如何在PHP中获得每月的最后一天?
考虑到:
$a_date = "2009-11-23"
我想要2009-11-30;鉴于
$a_date = "2009-12-23"
我要2009-12-31。
如何在PHP中获得每月的最后一天?
考虑到:
$a_date = "2009-11-23"
我想要2009-11-30;鉴于
$a_date = "2009-12-23"
我要2009-12-31。
当前回答
2行代码,你就完成了:
$oDate = new DateTime("2019-11-23");
// now your date object has been updated with last day of month
$oDate->setDate($oDate->format("Y"),$oDate->format("m"),$oDate->format("t"));
// or to just echo you can skip the above line using this
echo $oDate->format("Y-m-t");
其他回答
2行代码,你就完成了:
$oDate = new DateTime("2019-11-23");
// now your date object has been updated with last day of month
$oDate->setDate($oDate->format("Y"),$oDate->format("m"),$oDate->format("t"));
// or to just echo you can skip the above line using this
echo $oDate->format("Y-m-t");
这应该可以工作:
$week_start = strtotime('last Sunday', time());
$week_end = strtotime('next Sunday', time());
$month_start = strtotime('first day of this month', time());
$month_end = strtotime('last day of this month', time());
$year_start = strtotime('first day of January', time());
$year_end = strtotime('last day of December', time());
echo date('D, M jS Y', $week_start).'<br/>';
echo date('D, M jS Y', $week_end).'<br/>';
echo date('D, M jS Y', $month_start).'<br/>';
echo date('D, M jS Y', $month_end).'<br/>';
echo date('D, M jS Y', $year_start).'<br/>';
echo date('D, M jS Y', $year_end).'<br/>';
如果你知道一个月的最后一天,
public function getLastDateOfMonth($month)
{
$date = date('Y').'-'.$month.'-01'; //make date of month
return date('t', strtotime($date));
}
$this->getLastDateOfMonth(01); //31
我需要下个月的最后一天,也许有人会需要它:
echo date("Y-m-t", strtotime("next month")); //is 2020-08-13, return 2020-09-30
您也可以将它与datetime一起使用
$date = new \DateTime();
$nbrDay = $date->format('t');
$lastDay = $date->format('Y-m-t');