如果我有一个JavaScript对象,如:
var list = {
"you": 100,
"me": 75,
"foo": 116,
"bar": 15
};
是否有一种方法可以根据值对属性进行排序?最后得到
list = {
"bar": 15,
"me": 75,
"you": 100,
"foo": 116
};
如果我有一个JavaScript对象,如:
var list = {
"you": 100,
"me": 75,
"foo": 116,
"bar": 15
};
是否有一种方法可以根据值对属性进行排序?最后得到
list = {
"bar": 15,
"me": 75,
"you": 100,
"foo": 116
};
当前回答
输入是对象,输出是对象,使用lodash & js内置库,降序或升序选项,不改变输入对象
Eg输入输出
{
"a": 1,
"b": 4,
"c": 0,
"d": 2
}
{
"b": 4,
"d": 2,
"a": 1,
"c": 0
}
实现
const _ = require('lodash');
const o = { a: 1, b: 4, c: 0, d: 2 };
function sortByValue(object, descending = true) {
const { max, min } = Math;
const selector = descending ? max : min;
const objects = [];
const cloned = _.clone(object);
while (!_.isEmpty(cloned)) {
const selectedValue = selector(...Object.values(cloned));
const [key, value] = Object.entries(cloned).find(([, value]) => value === selectedValue);
objects.push({ [key]: value });
delete cloned[key];
}
return _.merge(...objects);
}
const o2 = sortByValue(o);
console.log(JSON.stringify(o2, null, 2));
其他回答
以防万一,有人正在寻找保持对象(键和值),使用@Markus R和@James Moran注释的代码引用,只需使用:
var list = {"you": 100, "me": 75, "foo": 116, "bar": 15};
var newO = {};
Object.keys(list).sort(function(a,b){return list[a]-list[b]})
.map(key => newO[key] = list[key]);
console.log(newO); // {bar: 15, me: 75, you: 100, foo: 116}
非常简短简单!
var sortedList = {};
Object.keys(list).sort((a,b) => list[a]-list[b]).forEach((key) => {
sortedList[key] = list[key]; });
打印稿
下面的函数根据值或值的属性对对象进行排序。如果你不使用TypeScript,你可以删除类型信息,将其转换为JavaScript。
/**
* Represents an associative array of a same type.
*/
interface Dictionary<T> {
[key: string]: T;
}
/**
* Sorts an object (dictionary) by value or property of value and returns
* the sorted result as a Map object to preserve the sort order.
*/
function sort<TValue>(
obj: Dictionary<TValue>,
valSelector: (val: TValue) => number | string,
) {
const sortedEntries = Object.entries(obj)
.sort((a, b) =>
valSelector(a[1]) > valSelector(b[1]) ? 1 :
valSelector(a[1]) < valSelector(b[1]) ? -1 : 0);
return new Map(sortedEntries);
}
使用
var list = {
"one": { height: 100, weight: 15 },
"two": { height: 75, weight: 12 },
"three": { height: 116, weight: 9 },
"four": { height: 15, weight: 10 },
};
var sortedMap = sort(list, val => val.height);
JavaScript对象中键的顺序是不保证的,所以我将排序并将结果返回为一个保留排序顺序的Map对象。
如果你想把它转换回Object,你可以这样做:
var sortedObj = {} as any;
sortedMap.forEach((v,k) => { sortedObj[k] = v });
输入是对象,输出是对象,使用lodash & js内置库,降序或升序选项,不改变输入对象
Eg输入输出
{
"a": 1,
"b": 4,
"c": 0,
"d": 2
}
{
"b": 4,
"d": 2,
"a": 1,
"c": 0
}
实现
const _ = require('lodash');
const o = { a: 1, b: 4, c: 0, d: 2 };
function sortByValue(object, descending = true) {
const { max, min } = Math;
const selector = descending ? max : min;
const objects = [];
const cloned = _.clone(object);
while (!_.isEmpty(cloned)) {
const selectedValue = selector(...Object.values(cloned));
const [key, value] = Object.entries(cloned).find(([, value]) => value === selectedValue);
objects.push({ [key]: value });
delete cloned[key];
}
return _.merge(...objects);
}
const o2 = sortByValue(o);
console.log(JSON.stringify(o2, null, 2));
这是获取排序对象和返回排序对象的方法
let sortedObject = {}
sortedObject = Object.keys(yourObject).sort((a, b) => {
return yourObject[a] - yourObject[b]
}).reduce((prev, curr, i) => {
prev[i] = yourObject[curr]
return prev
}, {});
您可以根据您的需求自定义排序功能