我怎么能，使用Javascript，使一个函数，将修剪字符串传递作为参数，到指定的长度，也作为参数传递。例如:
var string = "this is a string";
var length = 6;
var trimmedString = trimFunction(length, string);
// trimmedString should be:
// "this is"
有人有想法吗?我听说过一些关于使用子字符串，但不太明白。
当前回答
https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/String/substr
从链接:
string.substr(start[, length])
其他回答
let trimString = function (string, length) {
return string.length > length ?
string.substring(0, length) + '...' :
string;
};
用例,
let string = 'How to trim a string to N chars in Javascript';
trimString(string, 20);
//How to trim a string...
只是另一个建议，删除任何尾随空白
limitStrLength = (text, max_length) => {
if(text.length > max_length - 3){
return text.substring(0, max_length).trimEnd() + "..."
}
else{
return text
}
为什么不直接使用substring…字符串。substring(0、7);第一个参数(0)是起点。第二个参数(7)是结束点(独占)。更多信息请点击这里。
var string = "this is a string";
var length = 7;
var trimmedString = string.substring(0, length);
我认为你应该使用这个代码:-)
// sample string
const param= "Hi you know anybody like pizaa";
// You can change limit parameter(up to you)
const checkTitle = (str, limit = 17) => {
var newTitle = [];
if (param.length >= limit) {
param.split(" ").reduce((acc, cur) => {
if (acc + cur.length <= limit) {
newTitle.push(cur);
}
return acc + cur.length;
}, 0);
return `${newTitle.join(" ")} ...`;
}
return param;
};
console.log(checkTitle(str));
// result : Hi you know anybody ...
首选String.prototype.slice而不是String.prototype.substring方法(在substring中，在某些情况下它给出的结果与您期望的结果不同)。
从左到右修剪字符串:
const str = "123456789";
result = str.slice(0,5); // "12345", extracts first 5 characters
result = str.substring(0,5); // "12345"
startIndex > endIndex:
result = str.slice(5,0); // "", empty string
result = str.substring(5,0); // "12345" , swaps start & end indexes => str.substring(0,5)
从右到左修剪字符串:(-ve start index)
result = str.slice(-3); // "789", extracts last 3 characters
result = str.substring(-3); // "123456789" , -ve becomes 0 => str.substring(0)
result = str.substring(str.length - 3); // "789"
