我在React中构建了一个组件,它应该在窗口滚动上更新自己的风格,以创建视差效果。

组件渲染方法是这样的:

  function() {
    let style = { transform: 'translateY(0px)' };

    window.addEventListener('scroll', (event) => {
      let scrollTop = event.srcElement.body.scrollTop,
          itemTranslate = Math.min(0, scrollTop/3 - 60);

      style.transform = 'translateY(' + itemTranslate + 'px)');
    });

    return (
      <div style={style}></div>
    );
  }

这是行不通的,因为React不知道组件已经更改,因此组件不会重新呈现。

我已经尝试在组件的状态中存储itemTranslate的值,并在滚动回调中调用setState。然而,这使得滚动无法使用,因为它非常慢。

有什么建议吗?


当前回答

您应该在componentDidMount中绑定侦听器,这样它只创建一次。您应该能够在状态中存储样式,侦听器可能是性能问题的原因。

就像这样:

componentDidMount: function() {
    window.addEventListener('scroll', this.handleScroll);
},

componentWillUnmount: function() {
    window.removeEventListener('scroll', this.handleScroll);
},

handleScroll: function(event) {
    let scrollTop = event.srcElement.body.scrollTop,
        itemTranslate = Math.min(0, scrollTop/3 - 60);

    this.setState({
      transform: itemTranslate
    });
},

其他回答

用钩子:

import React, { useEffect, useState } from 'react';

function MyApp () {

    const [offset, setOffset] = useState(0);

    useEffect(() => {
        const onScroll = () => setOffset(window.pageYOffset);
        // clean up code
        window.removeEventListener('scroll', onScroll);
        window.addEventListener('scroll', onScroll, { passive: true });
        return () => window.removeEventListener('scroll', onScroll);
    }, []);

    console.log(offset); 
};
constructor() {
    super()
      this.state = {
        change: false
      }
  }

  componentDidMount() {
    window.addEventListener('scroll', this.handleScroll);
    console.log('add event');
  }

  componentWillUnmount() {
    window.removeEventListener('scroll', this.handleScroll);
    console.log('remove event');
  }

  handleScroll = e => {
    if (window.scrollY === 0) {
      this.setState({ change: false });
    } else if (window.scrollY > 0 ) {
      this.setState({ change: true });
    }
  }

render() {return (<div className="main" style={{boxShadow: this.state.change ?0px 6px 12px rgba(3,109,136,0.14):none}} ></div> .

我就是这么做的,而且效果很好。

一个使用classNames, React挂钩useEffect, useState和styles -jsx的例子:

import classNames from 'classnames'
import { useEffect, useState } from 'react'

const Header = _ => {
  const [ scrolled, setScrolled ] = useState()
  const classes = classNames('header', {
    scrolled: scrolled,
  })
  useEffect(_ => {
    const handleScroll = _ => { 
      if (window.pageYOffset > 1) {
        setScrolled(true)
      } else {
        setScrolled(false)
      }
    }
    window.addEventListener('scroll', handleScroll)
    return _ => {
      window.removeEventListener('scroll', handleScroll)
    }
  }, [])
  return (
    <header className={classes}>
      <h1>Your website</h1>
      <style jsx>{`
        .header {
          transition: background-color .2s;
        }
        .header.scrolled {
          background-color: rgba(0, 0, 0, .1);
        }
      `}</style>
    </header>
  )
}
export default Header

下面是另一个使用HOOKS fontAwesomeIcon和Kendo UI React的例子 [![这里截图][1]][1]

import { FontAwesomeIcon } from '@fortawesome/react-fontawesome';


const ScrollBackToTop = () => {
  const [show, handleShow] = useState(false);

  useEffect(() => {
    window.addEventListener('scroll', () => {
      if (window.scrollY > 1200) {
        handleShow(true);
      } else handleShow(false);
    });
    return () => {
      window.removeEventListener('scroll');
    };
  }, []);

  const backToTop = () => {
    window.scroll({ top: 0, behavior: 'smooth' });
  };

  return (
    <div>
      {show && (
      <div className="backToTop text-center">
        <button className="backToTop-btn k-button " onClick={() => backToTop()} >
          <div className="d-none d-xl-block mr-1">Top</div>
          <FontAwesomeIcon icon="chevron-up"/>
        </button>
      </div>
      )}
    </div>
  );
};

export default ScrollBackToTop;```


  [1]: https://i.stack.imgur.com/ZquHI.png

你可以传递一个函数给React元素的onScroll事件:https://facebook.github.io/react/docs/events.html#ui-events

<ScrollableComponent
 onScroll={this.handleScroll}
/>

另一个类似的答案是:https://stackoverflow.com/a/36207913/1255973