另一种方法(帮助@NullUserException和@Wexoni的注释)是在数组中检索对象的索引，然后从那里开始:

var index = array.map(function(obj){ return obj.name; }).indexOf('name-I-am-looking-for');
// Then we can access it to do whatever we want
array[index] = {name: 'newName', value: 'that', other: 'rocks'};

考虑到您有以下片段:

var array = [
    { name:"string 1", value:"this", other: "that" },
    { name:"string 2", value:"this", other: "that" }
];

您可以使用以下函数来搜索项目

const search = what => array.find(element => element.name === what);

您可以检查是否找到了该项目。

const found = search("string1");
if (found) {
    console.log(found.value, found.other);
} else {
    console.log('No result found');
}

var array = [
    { name:"string 1", value:"this", other: "that" },
    { name:"string 2", value:"this", other: "that" }
];

var foundValue = array.filter(obj=>obj.name==='string 1');

console.log(foundValue);

使用简单的for循环:

var result = null;
for (var i = 0; i < array.length; i++) { 
  if (array[i].name === "string 1") { 
    result = array[i];
    break;
  } 
}

如果可以，也就是说，如果您的浏览器支持，请使用Array。过滤器，它更简洁:

var result = array.filter(function (obj) {
  return obj.name === "string 1";
})[0];

你可以循环数组并测试该属性: 函数搜索(nameKey, myArray){ For(令i=0;i < myArray.length;我+ +){ if (myArray[i].name === nameKey) { 返回myArray[我]; ｝ ｝ ｝ Const数组= [ {name:"string 1"， value:"this"， other: "that"}， {name:"string 2"， value:"this"， other: "that"} ]; const resultObject = search("string 1"，数组); console.log (resultObject)

你可以使用npm中的查询对象。您可以使用筛选器搜索对象数组。

const queryable = require('query-objects');

const users = [
    {
      firstName: 'George',
      lastName: 'Eracleous',
      age: 28
    },
    {
      firstName: 'Erica',
      lastName: 'Archer',
      age: 50
    },
    {
      firstName: 'Leo',
      lastName: 'Andrews',
      age: 20
    }
];

const filters = [
    {
      field: 'age',
      value: 30,
      operator: 'lt'
    },
    {
      field: 'firstName',
      value: 'Erica',
      operator: 'equals'
    }
];

// Filter all users that are less than 30 years old AND their first name is Erica
const res = queryable(users).and(filters);

// Filter all users that are less than 30 years old OR their first name is Erica
const res = queryable(users).or(filters);