在Oracle中似乎没有AUTO_INCREMENT的概念,直到并且包括版本11g。
如何在Oracle 11g中创建一个行为像自动递增的列?
在Oracle中似乎没有AUTO_INCREMENT的概念,直到并且包括版本11g。
如何在Oracle 11g中创建一个行为像自动递增的列?
当前回答
create trigger t1_trigger
before insert on AUDITLOGS
for each row
begin
select t1_seq.nextval into :new.id from dual;
end;
我只需要改变表名(AUDITLOGS)与你的表名和新的。使用new.column_name标识
其他回答
这里是完整的解决方案w.r.t异常/错误处理自动增量,这个解决方案向后兼容,将工作在11g和12c,特别是如果应用程序在生产中。
请用合适的表名替换'TABLE_NAME'
--checking if table already exisits
BEGIN
EXECUTE IMMEDIATE 'DROP TABLE TABLE_NAME';
EXCEPTION WHEN OTHERS THEN NULL;
END;
/
--creating table
CREATE TABLE TABLE_NAME (
ID NUMBER(10) PRIMARY KEY NOT NULL,
.
.
.
);
--checking if sequence already exists
BEGIN
EXECUTE IMMEDIATE 'DROP SEQUENCE TABLE_NAME_SEQ';
EXCEPTION WHEN OTHERS THEN NULL;
END;
--creating sequence
/
CREATE SEQUENCE TABLE_NAME_SEQ START WITH 1 INCREMENT BY 1 MINVALUE 1 NOMAXVALUE NOCYCLE CACHE 2;
--granting rights as per required user group
/
GRANT SELECT, INSERT, UPDATE, DELETE ON TABLE_NAME TO USER_GROUP;
-- creating trigger
/
CREATE OR REPLACE TRIGGER TABLE_NAME_TS BEFORE INSERT OR UPDATE ON TABLE_NAME FOR EACH ROW
BEGIN
-- auto increment column
SELECT TABLE_NAME_SEQ.NextVal INTO :New.ID FROM dual;
-- You can also put some other required default data as per need of your columns, for example
SELECT SYS_CONTEXT('USERENV', 'SESSIONID') INTO :New.SessionID FROM dual;
SELECT SYS_CONTEXT('USERENV','SERVER_HOST') INTO :New.HostName FROM dual;
SELECT SYS_CONTEXT('USERENV','OS_USER') INTO :New.LoginID FROM dual;
.
.
.
END;
/
在甲骨文12c以后,你可以这样做,
CREATE TABLE MAPS
(
MAP_ID INTEGER GENERATED ALWAYS AS IDENTITY (START WITH 1 INCREMENT BY 1) NOT NULL,
MAP_NAME VARCHAR(24) NOT NULL,
UNIQUE (MAP_ID, MAP_NAME)
);
在Oracle (Pre 12c)中。
-- create table
CREATE TABLE MAPS
(
MAP_ID INTEGER NOT NULL ,
MAP_NAME VARCHAR(24) NOT NULL,
UNIQUE (MAP_ID, MAP_NAME)
);
-- create sequence
CREATE SEQUENCE MAPS_SEQ;
-- create tigger using the sequence
CREATE OR REPLACE TRIGGER MAPS_TRG
BEFORE INSERT ON MAPS
FOR EACH ROW
WHEN (new.MAP_ID IS NULL)
BEGIN
SELECT MAPS_SEQ.NEXTVAL
INTO :new.MAP_ID
FROM dual;
END;
/
FUNCTION UNIQUE2(
seq IN NUMBER
) RETURN VARCHAR2
AS
i NUMBER := seq;
s VARCHAR2(9);
r NUMBER(2,0);
BEGIN
WHILE i > 0 LOOP
r := MOD( i, 36 );
i := ( i - r ) / 36;
IF ( r < 10 ) THEN
s := TO_CHAR(r) || s;
ELSE
s := CHR( 55 + r ) || s;
END IF;
END LOOP;
RETURN 'ID'||LPAD( s, 14, '0' );
END;
当你想要序列化的数字,任何人都可以很容易地阅读/记忆/理解时,可以使用触发器和序列。但是如果你不想通过这种方式管理ID列(比如emp_id),并且这个列的值不是很可观,你可以在表创建中使用SYS_GUID()来获得像这样的自动递增。
CREATE TABLE <table_name>
(emp_id RAW(16) DEFAULT SYS_GUID() PRIMARY KEY,
name VARCHAR2(30));
现在,emp_id列将接受“全局唯一标识符值”。 您可以通过忽略emp_id列在表中插入值,就像这样。
INSERT INTO <table_name> (name) VALUES ('name value');
因此,它将向emp_id列插入唯一的值。
FUNCTION GETUNIQUEID_2 RETURN VARCHAR2
AS
v_curr_id NUMBER;
v_inc NUMBER;
v_next_val NUMBER;
pragma autonomous_transaction;
begin
CREATE SEQUENCE sequnce
START WITH YYMMDD0000000001
INCREMENT BY 1
NOCACHE
select sequence.nextval into v_curr_id from dual;
if(substr(v_curr_id,0,6)= to_char(sysdate,'yymmdd')) then
v_next_val := to_number(to_char(SYSDATE+1, 'yymmdd') || '0000000000');
v_inc := v_next_val - v_curr_id;
execute immediate ' alter sequence sequence increment by ' || v_inc ;
select sequence.nextval into v_curr_id from dual;
execute immediate ' alter sequence sequence increment by 1';
else
dbms_output.put_line('exception : file not found');
end if;
RETURN 'ID'||v_curr_id;
END;