SQL Server支持禁用和启用外键约束吗?还是我唯一的选择就是放弃这些限制,然后重新创造这些限制?
当前回答
最好的选择是DROP和CREATE外键约束。
我在这篇文章中没有找到对我“原样”工作的例子,如果外键引用不同的模式,一个不会工作,如果外键引用多列,另一个也不会工作。这个脚本同时考虑多个模式和每个外键的多个列。
下面是生成“ADD CONSTRAINT”语句的脚本,对于多列,它将用逗号分隔它们(确保在执行DROP语句之前保存此输出):
PRINT N'-- CREATE FOREIGN KEY CONSTRAINTS --';
SET NOCOUNT ON;
SELECT '
PRINT N''Creating '+ const.const_name +'...''
GO
ALTER TABLE ' + const.parent_obj + '
ADD CONSTRAINT ' + const.const_name + ' FOREIGN KEY (
' + const.parent_col_csv + '
) REFERENCES ' + const.ref_obj + '(' + const.ref_col_csv + ')
GO'
FROM (
SELECT QUOTENAME(fk.NAME) AS [const_name]
,QUOTENAME(schParent.NAME) + '.' + QUOTENAME(OBJECT_name(fkc.parent_object_id)) AS [parent_obj]
,STUFF((
SELECT ',' + QUOTENAME(COL_NAME(fcP.parent_object_id, fcp.parent_column_id))
FROM sys.foreign_key_columns AS fcP
WHERE fcp.constraint_object_id = fk.object_id
FOR XML path('')
), 1, 1, '') AS [parent_col_csv]
,QUOTENAME(schRef.NAME) + '.' + QUOTENAME(OBJECT_NAME(fkc.referenced_object_id)) AS [ref_obj]
,STUFF((
SELECT ',' + QUOTENAME(COL_NAME(fcR.referenced_object_id, fcR.referenced_column_id))
FROM sys.foreign_key_columns AS fcR
WHERE fcR.constraint_object_id = fk.object_id
FOR XML path('')
), 1, 1, '') AS [ref_col_csv]
FROM sys.foreign_key_columns AS fkc
INNER JOIN sys.foreign_keys AS fk ON fk.object_id = fkc.constraint_object_id
INNER JOIN sys.objects AS oParent ON oParent.object_id = fkc.parent_object_id
INNER JOIN sys.schemas AS schParent ON schParent.schema_id = oParent.schema_id
INNER JOIN sys.objects AS oRef ON oRef.object_id = fkc.referenced_object_id
INNER JOIN sys.schemas AS schRef ON schRef.schema_id = oRef.schema_id
GROUP BY fkc.parent_object_id
,fkc.referenced_object_id
,fk.NAME
,fk.object_id
,schParent.NAME
,schRef.NAME
) AS const
ORDER BY const.const_name
下面是生成“DROP CONSTRAINT”语句的脚本:
PRINT N'-- DROP FOREIGN KEY CONSTRAINTS --';
SET NOCOUNT ON;
SELECT '
PRINT N''Dropping ' + fk.NAME + '...''
GO
ALTER TABLE [' + sch.NAME + '].[' + OBJECT_NAME(fk.parent_object_id) + ']' + ' DROP CONSTRAINT ' + '[' + fk.NAME + ']
GO'
FROM sys.foreign_keys AS fk
INNER JOIN sys.schemas AS sch ON sch.schema_id = fk.schema_id
ORDER BY fk.NAME
其他回答
最好的选择是DROP和CREATE外键约束。
我在这篇文章中没有找到对我“原样”工作的例子,如果外键引用不同的模式,一个不会工作,如果外键引用多列,另一个也不会工作。这个脚本同时考虑多个模式和每个外键的多个列。
下面是生成“ADD CONSTRAINT”语句的脚本,对于多列,它将用逗号分隔它们(确保在执行DROP语句之前保存此输出):
PRINT N'-- CREATE FOREIGN KEY CONSTRAINTS --';
SET NOCOUNT ON;
SELECT '
PRINT N''Creating '+ const.const_name +'...''
GO
ALTER TABLE ' + const.parent_obj + '
ADD CONSTRAINT ' + const.const_name + ' FOREIGN KEY (
' + const.parent_col_csv + '
) REFERENCES ' + const.ref_obj + '(' + const.ref_col_csv + ')
GO'
FROM (
SELECT QUOTENAME(fk.NAME) AS [const_name]
,QUOTENAME(schParent.NAME) + '.' + QUOTENAME(OBJECT_name(fkc.parent_object_id)) AS [parent_obj]
,STUFF((
SELECT ',' + QUOTENAME(COL_NAME(fcP.parent_object_id, fcp.parent_column_id))
FROM sys.foreign_key_columns AS fcP
WHERE fcp.constraint_object_id = fk.object_id
FOR XML path('')
), 1, 1, '') AS [parent_col_csv]
,QUOTENAME(schRef.NAME) + '.' + QUOTENAME(OBJECT_NAME(fkc.referenced_object_id)) AS [ref_obj]
,STUFF((
SELECT ',' + QUOTENAME(COL_NAME(fcR.referenced_object_id, fcR.referenced_column_id))
FROM sys.foreign_key_columns AS fcR
WHERE fcR.constraint_object_id = fk.object_id
FOR XML path('')
), 1, 1, '') AS [ref_col_csv]
FROM sys.foreign_key_columns AS fkc
INNER JOIN sys.foreign_keys AS fk ON fk.object_id = fkc.constraint_object_id
INNER JOIN sys.objects AS oParent ON oParent.object_id = fkc.parent_object_id
INNER JOIN sys.schemas AS schParent ON schParent.schema_id = oParent.schema_id
INNER JOIN sys.objects AS oRef ON oRef.object_id = fkc.referenced_object_id
INNER JOIN sys.schemas AS schRef ON schRef.schema_id = oRef.schema_id
GROUP BY fkc.parent_object_id
,fkc.referenced_object_id
,fk.NAME
,fk.object_id
,schParent.NAME
,schRef.NAME
) AS const
ORDER BY const.const_name
下面是生成“DROP CONSTRAINT”语句的脚本:
PRINT N'-- DROP FOREIGN KEY CONSTRAINTS --';
SET NOCOUNT ON;
SELECT '
PRINT N''Dropping ' + fk.NAME + '...''
GO
ALTER TABLE [' + sch.NAME + '].[' + OBJECT_NAME(fk.parent_object_id) + ']' + ' DROP CONSTRAINT ' + '[' + fk.NAME + ']
GO'
FROM sys.foreign_keys AS fk
INNER JOIN sys.schemas AS sch ON sch.schema_id = fk.schema_id
ORDER BY fk.NAME
右键单击表设计,进入“关系”,在左侧窗格中选择外键,在右侧窗格中,将强制外键约束设置为“Yes”(启用外键约束)或“No”(禁用外键约束)。
你可以使用以下命令轻松切换CONSTRAINT: 修改表TableName不检查约束所有
完成交易后,不要忘记使用以下方法再次开启: 修改表表名检查约束全部
标记为“905”的答案看起来不错,但不能工作。
下面的方法对我很有效。不能禁用任何主键、唯一键或默认约束。事实上,如果“sp_helpconstraint”在status_enabled中显示“n/a”-意味着它不能被启用/禁用。
生成脚本为DISABLE
select 'ALTER TABLE ' + object_name(id) + ' NOCHECK CONSTRAINT [' + object_name(constid) + ']'
from sys.sysconstraints
where status & 0x4813 = 0x813 order by object_name(id)
——生成脚本以启用
select 'ALTER TABLE ' + object_name(id) + ' CHECK CONSTRAINT [' + object_name(constid) + ']'
from sys.sysconstraints
where status & 0x4813 = 0x813 order by object_name(id)
要禁用约束,您可以使用NOCHECK更改表
ALTER TABLE [TABLE_NAME] NOCHECK CONSTRAINT [ALL|CONSTRAINT_NAME]
要使您必须使用双重检查:
ALTER TABLE [TABLE_NAME] WITH CHECK CHECK CONSTRAINT [ALL|CONSTRAINT_NAME]
启用时请注意双重CHECK CHECK。 ALL表示表中的所有约束。
一旦完成,如果您需要检查状态,使用这个脚本列出约束状态。会很有帮助:
SELECT (CASE
WHEN OBJECTPROPERTY(CONSTID, 'CNSTISDISABLED') = 0 THEN 'ENABLED'
ELSE 'DISABLED'
END) AS STATUS,
OBJECT_NAME(CONSTID) AS CONSTRAINT_NAME,
OBJECT_NAME(FKEYID) AS TABLE_NAME,
COL_NAME(FKEYID, FKEY) AS COLUMN_NAME,
OBJECT_NAME(RKEYID) AS REFERENCED_TABLE_NAME,
COL_NAME(RKEYID, RKEY) AS REFERENCED_COLUMN_NAME
FROM SYSFOREIGNKEYS
ORDER BY TABLE_NAME, CONSTRAINT_NAME,REFERENCED_TABLE_NAME, KEYNO
推荐文章
- 确定记录是否存在的最快方法
- 从现有模式生成表关系图(SQL Server)
- 我如何循环通过一组记录在SQL Server?
- 数据库和模式的区别
- 如何在SQL Server中一次更改多个列
- 外键约束可能导致循环或多条级联路径?
- 如何选择每一行的列值不是独特的
- nvarchar(max)非文本
- 在SQL Server 2008 R2中重命名数据库时出错
- 将数据复制到另一个表中
- 如何在SQL中选择表的最后一条记录?
- 修改列,添加默认约束
- 在存储过程中使用“SET XACT_ABORT ON”有什么好处?
- 如何检查SQL Server文本列是否为空?
- 如何创建一个SQL Server函数“连接”多行从一个子查询到一个单独的分隔字段?