\n -简单换行符插入工作:

# Here's the test example - string with newline char:
In [36]: test_line = "Hi!!!\n testing first line.. \n testing second line.. \n and third line....."

输出:

In [37]: print(test_line)

Hi!!!
 testing first line..
 testing second line..
 and third line.....

在Python中，你可以只使用换行符，即\n

简单的解决方案

如果只调用print而不带任何参数，它将输出一个空行。

print

你可以像这样将输出管道到一个文件中(考虑到你的例子):

f = open('out.txt', 'w')
print 'First line' >> f
print >> f
print 'Second line' >> f
f.close()

它不仅与操作系统无关(甚至不需要使用操作系统包)，而且比将\n放在字符串中更具可读性。

解释

print()函数有一个可选的关键字参数，用于字符串的结尾，称为end，默认为操作系统的换行符，例如。\ n。所以，当你调用print('hello')时，Python实际上打印的是'hello' + '\n'。这意味着当你只调用print而不带任何参数时，它实际上打印的是" + '\n'，结果是换行符。

替代

使用多行字符串。

s = """First line
    Second line
    Third line"""
f = open('out.txt', 'w')
print s >> f
f.close()

您可以单独写入新行，也可以在单个字符串中写入，这样更容易。

示例1

输入

line1 = "hello how are you"
line2 = "I am testing the new line escape sequence"
line3 = "this seems to work"

你可以把“\n”分开写:

file.write(line1)
file.write("\n")
file.write(line2)
file.write("\n")
file.write(line3)
file.write("\n")

输出

hello how are you
I am testing the new line escape sequence
this seems to work

示例2

输入

正如其他人在之前的回答中指出的那样，将\n放在字符串中的相关点:

line = "hello how are you\nI am testing the new line escape sequence\nthis seems to work"

file.write(line)

输出

hello how are you
I am testing the new line escape sequence
this seems to work

Use:

"{}\n{}\n{}".format(
    "line1",
    "line2",
    "line3"
)

我个人更喜欢这种形式。

\n分隔字符串的行。在下面的示例中，我一直在循环中写入记录。每条记录以\n分隔。

f = open("jsonFile.txt", "w")

for row_index in range(2, sheet.nrows):

  mydict1 = {
    "PowerMeterId" : row_index + 1,
    "Service": "Electricity",
    "Building": "JTC FoodHub",
    "Floor": str(Floor),
    "Location": Location,
    "ReportType": "Electricity",
    "System": System,
    "SubSystem": "",
    "Incomer": "",
    "Category": "",
    "DisplayName": DisplayName,
    "Description": Description,
    "Tag": tag,
    "IsActive": 1,
    "DataProviderType": int(0),
    "DataTable": ""
  }
  mydict1.pop("_id", None)
  f.write(str(mydict1) + '\n')

f.close()