我能够通过使用一个sql查询检索具有相应列的表名，但列输出是逗号分隔的。我希望它能帮助到一些人

SELECT tbl_name, (SELECT GROUP_CONCAT(name, ',') FROM PRAGMA_TABLE_INFO(tbl_name)) as columns FROM sqlite_schema WHERE type = 'table';

如果您正在搜索任何特定的列，您可以使用Like语句

ex:

SELECT * FROM sqlite_master where sql like('%LAST%')

在Python中使用sqlite3

顶部答案PRAGMA table_info()返回一个元组列表，可能不适合进一步处理，例如:

[(0, 'id', 'INTEGER', 0, None, 0),
 (1, 'name', 'TEXT', 0, None, 0),
 (2, 'age', 'INTEGER', 0, None, 0),
 (3, 'profession', 'TEXT', 0, None, 0)]

在Python中使用sqlite3时，只需在最后添加一个列表推导式，以过滤掉不需要的信息。

import sqlite3 as sq

def col_names(t_name):
    with sq.connect('file:{}.sqlite?mode=ro'.format(t_name),uri=True) as conn:
        cursor = conn.cursor()
        cursor.execute("PRAGMA table_info({}) ".format(t_name))
        data = cursor.fetchall()
        return [i[1] for i in data]

col_names("your_table_name")

结果

["id","name","age","profession"]

免责声明:请勿在生产环境中使用，因为此代码段可能会受到SQL注入的影响!

function getDetails(){
var data = [];
dBase.executeSql("PRAGMA table_info('table_name') ", [], function(rsp){
    if(rsp.rows.length > 0){
        for(var i=0; i<rsp.rows.length; i++){
            var o = {
                name: rsp.rows.item(i).name,
                type: rsp.rows.item(i).type
            } 
            data.push(o);
        }
    }
    alert(rsp.rows.item(0).name);

},function(error){
    alert(JSON.stringify(error));
});             
}

获取一个表和列的列表作为视图:

CREATE VIEW Table_Columns AS
SELECT m.tbl_name AS TableView_Name, m.type AS TableView, cid+1 AS Column, p.*
FROM sqlite_master m, Pragma_Table_Info(m.tbl_name) p
WHERE m.type IN ('table', 'view') AND
   ( m.tbl_name = 'mypeople' OR m.tbl_name LIKE 'US_%')   -- filter tables
ORDER BY m.tbl_name;

-(NSMutableDictionary*)tableInfo:(NSString *)table
{
  sqlite3_stmt *sqlStatement;
  NSMutableDictionary *result = [[NSMutableDictionary alloc] init];
  const char *sql = [[NSString stringWithFormat:@"pragma table_info('%s')",[table UTF8String]] UTF8String];
  if(sqlite3_prepare(db, sql, -1, &sqlStatement, NULL) != SQLITE_OK)
  {
    NSLog(@"Problem with prepare statement tableInfo %@",[NSString stringWithUTF8String:(const char *)sqlite3_errmsg(db)]);

  }
  while (sqlite3_step(sqlStatement)==SQLITE_ROW)
  {
    [result setObject:@"" forKey:[NSString stringWithUTF8String:(char*)sqlite3_column_text(sqlStatement, 1)]];

  }

  return result;
  }