如果我有两个约会(例如。'8/18/2008'和'9/26/2008'),怎样才能得到这两个日期之间的天数?
当前回答
您需要datetime模块。
>>> from datetime import datetime
>>> datetime(2008,08,18) - datetime(2008,09,26)
datetime.timedelta(4)
另一个例子:
>>> import datetime
>>> today = datetime.date.today()
>>> print(today)
2008-09-01
>>> last_year = datetime.date(2007, 9, 1)
>>> print(today - last_year)
366 days, 0:00:00
正如这里所指出的
其他回答
对于计算日期和时间,有几个选项,但我将写简单的方式:
from datetime import timedelta, datetime, date
import dateutil.relativedelta
# current time
date_and_time = datetime.now()
date_only = date.today()
time_only = datetime.now().time()
# calculate date and time
result = date_and_time - timedelta(hours=26, minutes=25, seconds=10)
# calculate dates: years (-/+)
result = date_only - dateutil.relativedelta.relativedelta(years=10)
# months
result = date_only - dateutil.relativedelta.relativedelta(months=10)
# week
results = date_only - dateutil.relativedelta.relativedelta(weeks=1)
# days
result = date_only - dateutil.relativedelta.relativedelta(days=10)
# calculate time
result = date_and_time - timedelta(hours=26, minutes=25, seconds=10)
result.time()
希望能有所帮助
圣诞节前几天:
>>> import datetime
>>> today = datetime.date.today()
>>> someday = datetime.date(2008, 12, 25)
>>> diff = someday - today
>>> diff.days
86
这里有更多的算术。
from datetime import date
def d(s):
[month, day, year] = map(int, s.split('/'))
return date(year, month, day)
def days(start, end):
return (d(end) - d(start)).days
print days('8/18/2008', '9/26/2008')
当然,这假设您已经验证了日期的格式为r'\d+/\d+/\d+'。
以下是解决这个问题的三种方法:
from datetime import datetime
Now = datetime.now()
StartDate = datetime.strptime(str(Now.year) +'-01-01', '%Y-%m-%d')
NumberOfDays = (Now - StartDate)
print(NumberOfDays.days) # Starts at 0
print(datetime.now().timetuple().tm_yday) # Starts at 1
print(Now.strftime('%j')) # Starts at 1
它也可以很容易地用箭头完成:
import arrow
a = arrow.get('2017-05-09')
b = arrow.get('2017-05-11')
delta = (b-a)
print delta.days
参考:http://arrow.readthedocs.io/en/latest/
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