我怎样才能做得快呢?

当然我可以这样做:

static bool ByteArrayCompare(byte[] a1, byte[] a2)
{
    if (a1.Length != a2.Length)
        return false;

    for (int i=0; i<a1.Length; i++)
        if (a1[i]!=a2[i])
            return false;

    return true;
}

但我正在寻找一个BCL函数或一些高度优化的已证明的方法来做到这一点。

java.util.Arrays.equals((sbyte[])(Array)a1, (sbyte[])(Array)a2);

工作得很好,但这似乎不适用于x64。

注意我的快速回答。


当前回答

使用SequenceEquals进行比较。

其他回答

让我们再加一个!

最近微软发布了一个特殊的NuGet包System.Runtime.CompilerServices.Unsafe。它的特殊之处在于它是用IL编写的,并且提供了c#中无法直接使用的低级功能。

它的一个方法unsafety . as <T>(object)允许将任何引用类型转换为另一个引用类型,跳过任何安全检查。这通常是一个非常糟糕的主意,但如果两种类型具有相同的结构,它就可以工作。因此,我们可以使用这个函数将字节[]转换为长[]:

bool CompareWithUnsafeLibrary(byte[] a1, byte[] a2)
{
    if (a1.Length != a2.Length) return false;

    var longSize = (int)Math.Floor(a1.Length / 8.0);
    var long1 = Unsafe.As<long[]>(a1);
    var long2 = Unsafe.As<long[]>(a2);

    for (var i = 0; i < longSize; i++)
    {
        if (long1[i] != long2[i]) return false;
    }

    for (var i = longSize * 8; i < a1.Length; i++)
    {
        if (a1[i] != a2[i]) return false;
    }

    return true;
}

注意long1。Length仍然会返回原始数组的长度,因为它存储在数组内存结构中的字段中。

这个方法没有这里演示的其他方法那么快,但它比朴素方法快得多,不使用不安全的代码或P/Invoke或固定,实现非常简单(IMO)。以下是我的机器上的一些BenchmarkDotNet结果:

BenchmarkDotNet=v0.10.3.0, OS=Microsoft Windows NT 6.2.9200.0
Processor=Intel(R) Core(TM) i7-4870HQ CPU 2.50GHz, ProcessorCount=8
Frequency=2435775 Hz, Resolution=410.5470 ns, Timer=TSC
  [Host]     : Clr 4.0.30319.42000, 64bit RyuJIT-v4.6.1637.0
  DefaultJob : Clr 4.0.30319.42000, 64bit RyuJIT-v4.6.1637.0

                 Method |          Mean |    StdDev |
----------------------- |-------------- |---------- |
          UnsafeLibrary |   125.8229 ns | 0.3588 ns |
          UnsafeCompare |    89.9036 ns | 0.8243 ns |
           JSharpEquals | 1,432.1717 ns | 1.3161 ns |
 EqualBytesLongUnrolled |    43.7863 ns | 0.8923 ns |
              NewMemCmp |    65.4108 ns | 0.2202 ns |
            ArraysEqual |   910.8372 ns | 2.6082 ns |
          PInvokeMemcmp |    52.7201 ns | 0.1105 ns |

我还为所有测试创建了一个要点。

我想到了许多显卡内置的块传输加速方法。但是这样你就必须按字节复制所有的数据,所以如果你不想在非托管和依赖硬件的代码中实现你的整个逻辑,这对你没有多大帮助……

Another way of optimization similar to the approach shown above would be to store as much of your data as possible in a long[] rather than a byte[] right from the start, for example if you are reading it sequentially from a binary file, or if you use a memory mapped file, read in data as long[] or single long values. Then, your comparison loop will only need 1/8th of the number of iterations it would have to do for a byte[] containing the same amount of data. It is a matter of when and how often you need to compare vs. when and how often you need to access the data in a byte-by-byte manner, e.g. to use it in an API call as a parameter in a method that expects a byte[]. In the end, you only can tell if you really know the use case...

编辑:现代的快速方法是使用a1.SequenceEquals(a2)

用户gil提出了不安全的代码,产生了这个解决方案:

// Copyright (c) 2008-2013 Hafthor Stefansson
// Distributed under the MIT/X11 software license
// Ref: http://www.opensource.org/licenses/mit-license.php.
static unsafe bool UnsafeCompare(byte[] a1, byte[] a2) {
  unchecked {
    if(a1==a2) return true;
    if(a1==null || a2==null || a1.Length!=a2.Length)
      return false;
    fixed (byte* p1=a1, p2=a2) {
      byte* x1=p1, x2=p2;
      int l = a1.Length;
      for (int i=0; i < l/8; i++, x1+=8, x2+=8)
        if (*((long*)x1) != *((long*)x2)) return false;
      if ((l & 4)!=0) { if (*((int*)x1)!=*((int*)x2)) return false; x1+=4; x2+=4; }
      if ((l & 2)!=0) { if (*((short*)x1)!=*((short*)x2)) return false; x1+=2; x2+=2; }
      if ((l & 1)!=0) if (*((byte*)x1) != *((byte*)x2)) return false;
      return true;
    }
  }
}

它对尽可能多的数组进行基于64位的比较。这依赖于数组以qword对齐开始的事实。它会工作,如果不是qword对齐,只是没有那么快,如果它是。

它比简单的“for”循环快了大约7个计时器。使用j#库执行相当于原来的' for '循环。使用.SequenceEqual会慢7倍左右;我想只是因为它使用了ienumerator。movenext。我认为基于linq的解决方案至少会这么慢,甚至更糟。

似乎EqualBytesLongUnrolled是上述建议中最好的。

被跳过的方法(Enumerable.SequenceEqual,StructuralComparisons.StructuralEqualityComparer.Equals)不是慢速的。在265MB的数组上,我测量了这个:

Host Process Environment Information:
BenchmarkDotNet.Core=v0.9.9.0
OS=Microsoft Windows NT 6.2.9200.0
Processor=Intel(R) Core(TM) i7-3770 CPU 3.40GHz, ProcessorCount=8
Frequency=3323582 ticks, Resolution=300.8802 ns, Timer=TSC
CLR=MS.NET 4.0.30319.42000, Arch=64-bit RELEASE [RyuJIT]
GC=Concurrent Workstation
JitModules=clrjit-v4.6.1590.0

Type=CompareMemoriesBenchmarks  Mode=Throughput  

                 Method |      Median |    StdDev | Scaled | Scaled-SD |
----------------------- |------------ |---------- |------- |---------- |
             NewMemCopy |  30.0443 ms | 1.1880 ms |   1.00 |      0.00 |
 EqualBytesLongUnrolled |  29.9917 ms | 0.7480 ms |   0.99 |      0.04 |
          msvcrt_memcmp |  30.0930 ms | 0.2964 ms |   1.00 |      0.03 |
          UnsafeCompare |  31.0520 ms | 0.7072 ms |   1.03 |      0.04 |
       ByteArrayCompare | 212.9980 ms | 2.0776 ms |   7.06 |      0.25 |

OS=Windows
Processor=?, ProcessorCount=8
Frequency=3323582 ticks, Resolution=300.8802 ns, Timer=TSC
CLR=CORE, Arch=64-bit ? [RyuJIT]
GC=Concurrent Workstation
dotnet cli version: 1.0.0-preview2-003131

Type=CompareMemoriesBenchmarks  Mode=Throughput  

                 Method |      Median |    StdDev | Scaled | Scaled-SD |
----------------------- |------------ |---------- |------- |---------- |
             NewMemCopy |  30.1789 ms | 0.0437 ms |   1.00 |      0.00 |
 EqualBytesLongUnrolled |  30.1985 ms | 0.1782 ms |   1.00 |      0.01 |
          msvcrt_memcmp |  30.1084 ms | 0.0660 ms |   1.00 |      0.00 |
          UnsafeCompare |  31.1845 ms | 0.4051 ms |   1.03 |      0.01 |
       ByteArrayCompare | 212.0213 ms | 0.1694 ms |   7.03 |      0.01 |

我使用附带的。net 4.7发布版本做了一些测量,没有附带调试器。我认为人们一直在使用错误的度量,因为如果你关心这里的速度,你所关心的是计算两个字节数组是否相等需要多长时间。即以字节为单位的吞吐量。

StructuralComparison :              4.6 MiB/s
for                  :            274.5 MiB/s
ToUInt32             :            263.6 MiB/s
ToUInt64             :            474.9 MiB/s
memcmp               :           8500.8 MiB/s

正如你所看到的,没有比memcmp更好的方法了,而且它快了几个数量级。简单的for循环是次优选择。我仍然不明白为什么微软不能简单地包含一个缓冲区。比较方法。

[Program.cs]:

using System;
using System.Collections;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Runtime.InteropServices;
using System.Text;
using System.Threading.Tasks;

namespace memcmp
{
    class Program
    {
        static byte[] TestVector(int size)
        {
            var data = new byte[size];
            using (var rng = new System.Security.Cryptography.RNGCryptoServiceProvider())
            {
                rng.GetBytes(data);
            }
            return data;
        }

        static TimeSpan Measure(string testCase, TimeSpan offset, Action action, bool ignore = false)
        {
            var t = Stopwatch.StartNew();
            var n = 0L;
            while (t.Elapsed < TimeSpan.FromSeconds(10))
            {
                action();
                n++;
            }
            var elapsed = t.Elapsed - offset;
            if (!ignore)
            {
                Console.WriteLine($"{testCase,-16} : {n / elapsed.TotalSeconds,16:0.0} MiB/s");
            }
            return elapsed;
        }

        [DllImport("msvcrt.dll", CallingConvention = CallingConvention.Cdecl)]
        static extern int memcmp(byte[] b1, byte[] b2, long count);

        static void Main(string[] args)
        {
            // how quickly can we establish if two sequences of bytes are equal?

            // note that we are testing the speed of different comparsion methods

            var a = TestVector(1024 * 1024); // 1 MiB
            var b = (byte[])a.Clone();

            // was meant to offset the overhead of everything but copying but my attempt was a horrible mistake... should have reacted sooner due to the initially ridiculous throughput values...
            // Measure("offset", new TimeSpan(), () => { return; }, ignore: true);
            var offset = TimeZone.Zero

            Measure("StructuralComparison", offset, () =>
            {
                StructuralComparisons.StructuralEqualityComparer.Equals(a, b);
            });

            Measure("for", offset, () =>
            {
                for (int i = 0; i < a.Length; i++)
                {
                    if (a[i] != b[i]) break;
                }
            });

            Measure("ToUInt32", offset, () =>
            {
                for (int i = 0; i < a.Length; i += 4)
                {
                    if (BitConverter.ToUInt32(a, i) != BitConverter.ToUInt32(b, i)) break;
                }
            });

            Measure("ToUInt64", offset, () =>
            {
                for (int i = 0; i < a.Length; i += 8)
                {
                    if (BitConverter.ToUInt64(a, i) != BitConverter.ToUInt64(b, i)) break;
                }
            });

            Measure("memcmp", offset, () =>
            {
                memcmp(a, b, a.Length);
            });
        }
    }
}