如果我有一个JavaScript对象,如:
var list = {
"you": 100,
"me": 75,
"foo": 116,
"bar": 15
};
是否有一种方法可以根据值对属性进行排序?最后得到
list = {
"bar": 15,
"me": 75,
"you": 100,
"foo": 116
};
如果我有一个JavaScript对象,如:
var list = {
"you": 100,
"me": 75,
"foo": 116,
"bar": 15
};
是否有一种方法可以根据值对属性进行排序?最后得到
list = {
"bar": 15,
"me": 75,
"you": 100,
"foo": 116
};
当前回答
输入是对象,输出是对象,使用lodash & js内置库,降序或升序选项,不改变输入对象
Eg输入输出
{
"a": 1,
"b": 4,
"c": 0,
"d": 2
}
{
"b": 4,
"d": 2,
"a": 1,
"c": 0
}
实现
const _ = require('lodash');
const o = { a: 1, b: 4, c: 0, d: 2 };
function sortByValue(object, descending = true) {
const { max, min } = Math;
const selector = descending ? max : min;
const objects = [];
const cloned = _.clone(object);
while (!_.isEmpty(cloned)) {
const selectedValue = selector(...Object.values(cloned));
const [key, value] = Object.entries(cloned).find(([, value]) => value === selectedValue);
objects.push({ [key]: value });
delete cloned[key];
}
return _.merge(...objects);
}
const o2 = sortByValue(o);
console.log(JSON.stringify(o2, null, 2));
其他回答
function sortObjByValue(list){
var sortedObj = {}
Object.keys(list)
.map(key => [key, list[key]])
.sort((a,b) => a[1] > b[1] ? 1 : a[1] < b[1] ? -1 : 0)
.forEach(data => sortedObj[data[0]] = data[1]);
return sortedObj;
}
sortObjByValue(list);
Github Gist Link
如果我有一个这样的对象,
var dayObj = {
"Friday":["5:00pm to 12:00am"] ,
"Wednesday":["5:00pm to 11:00pm"],
"Sunday":["11:00am to 11:00pm"],
"Thursday":["5:00pm to 11:00pm"],
"Saturday":["11:00am to 12:00am"]
}
我想按天排序,
我们应该先有daySorterMap,
var daySorterMap = {
// "sunday": 0, // << if sunday is first day of week
"Monday": 1,
"Tuesday": 2,
"Wednesday": 3,
"Thursday": 4,
"Friday": 5,
"Saturday": 6,
"Sunday": 7
}
初始化一个单独的对象sortedDayObj,
var sortedDayObj={};
Object.keys(dayObj)
.sort((a,b) => daySorterMap[a] - daySorterMap[b])
.forEach(value=>sortedDayObj[value]= dayObj[value])
你可以返回sortedDayObj
我已经用自己的方式尝试过了
var maxSpeed = {
car: 300,
bike: 60,
motorbike: 200,
airplane: 1000,
helicopter: 400,
rocket: 8 * 60 * 60
};
var sorted = {}
Object.keys(maxSpeed).sort ((a,b) => maxSpeed[a] - maxSpeed[b]).map(item => sorted[item] = maxSpeed[item]);
console.log(sorted)
以防万一,有人正在寻找保持对象(键和值),使用@Markus R和@James Moran注释的代码引用,只需使用:
var list = {"you": 100, "me": 75, "foo": 116, "bar": 15};
var newO = {};
Object.keys(list).sort(function(a,b){return list[a]-list[b]})
.map(key => newO[key] = list[key]);
console.log(newO); // {bar: 15, me: 75, you: 100, foo: 116}
ES6更新:如果你关心的是有一个排序的对象来迭代(这就是为什么我想象你想要你的对象属性排序),你可以使用Map对象。
您可以按顺序插入(key, value)对,然后执行for..of循环将确保它们按照您插入它们的顺序进行循环
var myMap = new Map();
myMap.set(0, "zero");
myMap.set(1, "one");
for (var [key, value] of myMap) {
console.log(key + " = " + value);
}
// 0 = zero
// 1 = one