我在格式化日期时间时遇到了麻烦。timedelta对象。
这就是我想做的: 我有一个对象列表,对象类的成员之一是显示事件持续时间的timedelta对象。我想以小时:分钟的格式显示这个持续时间。
我尝试了各种方法来做这件事,但我有困难。我目前的方法是为返回小时和分钟的对象在类中添加方法。我可以通过除以time得到小时数。秒乘以3600,四舍五入。我在得到剩余的秒并将其转换为分钟时遇到了麻烦。
顺便说一下,我使用谷歌AppEngine和Django模板来表示。
我在格式化日期时间时遇到了麻烦。timedelta对象。
这就是我想做的: 我有一个对象列表,对象类的成员之一是显示事件持续时间的timedelta对象。我想以小时:分钟的格式显示这个持续时间。
我尝试了各种方法来做这件事,但我有困难。我目前的方法是为返回小时和分钟的对象在类中添加方法。我可以通过除以time得到小时数。秒乘以3600,四舍五入。我在得到剩余的秒并将其转换为分钟时遇到了麻烦。
顺便说一下,我使用谷歌AppEngine和Django模板来表示。
当前回答
我使用人类友好的python库来做这件事,它工作得非常好。
import humanfriendly
from datetime import timedelta
delta = timedelta(seconds = 321)
humanfriendly.format_timespan(delta)
'5 minutes and 21 seconds'
网址:https://pypi.org/project/humanfriendly/
其他回答
Timedelta到字符串,用于打印运行时间信息。
def strfdelta_round(tdelta, round_period='second'):
"""timedelta to string, use for measure running time
attend period from days downto smaller period, round to minimum period
omit zero value period
"""
period_names = ('day', 'hour', 'minute', 'second', 'millisecond')
if round_period not in period_names:
raise Exception(f'round_period "{round_period}" invalid, should be one of {",".join(period_names)}')
period_seconds = (86400, 3600, 60, 1, 1/pow(10,3))
period_desc = ('days', 'hours', 'mins', 'secs', 'msecs')
round_i = period_names.index(round_period)
s = ''
remainder = tdelta.total_seconds()
for i in range(len(period_names)):
q, remainder = divmod(remainder, period_seconds[i])
if int(q)>0:
if not len(s)==0:
s += ' '
s += f'{q:.0f} {period_desc[i]}'
if i==round_i:
break
if i==round_i+1:
s += f'{remainder} {period_desc[round_i]}'
break
return s
例如,自动省略零前导周期:
>>> td = timedelta(days=0, hours=2, minutes=5, seconds=8, microseconds=3549)
>>> strfdelta_round(td, 'second')
'2 hours 5 mins 8 secs'
或者省略中间的零周期:
>>> td = timedelta(days=2, hours=0, minutes=5, seconds=8, microseconds=3549)
>>> strfdelta_round(td, 'millisecond')
'2 days 5 mins 8 secs 3 msecs'
或舍入至分钟,省略以下分钟:
>>> td = timedelta(days=1, hours=2, minutes=5, seconds=8, microseconds=3549)
>>> strfdelta_round(td, 'minute')
'1 days 2 hours 5 mins'
提问者想要一个比典型的更好的格式:
>>> import datetime
>>> datetime.timedelta(seconds=41000)
datetime.timedelta(0, 41000)
>>> str(datetime.timedelta(seconds=41000))
'11:23:20'
>>> str(datetime.timedelta(seconds=4102.33))
'1:08:22.330000'
>>> str(datetime.timedelta(seconds=413302.33))
'4 days, 18:48:22.330000'
所以,实际上有两种格式,一种是天数为0,它被省略了,另一种是文本“n天,h:m:s”。但是,秒可能有分数,打印输出中没有前导0,所以列很乱。
如果你喜欢,下面是我的日常工作:
def printNiceTimeDelta(stime, etime):
delay = datetime.timedelta(seconds=(etime - stime))
if (delay.days > 0):
out = str(delay).replace(" days, ", ":")
else:
out = "0:" + str(delay)
outAr = out.split(':')
outAr = ["%02d" % (int(float(x))) for x in outAr]
out = ":".join(outAr)
return out
返回dd:hh:mm:ss格式的输出:
00:00:00:15
00:00:00:19
02:01:31:40
02:01:32:22
我确实想过在上面加上年份,但这是留给读者的练习,因为超过1年的输出是安全的:
>>> str(datetime.timedelta(seconds=99999999))
'1157 days, 9:46:39'
可能:
>>> import datetime
>>> dt0 = datetime.datetime(1,1,1)
>>> td = datetime.timedelta(minutes=34, hours=12, seconds=56)
>>> (dt0+td).strftime('%X')
'12:34:56'
>>> (dt0+td).strftime('%M:%S')
'34:56'
>>> (dt0+td).strftime('%H:%M')
'12:34'
>>>
# Format seconds to days, hours, minutes and seconds string
def ptime(seconds):
if(seconds >= 86400):
d = seconds // 86400 # // floor division
return (f"{round(d)}d") + ptime(seconds - d * 86400)
else:
if(seconds >= 3600):
h = seconds // 3600
return (f"{round(h)}h") + ptime(seconds - h * 3600)
else:
if(seconds >= 60):
m = seconds // 60
return(f"{round(m)}m" + ptime(seconds - m * 60))
else:
if (seconds > 0):
return(f"{round(seconds)}s")
else:
return("")
我想这样做,所以写了一个简单的函数。它对我来说非常有用,而且非常通用(支持年到微秒,以及任何粒度级别,例如,你可以选择“2天4小时48分钟”和“2天4小时”和“2天4.8小时”等。
def pretty_print_timedelta(t, max_components=None, max_decimal_places=2):
'''
Print a pretty string for a timedelta.
For example datetime.timedelta(days=2, seconds=17280) will be printed as '2 days, 4 hours, 48 minutes'. Setting max_components to e.g. 1 will change this to '2.2 days', where the
number of decimal points can also be set.
'''
time_scales = [timedelta(days=365), timedelta(days=1), timedelta(hours=1), timedelta(minutes=1), timedelta(seconds=1), timedelta(microseconds=1000), timedelta(microseconds=1)]
time_scale_names_dict = {timedelta(days=365): 'year',
timedelta(days=1): 'day',
timedelta(hours=1): 'hour',
timedelta(minutes=1): 'minute',
timedelta(seconds=1): 'second',
timedelta(microseconds=1000): 'millisecond',
timedelta(microseconds=1): 'microsecond'}
count = 0
txt = ''
first = True
for scale in time_scales:
if t >= scale:
count += 1
if count == max_components:
n = t / scale
else:
n = int(t / scale)
t -= n*scale
n_txt = str(round(n, max_decimal_places))
if n_txt[-2:]=='.0': n_txt = n_txt[:-2]
txt += '{}{} {}{}'.format('' if first else ', ', n_txt, time_scale_names_dict[scale], 's' if n>1 else '', )
if first:
first = False
if len(txt) == 0:
txt = 'none'
return txt