这是这个问题的另一个答案。

(新版本发布于6/4/13)。

    private static DataSet GetDataSet(SqlConnectionStringBuilder scsb, string strSql, params object[] pars)
    {
        var ds = new DataSet();
        using (var sqlConn = new SqlConnection(scsb.ConnectionString))
        {
            var sqlParameters = new List<SqlParameter>();
            var replacementStrings = new Dictionary<string, string>();
            if (pars != null)
            {
                for (int i = 0; i < pars.Length; i++)
                {
                    if (pars[i] is IEnumerable<object>)
                    {
                        List<object> enumerable = (pars[i] as IEnumerable<object>).ToList();
                        replacementStrings.Add("@" + i, String.Join(",", enumerable.Select((value, pos) => String.Format("@_{0}_{1}", i, pos))));
                        sqlParameters.AddRange(enumerable.Select((value, pos) => new SqlParameter(String.Format("@_{0}_{1}", i, pos), value ?? DBNull.Value)).ToArray());
                    }
                    else
                    {
                        sqlParameters.Add(new SqlParameter(String.Format("@{0}", i), pars[i] ?? DBNull.Value));
                    }
                }
            }
            strSql = replacementStrings.Aggregate(strSql, (current, replacementString) => current.Replace(replacementString.Key, replacementString.Value));
            using (var sqlCommand = new SqlCommand(strSql, sqlConn))
            {
                if (pars != null)
                {
                    sqlCommand.Parameters.AddRange(sqlParameters.ToArray());
                }
                else
                {
                    //Fail-safe, just in case a user intends to pass a single null parameter
                    sqlCommand.Parameters.Add(new SqlParameter("@0", DBNull.Value));
                }
                using (var sqlDataAdapter = new SqlDataAdapter(sqlCommand))
                {
                    sqlDataAdapter.Fill(ds);
                }
            }
        }
        return ds;
    }

欢呼。

另一种可能的解决方案是，不向存储过程传递可变数量的参数，而是传递一个包含您要查找的名称的字符串，但通过将它们围绕在'<>'中使它们唯一。然后使用PATINDEX查找名称:

SELECT * 
FROM Tags 
WHERE PATINDEX('%<' + Name + '>%','<jo>,<john>,<scruffy>,<rubyonrails>') > 0

可以将参数作为字符串传递

这是弦

DECLARE @tags

SET @tags = ‘ruby|rails|scruffy|rubyonrails’

select * from Tags 
where Name in (SELECT item from fnSplit(@tags, ‘|’))
order by Count desc

然后你所要做的就是将字符串作为1参数传递。

这是我使用的分裂函数。

CREATE FUNCTION [dbo].[fnSplit](
    @sInputList VARCHAR(8000) -- List of delimited items
  , @sDelimiter VARCHAR(8000) = ',' -- delimiter that separates items
) RETURNS @List TABLE (item VARCHAR(8000))

BEGIN
DECLARE @sItem VARCHAR(8000)
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0
 BEGIN
 SELECT
  @sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,@sInputList,0)-1))),
  @sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList))))

 IF LEN(@sItem) > 0
  INSERT INTO @List SELECT @sItem
 END

IF LEN(@sInputList) > 0
 INSERT INTO @List SELECT @sInputList -- Put the last item in
RETURN
END

如果你有SQL Server 2008或更高版本，我会使用表值参数。

如果你不幸被困在SQL Server 2005上，你可以添加这样一个CLR函数，

[SqlFunction(
    DataAccessKind.None,
    IsDeterministic = true,
    SystemDataAccess = SystemDataAccessKind.None,
    IsPrecise = true,
    FillRowMethodName = "SplitFillRow",
    TableDefinintion = "s NVARCHAR(MAX)"]
public static IEnumerable Split(SqlChars seperator, SqlString s)
{
    if (s.IsNull)
        return new string[0];

    return s.ToString().Split(seperator.Buffer);
}

public static void SplitFillRow(object row, out SqlString s)
{
    s = new SqlString(row.ToString());
}

你可以这样用，

declare @desiredTags nvarchar(MAX);
set @desiredTags = 'ruby,rails,scruffy,rubyonrails';

select * from Tags
where Name in [dbo].[Split] (',', @desiredTags)
order by Count desc

这是一个可重复使用的变化的解决方案在马克托罗特的优秀答案。

扩展方法:

public static class ParameterExtensions
{
    public static Tuple<string, SqlParameter[]> ToParameterTuple<T>(this IEnumerable<T> values)
    {
        var createName = new Func<int, string>(index => "@value" + index.ToString());
        var paramTuples = values.Select((value, index) => 
        new Tuple<string, SqlParameter>(createName(index), new SqlParameter(createName(index), value))).ToArray();
        var inClause = string.Join(",", paramTuples.Select(t => t.Item1));
        var parameters = paramTuples.Select(t => t.Item2).ToArray();
        return new Tuple<string, SqlParameter[]>(inClause, parameters);
    }
}

用法:

        string[] tags = {"ruby", "rails", "scruffy", "rubyonrails"};
        var paramTuple = tags.ToParameterTuple();
        var cmdText = $"SELECT * FROM Tags WHERE Name IN ({paramTuple.Item1})";

        using (var cmd = new SqlCommand(cmdText))
        {
            cmd.Parameters.AddRange(paramTuple.Item2);
        }

下面是我用过的一个快速而又复杂的技巧:

SELECT * FROM Tags
WHERE '|ruby|rails|scruffy|rubyonrails|'
LIKE '%|' + Name + '|%'

下面是c#代码:

string[] tags = new string[] { "ruby", "rails", "scruffy", "rubyonrails" };
const string cmdText = "select * from tags where '|' + @tags + '|' like '%|' + Name + '|%'";

using (SqlCommand cmd = new SqlCommand(cmdText)) {
   cmd.Parameters.AddWithValue("@tags", string.Join("|", tags);
}

两个问题:

演出糟透了。像“%……%"查询没有索引。 请确保没有任何|、blank或null标记，否则将无法工作

有些人可能认为还有其他更清洁的方法可以做到这一点，所以请继续阅读。