我需要找到并提取字符串中包含的数字。

例如,从这些字符串:

string test = "1 test"
string test1 = " 1 test"
string test2 = "test 99"

我该怎么做呢?


当前回答

下面是Linq版本:

string s = "123iuow45ss";
var getNumbers = (from t in s
                  where char.IsDigit(t)
                  select t).ToArray();
Console.WriteLine(new string(getNumbers));

其他回答

我使用这个一行程序从任何字符串中提取所有数字。

var phoneNumber = "(555)123-4567";
var numsOnly = string.Join("", new Regex("[0-9]").Matches(phoneNumber)); // 5551234567

基于上一个示例,我创建了一个方法:

private string GetNumberFromString(string sLongString, int iLimitNumbers)
{
    string sReturn = "NA";
    int iNumbersCounter = 0;
    int iCharCounter = 0; 

    string sAlphaChars = string.Empty;
    string sNumbers = string.Empty;
    foreach (char str in sLongString)
    {
        if (char.IsDigit(str))
        {
            sNumbers += str.ToString();
            iNumbersCounter++;
            if (iNumbersCounter == iLimitNumbers)
            {
                return sReturn = sNumbers;
            }
        }
        else
        {
            sAlphaChars += str.ToString();
            iCharCounter++;
            // reset the counter 
            iNumbersCounter = 0; 
        }
    }
    return sReturn;
}

获取字符串中包含的所有正数的扩展方法:

    public static List<long> Numbers(this string str)
    {
        var nums = new List<long>();
        var start = -1;
        for (int i = 0; i < str.Length; i++)
        {
            if (start < 0 && Char.IsDigit(str[i]))
            {
                start = i;
            }
            else if (start >= 0 && !Char.IsDigit(str[i]))
            {
                nums.Add(long.Parse(str.Substring(start, i - start)));
                start = -1;
            }
        }
        if (start >= 0)
            nums.Add(long.Parse(str.Substring(start, str.Length - start)));
        return nums;
    }

如果你也想要负数,只需修改这段代码来处理负号(-)

假设输入如下:

"I was born in 1989, 27 years ago from now (2016)"

得到的数字列表将是:

[1989, 27, 2016]

你也可以试试这个

string.Join(null,System.Text.RegularExpressions.Regex.Split(expr, "[^\\d]"));
var match=Regex.Match(@"a99b",@"\d+");
if(match.Success)
{
    int val;
    if(int.TryParse(match.Value,out val))
    {
        //val is set
    }
}