当在Iterable上使用外部迭代时，我们使用break或return from enhanced for-each循环，如下:
for (SomeObject obj : someObjects) {
if (some_condition_met) {
break; // or return obj
}
}
如何在Java 8 lambda表达式中使用内部迭代中断或返回:
someObjects.forEach(obj -> {
//what to do here?
})
当前回答
我建议使用anyMatch。例子:-
return someObjects.stream().anyMatch(obj ->
some_condition_met;
);
你可以参考这篇文章来理解anyMatch:- https://beginnersbook.com/2017/11/java-8-stream-anymatch-example/
其他回答
int valueToMatch = 7;
Stream.of(1,2,3,4,5,6,7,8).anyMatch(val->{
boolean isMatch = val == valueToMatch;
if(isMatch) {
/*Do whatever you want...*/
System.out.println(val);
}
return isMatch;
});
它只会在找到匹配的地方执行操作，在找到匹配后停止迭代。
您可以使用java8 + rxjava。
//import java.util.stream.IntStream;
//import rx.Observable;
IntStream intStream = IntStream.range(1,10000000);
Observable.from(() -> intStream.iterator())
.takeWhile(n -> n < 10)
.forEach(n-> System.out.println(n));
lambda中的return等于for-each中的continue，但不等同于break。你可以直接返回继续:
someObjects.forEach(obj -> {
if (some_condition_met) {
return;
}
})
更新到Java 9+与takeWhile:
MutableBoolean ongoing = MutableBoolean.of(true);
someobjects.stream()...takeWhile(t -> ongoing.value()).forEach(t -> {
// doing something.
if (...) { // want to break;
ongoing.setFalse();
}
});
我建议使用anyMatch。例子:-
return someObjects.stream().anyMatch(obj ->
some_condition_met;
);
你可以参考这篇文章来理解anyMatch:- https://beginnersbook.com/2017/11/java-8-stream-anymatch-example/
