对于某个Hibernate实体,我们需要存储它的创建时间和最后一次更新时间。你会怎么设计呢?

您将在数据库中使用什么数据类型(假设MySQL,可能位于与JVM不同的时区)?数据类型是否支持时区? 你会在Java中使用什么数据类型(日期,日历,长,…)? 您会让谁负责设置时间戳——数据库、ORM框架(Hibernate)还是应用程序程序员? 你会为映射使用什么注释(例如@Temporal)?

我不仅在寻找一个可行的解决方案,而且在寻找一个安全、设计良好的解决方案。


当前回答

如果我们在方法中使用@Transactional, @CreationTimestamp和@UpdateTimestamp将值保存在DB中,但在使用save(…)后将返回null。

在这种情况下,使用saveAndFlush(…)达到了目的

其他回答

如果你正在使用JPA注释,你可以使用@PrePersist和@PreUpdate事件钩子来做到这一点:

@Entity
@Table(name = "entities")    
public class Entity {
  ...

  private Date created;
  private Date updated;

  @PrePersist
  protected void onCreate() {
    created = new Date();
  }

  @PreUpdate
  protected void onUpdate() {
    updated = new Date();
  }
}

或者您可以在类上使用@EntityListener注释,并将事件代码放在外部类中。

只是强调一下:java.util. calendar不是用于时间戳的。date是指时间上的某一刻,不受时区等区域性事物的影响。大多数数据库以这种方式存储数据(即使它们看起来不是这样;这通常是客户端软件中的时区设置;数据是好的)

如果我们在方法中使用@Transactional, @CreationTimestamp和@UpdateTimestamp将值保存在DB中,但在使用save(…)后将返回null。

在这种情况下,使用saveAndFlush(…)达到了目的

你可以使用@CreationTimestamp和@UpdateTimestamp:

@CreationTimestamp
@Temporal(TemporalType.TIMESTAMP)
@Column(name = "create_date")
private Date createDate;

@UpdateTimestamp
@Temporal(TemporalType.TIMESTAMP)
@Column(name = "modify_date")
private Date modifyDate;

谢谢所有帮助过我的人。在我自己做了一些研究之后(我是问这个问题的人),以下是我发现最有意义的:

Database column type: the timezone-agnostic number of milliseconds since 1970 represented as decimal(20) because 2^64 has 20 digits and disk space is cheap; let's be straightforward. Also, I will use neither DEFAULT CURRENT_TIMESTAMP, nor triggers. I want no magic in the DB. Java field type: long. The Unix timestamp is well supported across various libs, long has no Y2038 problems, timestamp arithmetic is fast and easy (mainly operator < and operator +, assuming no days/months/years are involved in the calculations). And, most importantly, both primitive longs and java.lang.Longs are immutable—effectively passed by value—unlike java.util.Dates; I'd be really pissed off to find something like foo.getLastUpdate().setTime(System.currentTimeMillis()) when debugging somebody else's code. The ORM framework should be responsible for filling in the data automatically. I haven't tested this yet, but only looking at the docs I assume that @Temporal will do the job; not sure about whether I might use @Version for this purpose. @PrePersist and @PreUpdate are good alternatives to control that manually. Adding that to the layer supertype (common base class) for all entities, is a cute idea provided that you really want timestamping for all of your entities.