*******************************************************"
}
show_params "$@"
EOD
cat workdir/_script_.sh > workdir/_side_by_side_script_sourced.inc
cat <<'EOD' >> workdir/_script_.sh
echo "# . $realpath/_side_by_side_script_sourced.inc 'hello there' 'william'"
. $realpath/_side_by_side_script_sourced.inc 'hello there' 'william'
[ $ret = 0 ] || echo "*******************************************************"
[ $ret = 0 ] || echo "*********** ERROR **********************************"
[ $ret = 0 ] || echo "*******************************************************"
EOD
chmod +x workdir/_script_.sh
[ -L _mytest_ ] && rm _mytest_
ln -s workdir/_script_.sh _mytest_
# ------------- CALLED ------------- #
called_by () {
echo '=========================================================================='
echo " Called by : " "$@"
echo '=========================================================================='
eval "$@"
}
called_by bash _mytest_
called_by ./_mytest_
called_by bash workdir/_script_.sh
called_by workdir/_script_.sh
called_by . workdir/_script_.sh
# ------------- RESULTS ------------- #
echo
echo
[ $ret = 0 ] || echo "*******************************************************"
[ $ret = 0 ] || echo "*********** ERROR **********************************"
[ $ret = 0 ] || echo "*******************************************************"
echo
[ $ret = 0 ] && echo ".... location of scripts (\$realpath) should always be equal to $realpath, for all test cases at date".
echo
# ------------- END ------------- #
以下是我从Dimitre Radoulov的回答中得到的灵感(顺便说一下,我给他的回答投了赞)。
script="$BASH_SOURCE"
[ -z "$BASH_SOURCE" ] && script="$0"
echo "Called $script with $# argument(s)"
不管你如何调用你的脚本
. path/to/script.sh
or
./path/to/script.sh
me=`basename "$0"`
对于读取symlink1,这通常不是你想要的(你通常不想以这种方式迷惑用户),尝试:
me="$(basename "$(test -L "$0" && readlink "$0" || echo "$0")")"
在我看来,这会产生令人困惑的输出。“我跑了foo.sh,但它说我跑了bar.sh!?”一定是虫子!”此外,使用不同名称的符号链接的目的之一是根据其名称提供不同的功能(例如某些平台上的gzip和gunzip)。
1也就是说,为了解析符号链接,当用户执行foo.sh时,它实际上是一个到bar.sh的符号链接,你希望使用解析的名称bar.sh而不是foo.sh。
在bash中,您可以使用$0获取脚本文件名。通常$1,$2等用于访问CLI参数。类似地,$0是访问触发脚本的名称(脚本文件名)。
#!/bin/bash
echo "You are running $0"
...
...
如果你使用/path/to/script.sh这样的路径调用脚本,那么$0也会给出带有路径的文件名。在这种情况下,需要使用$(basename $0)来获取脚本文件名。
如果脚本名中有空格,更可靠的方法是使用"$0"或"$(basename "$0")"-或MacOS: "$(basename \"$0\")"。这可以防止名称以任何方式被破坏或解释。一般来说,在shell中始终使用双引号作为变量名是一种良好的实践。