Angular确实在HTML指令中提供了一些使用数字的for循环的支持:
<div data-ng-repeat="i in [1,2,3,4,5]">
do something
</div>
但是，如果作用域变量包含一个具有动态数字的范围，那么每次都需要创建一个空数组。
在控制器中
var range = [];
for(var i=0;i<total;i++) {
range.push(i);
}
$scope.range = range;
在HTML中
<div data-ng-repeat="i in range">
do something
</div>
这是可行的，但这是不必要的，因为我们在循环中根本不会使用范围数组。有人知道设置最小/最大值的范围或规则吗?
喜欢的东西:
<div data-ng-repeat="i in 1 .. 100">
do something
</div>
当前回答
最简单的无代码解决方案是初始化一个数组的范围，并使用$index +无论多少我想通过偏移:
<select ng-init="(_Array = []).length = 5;">
<option ng-repeat="i in _Array track by $index">{{$index+5}}</option>
</select>
其他回答
我使用自定义ng-repeat-range指令:
/**
* Ng-Repeat implementation working with number ranges.
*
* @author Umed Khudoiberdiev
*/
angular.module('commonsMain').directive('ngRepeatRange', ['$compile', function ($compile) {
return {
replace: true,
scope: { from: '=', to: '=', step: '=' },
link: function (scope, element, attrs) {
// returns an array with the range of numbers
// you can use _.range instead if you use underscore
function range(from, to, step) {
var array = [];
while (from + step <= to)
array[array.length] = from += step;
return array;
}
// prepare range options
var from = scope.from || 0;
var step = scope.step || 1;
var to = scope.to || attrs.ngRepeatRange;
// get range of numbers, convert to the string and add ng-repeat
var rangeString = range(from, to + 1, step).join(',');
angular.element(element).attr('ng-repeat', 'n in [' + rangeString + ']');
angular.element(element).removeAttr('ng-repeat-range');
$compile(element)(scope);
}
};
}]);
HTML代码是
<div ng-repeat-range from="0" to="20" step="5">
Hello 4 times!
</div>
或者简单地
<div ng-repeat-range from="5" to="10">
Hello 5 times!
</div>
或者简单地说
<div ng-repeat-range to="3">
Hello 3 times!
</div>
或者只是
<div ng-repeat-range="7">
Hello 7 times!
</div>
只有简单的Javascript(你甚至不需要一个控制器):
<div ng-repeat="n in [].constructor(10) track by $index">
{{ $index }}
</div>
在模拟时非常有用
这是jzm改进后的答案(我不能评论，否则我会评论她/他的答案，因为她/他包含错误)。 函数有一个开始/结束范围值，所以它更灵活，而且……它的工作原理。这个特殊的例子是在一个月的某一天:
$scope.rangeCreator = function (minVal, maxVal) {
var arr = [];
for (var i = minVal; i <= maxVal; i++) {
arr.push(i);
}
return arr;
};
<div class="col-sm-1">
<select ng-model="monthDays">
<option ng-repeat="day in rangeCreator(1,31)">{{day}}</option>
</select>
</div>
@Mormegil的解决方案的改进
app.filter('makeRange', function() {
return function(inp) {
var range = [+inp[1] && +inp[0] || 0, +inp[1] || +inp[0]];
var min = Math.min(range[0], range[1]);
var max = Math.max(range[0], range[1]);
var result = [];
for (var i = min; i <= max; i++) result.push(i);
if (range[0] > range[1]) result.reverse();
return result;
};
});
使用
<span ng-repeat="n in [3, -3] | makeRange" ng-bind="n"></span>
Three, two, one, zero, one, two, three
<span ng-repeat="n in [-3, 3] | makeRange" ng-bind="n"></span>
Minus 3, minus 2, minus 1, 0, 1, 2, 3
<span ng-repeat="n in [3] | makeRange" ng-bind="n"></span>
0, 1, 2, 3
<span ng-repeat="n in [-3] | makeRange" ng-bind="n"></span>
0-1-2-3
最简单的无代码解决方案是初始化一个数组的范围，并使用$index +无论多少我想通过偏移:
<select ng-init="(_Array = []).length = 5;">
<option ng-repeat="i in _Array track by $index">{{$index+5}}</option>
</select>
