常见的方法是将文档转换为TF-IDF向量，然后计算它们之间的余弦相似度。任何关于信息检索(IR)的教科书都涵盖了这一点。参见《信息检索导论》，该书可在网上免费获得。

两两计算相似度

TF-IDF(以及类似的文本转换)在Python包Gensim和scikit-learn中实现。在后一个包中，计算余弦相似度非常简单

from sklearn.feature_extraction.text import TfidfVectorizer

documents = [open(f).read() for f in text_files]
tfidf = TfidfVectorizer().fit_transform(documents)
# no need to normalize, since Vectorizer will return normalized tf-idf
pairwise_similarity = tfidf * tfidf.T

或者，如果文档是普通字符串，

>>> corpus = ["I'd like an apple", 
...           "An apple a day keeps the doctor away", 
...           "Never compare an apple to an orange", 
...           "I prefer scikit-learn to Orange", 
...           "The scikit-learn docs are Orange and Blue"]                                                                                                                                                                                                   
>>> vect = TfidfVectorizer(min_df=1, stop_words="english")                                                                                                                                                                                                   
>>> tfidf = vect.fit_transform(corpus)                                                                                                                                                                                                                       
>>> pairwise_similarity = tfidf * tfidf.T 

尽管Gensim在这类任务中可能有更多选择。

再看看这个问题。

[免责声明:我参与了scikit-learn TF-IDF的实现。]

解读结果

从上面来看，pairwise_similarity是一个方形的Scipy稀疏矩阵，行数和列数等于语料库中文档的数量。

>>> pairwise_similarity                                                                                                                                                                                                                                      
<5x5 sparse matrix of type '<class 'numpy.float64'>'
    with 17 stored elements in Compressed Sparse Row format>

你可以通过.toarray()或.A将稀疏数组转换为NumPy数组:

>>> pairwise_similarity.toarray()                                                                                                                                                                                                                            
array([[1.        , 0.17668795, 0.27056873, 0.        , 0.        ],
       [0.17668795, 1.        , 0.15439436, 0.        , 0.        ],
       [0.27056873, 0.15439436, 1.        , 0.19635649, 0.16815247],
       [0.        , 0.        , 0.19635649, 1.        , 0.54499756],
       [0.        , 0.        , 0.16815247, 0.54499756, 1.        ]])

假设我们想要找到与最终文档最相似的文档，“the scikit-learn docs are Orange and Blue”。本文语料库索引为4。您可以通过取该行的argmax来找到最相似文档的索引，但首先需要屏蔽1,1表示每个文档与其自身的相似性。你可以通过np.fill_diagonal()来实现后者，通过np.nanargmax()来实现前者:

>>> import numpy as np     
                                                                                                                                                                                                                                  
>>> arr = pairwise_similarity.toarray()     
>>> np.fill_diagonal(arr, np.nan)                                                                                                                                                                                                                            
                                                                                                                                                                                                                 
>>> input_doc = "The scikit-learn docs are Orange and Blue"                                                                                                                                                                                                  
>>> input_idx = corpus.index(input_doc)                                                                                                                                                                                                                      
>>> input_idx                                                                                                                                                                                                                                                
4

>>> result_idx = np.nanargmax(arr[input_idx])                                                                                                                                                                                                                
>>> corpus[result_idx]                                                                                                                                                                                                                                       
'I prefer scikit-learn to Orange'

注意:使用稀疏矩阵的目的是为大型语料库和词汇表节省(大量空间)。你可以这样做，而不是转换为NumPy数组:

>>> n, _ = pairwise_similarity.shape                                                                                                                                                                                                                         
>>> pairwise_similarity[np.arange(n), np.arange(n)] = -1.0
>>> pairwise_similarity[input_idx].argmax()                                                                                                                                                                                                                  
3

与@larsman相同，但有一些预处理

import nltk, string
from sklearn.feature_extraction.text import TfidfVectorizer

nltk.download('punkt') # if necessary...


stemmer = nltk.stem.porter.PorterStemmer()
remove_punctuation_map = dict((ord(char), None) for char in string.punctuation)

def stem_tokens(tokens):
    return [stemmer.stem(item) for item in tokens]

'''remove punctuation, lowercase, stem'''
def normalize(text):
    return stem_tokens(nltk.word_tokenize(text.lower().translate(remove_punctuation_map)))

vectorizer = TfidfVectorizer(tokenizer=normalize, stop_words='english')

def cosine_sim(text1, text2):
    tfidf = vectorizer.fit_transform([text1, text2])
    return ((tfidf * tfidf.T).A)[0,1]


print cosine_sim('a little bird', 'a little bird')
print cosine_sim('a little bird', 'a little bird chirps')
print cosine_sim('a little bird', 'a big dog barks')

这里有一个小应用程序让你开始…

import difflib as dl

a = file('file').read()
b = file('file1').read()

sim = dl.get_close_matches

s = 0
wa = a.split()
wb = b.split()

for i in wa:
    if sim(i, wb):
        s += 1

n = float(s) / float(len(wa))
print '%d%% similarity' % int(n * 100)

这里是Simphile NLP文本相似性Python包的创建者。Simphile包含几种文本相似度方法，它们与语言无关，并且比语言嵌入占用的cpu更少。

安装:

pip install simphile

选择你最喜欢的方法。这个例子显示了三点:

from simphile import jaccard_similarity, euclidian_similarity, compression_similarity

text_a = "I love dogs"
text_b = "I love cats"

print(f"Jaccard Similarity: {jaccard_similarity(text_a, text_b)}")
print(f"Euclidian Similarity: {euclidian_similarity(text_a, text_b)}")
print(f"Compression Similarity: {compression_similarity(text_a, text_b)}")

压缩相似性——利用压缩算法的模式识别 欧几里得相似性-把文本当作多维空间中的点，并计算它们的接近度 Jaccard Similairy -文字重叠越多，文本越相似

这是一个老问题了，但我发现斯派西可以很容易地解决这个问题。读取文档后，可以使用简单的api相似性来查找文档向量之间的余弦相似性。

首先安装包并下载模型:

pip install spacy
python -m spacy download en_core_web_sm

然后用like so:

import spacy
nlp = spacy.load('en_core_web_sm')
doc1 = nlp(u'Hello hi there!')
doc2 = nlp(u'Hello hi there!')
doc3 = nlp(u'Hey whatsup?')

print (doc1.similarity(doc2)) # 0.999999954642
print (doc2.similarity(doc3)) # 0.699032527716
print (doc1.similarity(doc3)) # 0.699032527716

我们可以使用句子转换来完成这个任务 链接

下面是一个来自sbert的简单示例:

from sentence_transformers import SentenceTransformer, util
model = SentenceTransformer('all-MiniLM-L6-v2')
# Two lists of sentences
sentences1 = ['The cat sits outside']
sentences2 = ['The dog plays in the garden']
#Compute embedding for both lists
embeddings1 = model.encode(sentences1, convert_to_tensor=True)
embeddings2 = model.encode(sentences2, convert_to_tensor=True)
#Compute cosine-similarities
cosine_scores = util.cos_sim(embeddings1, embeddings2)
#Output the pairs with their score
for i in range(len(sentences1)):
   print("{} \t\t {} \t\t Score: {:.4f}".format(sentences1[i], 
         sentences2[i], cosine_scores[i][i]))