我试图做POST与HttpURLConnection(我需要使用这种方式,不能使用HttpPost),我想添加参数的连接,如

post.setEntity(new UrlEncodedFormEntity(nvp));

在哪里

nvp = new ArrayList<NameValuePair>();

有一些数据存储在。我找不到一种方法如何添加这个数组列表到我的HttpURLConnection在这里:

HttpsURLConnection https = (HttpsURLConnection) url.openConnection();
https.setHostnameVerifier(DO_NOT_VERIFY);
http = https;
http.setRequestMethod("POST");
http.setDoInput(true);
http.setDoOutput(true);

出现这种尴尬的https和http组合的原因是不需要验证证书。不过,这不是问题,它可以很好地发布服务器。但我需要它来张贴论点。

什么好主意吗?


重复的免责声明:

早在2012年,我还不知道如何在HTTP POST请求中插入参数。我一直在使用NameValuePair,因为它在教程中。这个问题可能看起来像一个重复的问题,然而,我2012年自己读了另一个问题,它没有使用NameValuePair。事实上,这并没有解决我的问题。


当前回答

因为NameValuePair已弃用。想过分享我的代码

public String  performPostCall(String requestURL,
            HashMap<String, String> postDataParams) {

        URL url;
        String response = "";
        try {
            url = new URL(requestURL);

            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            conn.setReadTimeout(15000);
            conn.setConnectTimeout(15000);
            conn.setRequestMethod("POST");
            conn.setDoInput(true);
            conn.setDoOutput(true);


            OutputStream os = conn.getOutputStream();
            BufferedWriter writer = new BufferedWriter(
                    new OutputStreamWriter(os, "UTF-8"));
            writer.write(getPostDataString(postDataParams));

            writer.flush();
            writer.close();
            os.close();
            int responseCode=conn.getResponseCode();

            if (responseCode == HttpsURLConnection.HTTP_OK) {
                String line;
                BufferedReader br=new BufferedReader(new InputStreamReader(conn.getInputStream()));
                while ((line=br.readLine()) != null) {
                    response+=line;
                }
            }
            else {
                response="";

            }
        } catch (Exception e) {
            e.printStackTrace();
        }

        return response;
    }

....

  private String getPostDataString(HashMap<String, String> params) throws UnsupportedEncodingException{
        StringBuilder result = new StringBuilder();
        boolean first = true;
        for(Map.Entry<String, String> entry : params.entrySet()){
            if (first)
                first = false;
            else
                result.append("&");

            result.append(URLEncoder.encode(entry.getKey(), "UTF-8"));
            result.append("=");
            result.append(URLEncoder.encode(entry.getValue(), "UTF-8"));
        }

        return result.toString();
    }

其他回答

一个解决方案是让你自己的params字符串。

这是我在我的最新项目中使用的实际方法。你需要将args从hashtable更改为namevaluepair:

private static String getPostParamString(Hashtable<String, String> params) {
    if(params.size() == 0)
        return "";

    StringBuffer buf = new StringBuffer();
    Enumeration<String> keys = params.keys();
    while(keys.hasMoreElements()) {
        buf.append(buf.length() == 0 ? "" : "&");
        String key = keys.nextElement();
        buf.append(key).append("=").append(params.get(key));
    }
    return buf.toString();
}

发布参数:

OutputStreamWriter writer = new OutputStreamWriter(conn.getOutputStream());
writer.write(getPostParamString(req.getPostParams()));

我使用的方法是这样的:

SchemeRegistry sR = new SchemeRegistry();
sR.register(new Scheme("https", SSLSocketFactory.getSocketFactory(), 443));

HttpParams params = new BasicHttpParams();
SingleClientConnManager mgr = new SingleClientConnManager(params, sR);

HttpClient httpclient = new DefaultHttpClient(mgr, params);

HttpPost httppost = new HttpPost(url);
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

HttpResponse response = httpclient.execute(httppost);

使用PrintWriter有一个更简单的方法(见这里)

基本上你所需要的是:

// set up URL connection
URL urlToRequest = new URL(urlStr);
HttpURLConnection urlConnection = (HttpURLConnection)urlToRequest.openConnection();
urlConnection.setDoOutput(true);
urlConnection.setRequestMethod("POST");
urlConnection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");

// write out form parameters
String postParamaters = "param1=value1&param2=value2"
urlConnection.setFixedLengthStreamingMode(postParameters.getBytes().length);
PrintWriter out = new PrintWriter(urlConnection.getOutputStream());
out.print(postParameters);
out.close();

// connect
urlConnection.connect();

如果你不需要ArrayList<NameValuePair>作为参数,这是一个更短的解决方案,它使用Uri构建查询字符串。建筑类:

URL url = new URL("http://yoururl.com");
HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
conn.setReadTimeout(10000);
conn.setConnectTimeout(15000);
conn.setRequestMethod("POST");
conn.setDoInput(true);
conn.setDoOutput(true);

Uri.Builder builder = new Uri.Builder()
        .appendQueryParameter("firstParam", paramValue1)
        .appendQueryParameter("secondParam", paramValue2)
        .appendQueryParameter("thirdParam", paramValue3);
String query = builder.build().getEncodedQuery();

OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
            new OutputStreamWriter(os, "UTF-8"));
writer.write(query);
writer.flush();
writer.close();
os.close();

conn.connect();
JSONObject params = new JSONObject();
try {
   params.put(key, val);
}catch (JSONException e){
   e.printStackTrace();
}

这就是我如何通过POST传递“params”(JSONObject)

connection.getOutputStream().write(params.toString().getBytes("UTF-8"));