你可能已经知道，如果你使用下面这行代码，你的应用程序将会被苹果拒绝

NSString *num = [[NSUserDefaults standardUserDefaults] stringForKey:@"SBFormattedPhoneNumber"];

这是参考资料

http://ayeapi.blogspot.com/2009/12/sbformatphonenumber-is-lie.html

您可以使用以下信息

NSString *phoneName = [[UIDevice currentDevice] name];

NSString *phoneUniqueIdentifier = [[UIDevice currentDevice] uniqueIdentifier];

等等

@property(nonatomic,readonly,retain) NSString    *name;              // e.g. "My iPhone"
@property(nonatomic,readonly,retain) NSString    *model;             // e.g. @"iPhone", @"iPod Touch"
@property(nonatomic,readonly,retain) NSString    *localizedModel;    // localized version of model
@property(nonatomic,readonly,retain) NSString    *systemName;        // e.g. @"iPhone OS"
@property(nonatomic,readonly,retain) NSString    *systemVersion;     // e.g. @"2.0"
@property(nonatomic,readonly) UIDeviceOrientation orientation;       // return current device orientation
@property(nonatomic,readonly,retain) NSString    *uniqueIdentifier;  // a string unique to each device based on various hardware info.

希望这能有所帮助!

不，没有合法可靠的方法来做这件事。

如果您找到了一种方法，它将在未来被禁用，就像之前的每个方法一样。

你可能已经知道，如果你使用下面这行代码，你的应用程序将会被苹果拒绝

NSString *num = [[NSUserDefaults standardUserDefaults] stringForKey:@"SBFormattedPhoneNumber"];

这是参考资料

http://ayeapi.blogspot.com/2009/12/sbformatphonenumber-is-lie.html

您可以使用以下信息

NSString *phoneName = [[UIDevice currentDevice] name];

NSString *phoneUniqueIdentifier = [[UIDevice currentDevice] uniqueIdentifier];

等等

@property(nonatomic,readonly,retain) NSString    *name;              // e.g. "My iPhone"
@property(nonatomic,readonly,retain) NSString    *model;             // e.g. @"iPhone", @"iPod Touch"
@property(nonatomic,readonly,retain) NSString    *localizedModel;    // localized version of model
@property(nonatomic,readonly,retain) NSString    *systemName;        // e.g. @"iPhone OS"
@property(nonatomic,readonly,retain) NSString    *systemVersion;     // e.g. @"2.0"
@property(nonatomic,readonly) UIDeviceOrientation orientation;       // return current device orientation
@property(nonatomic,readonly,retain) NSString    *uniqueIdentifier;  // a string unique to each device based on various hardware info.

希望这能有所帮助!

AppStore会拒绝它，因为它超出了应用容器。

应用程序应该在它们的包中是自包含的，并且不能读取或写入指定容器区域之外的数据

第2.5.2节: https://developer.apple.com/app-store/review/guidelines/#software-requirements

使用私有API，您可以通过以下方式获取用户电话号码:

extern NSString* CTSettingCopyMyPhoneNumber();


+(NSString *) phoneNumber {
NSString *phone = CTSettingCopyMyPhoneNumber();

return phone;
}

也可以将coretphony .framework包含到你的项目中。

冒着被扣分的风险，我想建议排名最高的解决方案(目前是第一个响应)违反了2009年11月5日的最新SDK协议。我们的申请因为使用它而被拒绝了。以下是苹果公司的回应:

"For security reasons, iPhone OS restricts an application (including its preferences and data) to a unique location in the file system. This restriction is part of the security feature known as the application's "sandbox." The sandbox is a set of fine-grained controls limiting an application's access to files, preferences, network resources, hardware, and so on." The device's phone number is not available within your application's container. You will need to revise your application to read only within your directory container and resubmit your binary to iTunes Connect in order for your application to be reconsidered for the App Store.

这确实令人失望，因为我们想让用户不必输入自己的电话号码。