有没有什么简单的方法来实现APT(高级包工具)命令行界面在Python中的作用?
我的意思是,当包管理器提示一个yes/no问题,后面跟着[yes/no]时,脚本接受yes/ Y/yes/ Y或Enter(默认为yes,由大写字母提示)。
我在官方文档中唯一找到的是input和raw_input…
我知道模仿它并不难,但是重写:|很烦人
有没有什么简单的方法来实现APT(高级包工具)命令行界面在Python中的作用?
我的意思是,当包管理器提示一个yes/no问题,后面跟着[yes/no]时,脚本接受yes/ Y/yes/ Y或Enter(默认为yes,由大写字母提示)。
我在官方文档中唯一找到的是input和raw_input…
我知道模仿它并不难,但是重写:|很烦人
当前回答
def question(question, answers):
acceptable = False
while not acceptable:
print(question + "specify '%s' or '%s'") % answers
answer = raw_input()
if answer.lower() == answers[0].lower() or answers[0].lower():
print('Answer == %s') % answer
acceptable = True
return answer
raining = question("Is it raining today?", ("Y", "N"))
换做是我就会这么做。
输出
Is it raining today? Specify 'Y' or 'N'
> Y
answer = 'Y'
其他回答
您可以使用单击的确认方法。
import click
if click.confirm('Do you want to continue?', default=True):
print('Do something')
这将打印:
$ Do you want to continue? [Y/n]:
应该适用于Linux, Mac或Windows上的Python 2/3。
文档:http://click.pocoo.org/5/prompts/ # confirmation-prompts
我会这样做:
# raw_input returns the empty string for "enter"
yes = {'yes','y', 'ye', ''}
no = {'no','n'}
choice = raw_input().lower()
if choice in yes:
return True
elif choice in no:
return False
else:
sys.stdout.write("Please respond with 'yes' or 'no'")
正如Alexander Artemenko提到的,这里有一个使用strtobool()的简单解决方案。
from distutils.util import strtobool
def user_yes_no_query(question):
sys.stdout.write('%s [y/n]\n' % question)
while True:
try:
return strtobool(raw_input().lower())
except ValueError:
sys.stdout.write('Please respond with \'y\' or \'n\'.\n')
使用
>>> user_yes_no_query('Do you like cheese?')
Do you like cheese? [y/n]
Only on tuesdays
Please respond with 'y' or 'n'.
ok
Please respond with 'y' or 'n'.
y
>>> True
Python x.x
res = True
while res:
res = input("Please confirm with y/yes...").lower(); res = res not in {'y','yes','Y','YES',''}
我修改了fmark的答案,用python 2/3兼容更pythonic。
如果您对更多错误处理感兴趣,请参阅ipython的实用程序模块
# PY2/3 compatibility
from __future__ import print_function
# You could use the six package for this
try:
input_ = raw_input
except NameError:
input_ = input
def query_yes_no(question, default=True):
"""Ask a yes/no question via standard input and return the answer.
If invalid input is given, the user will be asked until
they acutally give valid input.
Args:
question(str):
A question that is presented to the user.
default(bool|None):
The default value when enter is pressed with no value.
When None, there is no default value and the query
will loop.
Returns:
A bool indicating whether user has entered yes or no.
Side Effects:
Blocks program execution until valid input(y/n) is given.
"""
yes_list = ["yes", "y"]
no_list = ["no", "n"]
default_dict = { # default => prompt default string
None: "[y/n]",
True: "[Y/n]",
False: "[y/N]",
}
default_str = default_dict[default]
prompt_str = "%s %s " % (question, default_str)
while True:
choice = input_(prompt_str).lower()
if not choice and default is not None:
return default
if choice in yes_list:
return True
if choice in no_list:
return False
notification_str = "Please respond with 'y' or 'n'"
print(notification_str)