我扩展了Sujoy的代码来组成一个函数。

/**
 * http://stackoverflow.com/a/10997390/11236
 */
function updateURLParameter(url, param, paramVal){
    var newAdditionalURL = "";
    var tempArray = url.split("?");
    var baseURL = tempArray[0];
    var additionalURL = tempArray[1];
    var temp = "";
    if (additionalURL) {
        tempArray = additionalURL.split("&");
        for (var i=0; i<tempArray.length; i++){
            if(tempArray[i].split('=')[0] != param){
                newAdditionalURL += temp + tempArray[i];
                temp = "&";
            }
        }
    }

    var rows_txt = temp + "" + param + "=" + paramVal;
    return baseURL + "?" + newAdditionalURL + rows_txt;
}

函数调用:

var newURL = updateURLParameter(window.location.href, 'locId', 'newLoc');
newURL = updateURLParameter(newURL, 'resId', 'newResId');

window.history.replaceState('', '', updateURLParameter(window.location.href, "param", "value"));

更新版本，也照顾到URL上的锚。

function updateURLParameter(url, param, paramVal)
{
    var TheAnchor = null;
    var newAdditionalURL = "";
    var tempArray = url.split("?");
    var baseURL = tempArray[0];
    var additionalURL = tempArray[1];
    var temp = "";

    if (additionalURL) 
    {
        var tmpAnchor = additionalURL.split("#");
        var TheParams = tmpAnchor[0];
            TheAnchor = tmpAnchor[1];
        if(TheAnchor)
            additionalURL = TheParams;

        tempArray = additionalURL.split("&");

        for (var i=0; i<tempArray.length; i++)
        {
            if(tempArray[i].split('=')[0] != param)
            {
                newAdditionalURL += temp + tempArray[i];
                temp = "&";
            }
        }        
    }
    else
    {
        var tmpAnchor = baseURL.split("#");
        var TheParams = tmpAnchor[0];
            TheAnchor  = tmpAnchor[1];

        if(TheParams)
            baseURL = TheParams;
    }

    if(TheAnchor)
        paramVal += "#" + TheAnchor;

    var rows_txt = temp + "" + param + "=" + paramVal;
    return baseURL + "?" + newAdditionalURL + rows_txt;
}

没有库，使用URL() WebAPI (https://developer.mozilla.org/en-US/docs/Web/API/URL)

function setURLParameter(url, parameter, value) {
    let url = new URL(url);
    if (url.searchParams.get(parameter) === value) {
        return url;
    }
    url.searchParams.set(parameter, value);
    return url.href;
}

这在IE: https://developer.mozilla.org/en-US/docs/Web/API/URL#Browser_compatibility上不起作用

在这里，我引用了Adil Malik的回答，并修正了我认为的3个问题。

/**
 * Adds or updates a URL parameter.
 *
 * @param {string} url  the URL to modify
 * @param {string} param  the name of the parameter
 * @param {string} paramVal  the new value for the parameter
 * @return {string}  the updated URL
 */
self.setParameter = function (url, param, paramVal){
  // http://stackoverflow.com/a/10997390/2391566
  var parts = url.split('?');
  var baseUrl = parts[0];
  var oldQueryString = parts[1];
  var newParameters = [];
  if (oldQueryString) {
    var oldParameters = oldQueryString.split('&');
    for (var i = 0; i < oldParameters.length; i++) {
      if(oldParameters[i].split('=')[0] != param) {
        newParameters.push(oldParameters[i]);
      }
    }
  }
  if (paramVal !== '' && paramVal !== null && typeof paramVal !== 'undefined') {
    newParameters.push(param + '=' + encodeURI(paramVal));
  }
  if (newParameters.length > 0) {
    return baseUrl + '?' + newParameters.join('&');
  } else {
    return baseUrl;
  }
}

如果您想在地址栏中更改url:

const search = new URLSearchParams(location.search);
search.set('rows', 10);
location.search = search.toString();

注意，改变位置。搜索重新加载页面。

在URLSearchParams文档中，有一种非常干净的方法可以做到这一点，而且不会影响历史堆栈。

// URL: https://example.com?version=1.0
const params = new URLSearchParams(location.search);
params.set('version', 2.0);

window.history.replaceState({}, '', `${location.pathname}?${params}`);
// URL: https://example.com?version=2.0

类似地，删除参数

params.delete('version')
window.history.replaceState({}, '', `${location.pathname}?${params}`);
// URL: https://example.com?

快速的纯js小解决方案，不需要插件:

function replaceQueryParam(param, newval, search) {
    var regex = new RegExp("([?;&])" + param + "[^&;]*[;&]?");
    var query = search.replace(regex, "$1").replace(/&$/, '');

    return (query.length > 2 ? query + "&" : "?") + (newval ? param + "=" + newval : '');
}

这样叫它:

 window.location = '/mypage' + replaceQueryParam('rows', 55, window.location.search)

或者，如果你想保持在同一页上并替换多个参数:

 var str = window.location.search
 str = replaceQueryParam('rows', 55, str)
 str = replaceQueryParam('cols', 'no', str)
 window.location = window.location.pathname + str

Luke:要完全删除参数，为值传递false或null: replaceQueryParam('rows'， false, params)。因为0也是假的，所以指定'0'。