我有这个dtd: http://fast-code.sourceforge.net/template.dtd 但是当我在xml中包含时,我得到警告: 没有为文档检测到语法约束(DTD或XML模式)。 xml是:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE templates PUBLIC "//UNKNOWN/" "http://fast-code.sourceforge.net/template.dtd">

<templates>
<template type="INSTANCE_OF_CLASS">
    <description>Used to Create instance of class</description>
    <variation>asasa</variation>
    <variation-field>asasa</variation-field>
    <class-pattern>asasa</class-pattern>
    <getter-setter>setter</getter-setter>
    <allowed-file-extensions>java</allowed-file-extensions>
    <number-required-classes>1</number-required-classes>
    <allow-multiple-variation>false</allow-multiple-variation>
    <template-body>
        <![CDATA[
            // Creating new instance of ${class_name}
            final ${class_name} ${instance} = new ${class_name}();
            #foreach ($field in ${fields})
                ${instance}.${field.setter}(${field.value});
            #end
        ]]>
    </template-body>
</template>
</templates>

编辑:我改变了xml,我现在得到这个错误:

元素类型“template”的内容必须匹配“(description,variation?,variation-field?,允许 multiple-variation ?,阶级结构? getter-setter ? allowed-file-extensions吗?阈值- 类?模板体内)”。


当前回答

答:

下面每个DTD部分的注释。更多信息请参考官方规范。

  <!
  DOCTYPE ----------------------------------------- correct
  templates --------------------------------------- correct  Name matches root element.
  PUBLIC ------------------------------------------ correct  Accessing external subset via URL.
  "//UNKNOWN/" ------------------------------------ invalid? Seems useless, wrong, out-of-place.
                                                             Safely replaceable by DTD URL in next line.
  "http://fast-code.sourceforge.net/template.dtd" - invalid  URL is currently broken.
  >

简单的解释:

一个非常基本的DTD看起来就像这里的第二行:

<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE nameOfYourRootElement>
<nameOfYourRootElement>
</nameOfYourRootElement>

详细解释:

dtd用于建立商定的数据格式并验证此类数据的接收。它们定义了XML文档的结构,包括:

法律要素清单 特殊字符 字符串 还有更多

E.g.

<!DOCTYPE nameOfYourRootElement
[
<!ELEMENT nameOfYourRootElement (nameOfChildElement1,nameOfChildElement2)>
<!ELEMENT nameOfChildElement1 (#PCDATA)>
<!ELEMENT nameOfChildElement2 (#PCDATA)>
<!ENTITY nbsp "&#xA0;"> 
<!ENTITY author "Your Author Name">
]>

Meaning of above lines... Line 1) Root element defined as "nameOfYourRootElement" Line 2) Start of element definitions Line 3) Root element children defined as "nameOfYourRootElement1" and "nameOfYourRootElement2" Line 4) Child element, which is defined as data type #PCDATA Line 5) Child element, which is defined as data type #PCDATA Line 6) Expand instances of &nbsp; to &#xA0; when document is parsed by XML parser Line 7) Expand instances of &author; to Your Author Name when document is parsed by XML parser Line 8) End of definitions

其他回答

What I found to be the solution was something very very simple that I think you should try before tinkering with the preferences. In my case I had this problem in a strings file that had as a base tag "resources" ...all I did was delete the tag from the top and the bottom, clean the project, save the file and reinsert the tag. The problem has since disappeared and never gave me any warnings. It may sound to simple to be true but hey, sometimes it's the simplest things that solve the problems. Cheers

我通过指定<!来消除这个恼人的警告。DOCTYPE xml> <?xml……>标记,而不是指定其他内容(如在您的情况下的模板)。

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xml>

我在eclipse中使用web.xml文件时也遇到了同样的问题 它向我展示了这个“文档中没有引用语法约束”

但可以通过添加标签来解决 在XML标记之后,即<?xml version = "1.0" encoding = "UTF-8"?>

试着理解警告信息中给出的建议,这有时是有帮助的。

我也有同样的问题,在做了一些研究后,我找到了解决方案,并在开头添加了下面的一行

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xml>

这就引出了我的另一个问题。 我通过阅读建议解决了这个问题,这又变成了另一个问题,这个问题已经解决了,理解了最初的原因,第一个链接被打破了(没有找到)。下面是一步一步的图片,解释了已经做了什么来完全解决这个问题。

添加DOCTYPE标签…

在这种情况下:

<!DOCTYPE xml>

添加后:

<?xml version="1.0" encoding="UTF-8"?>

So:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xml>