我必须进行REST调用，其中包括自定义头和查询参数。我设置我的HttpEntity只有头(没有正文)，我使用RestTemplate.exchange()方法如下:
HttpHeaders headers = new HttpHeaders();
headers.set("Accept", "application/json");
Map<String, String> params = new HashMap<String, String>();
params.put("msisdn", msisdn);
params.put("email", email);
params.put("clientVersion", clientVersion);
params.put("clientType", clientType);
params.put("issuerName", issuerName);
params.put("applicationName", applicationName);
HttpEntity entity = new HttpEntity(headers);
HttpEntity<String> response = restTemplate.exchange(url, HttpMethod.GET, entity, String.class, params);
这在客户端失败，因为调度程序servlet无法将请求解析到处理程序。调试之后，似乎没有发送请求参数。
当我使用请求体和没有查询参数的POST做一个交换时，它工作得很好。
有人有什么想法吗?
我提供了一个RestTemplate GET方法的代码片段与路径参数示例
public ResponseEntity<String> getName(int id) {
final String url = "http://localhost:8080/springrestexample/employee/name?id={id}";
Map<String, String> params = new HashMap<String, String>();
params.put("id", id);
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity request = new HttpEntity(headers);
ResponseEntity<String> response = restTemplate.exchange(url, HttpMethod.GET, String.class, params);
return response;
}
我也尝试过类似的东西，RoboSpice的例子帮助我解决了这个问题:
HttpHeaders headers = new HttpHeaders();
headers.set("Accept", "application/json");
HttpEntity<String> request = new HttpEntity<>(input, createHeader());
String url = "http://awesomesite.org";
Uri.Builder uriBuilder = Uri.parse(url).buildUpon();
uriBuilder.appendQueryParameter(key, value);
uriBuilder.appendQueryParameter(key, value);
...
String url = uriBuilder.build().toString();
HttpEntity<String> response = restTemplate.exchange(url, HttpMethod.GET, request , String.class);
在Spring Web 4.3.6中我也看到了
public <T> T getForObject(String url, Class<T> responseType, Object... uriVariables)
这意味着你不必创建一个丑陋的地图
如果你有这个url
http://my-url/action?param1={param1}¶m2={param2}
你可以选择
restTemplate.getForObject(url, Response.class, param1, param2)
or
restTemplate.getForObject(url, Response.class, param [])
至少从Spring 3开始，许多RestTemplate方法不是使用UriComponentsBuilder来构建URL(这有点啰嗦)，而是在参数路径中接受占位符(不仅仅是交换)。
从文档中可以看到:
Many of the RestTemplate methods accepts a URI template and URI
template variables, either as a String vararg, or as
Map<String,String>.
For example with a String vararg:
restTemplate.getForObject(
"http://example.com/hotels/{hotel}/rooms/{room}", String.class, "42", "21");
Or with a Map<String, String>:
Map<String, String> vars = new HashMap<>();
vars.put("hotel", "42");
vars.put("room", "21");
restTemplate.getForObject("http://example.com/hotels/{hotel}/rooms/{room}",
String.class, vars);
参考:https://docs.spring.io/spring/docs/current/spring-framework-reference/integration.html # rest-resttemplate-uri
如果你查看JavaDoc for RestTemplate并搜索“URI Template”，你可以看到哪些方法可以使用占位符。
