在我的一个脚本中得到以下代码:
#
# url is defined above.
#
jsonurl = urlopen(url)
#
# While trying to debug, I put this in:
#
print jsonurl
#
# Was hoping text would contain the actual json crap from the URL, but seems not...
#
text = json.loads(jsonurl)
print text
我要做的是获得{{.....等.....}}东西，我看到的URL，当我在Firefox加载到我的脚本，所以我可以解析出一个值。我已经谷歌了很多，但我还没有找到一个很好的答案，如何实际得到{{…}}将以.json结尾的URL转换为Python脚本中的对象。
当前回答
这将从Python 2的网页中获取JSON格式的字典。X和Python 3。X:
#!/usr/bin/env python
try:
# For Python 3.0 and later
from urllib.request import urlopen
except ImportError:
# Fall back to Python 2's urllib2
from urllib2 import urlopen
import json
def get_jsonparsed_data(url):
"""
Receive the content of ``url``, parse it as JSON and return the object.
Parameters
----------
url : str
Returns
-------
dict
"""
response = urlopen(url)
data = response.read().decode("utf-8")
return json.loads(data)
url = ("http://maps.googleapis.com/maps/api/geocode/json?"
"address=googleplex&sensor=false")
print(get_jsonparsed_data(url))
请参见:JSON的读写示例
其他回答
从URL获取数据，然后调用json。加载。
Python3例子:
import urllib.request, json
with urllib.request.urlopen("http://maps.googleapis.com/maps/api/geocode/json?address=google") as url:
data = json.load(url)
print(data)
Python2例子:
import urllib, json
url = "http://maps.googleapis.com/maps/api/geocode/json?address=google"
response = urllib.urlopen(url)
data = json.loads(response.read())
print data
输出结果如下所示:
{
"results" : [
{
"address_components" : [
{
"long_name" : "Charleston and Huff",
"short_name" : "Charleston and Huff",
"types" : [ "establishment", "point_of_interest" ]
},
{
"long_name" : "Mountain View",
"short_name" : "Mountain View",
"types" : [ "locality", "political" ]
},
{
...
没有必要使用额外的库来解析json…
Json.loads()返回一个字典。
在你的例子中，只需输入text["someValueKey"]
这将从Python 2的网页中获取JSON格式的字典。X和Python 3。X:
#!/usr/bin/env python
try:
# For Python 3.0 and later
from urllib.request import urlopen
except ImportError:
# Fall back to Python 2's urllib2
from urllib2 import urlopen
import json
def get_jsonparsed_data(url):
"""
Receive the content of ``url``, parse it as JSON and return the object.
Parameters
----------
url : str
Returns
-------
dict
"""
response = urlopen(url)
data = response.read().decode("utf-8")
return json.loads(data)
url = ("http://maps.googleapis.com/maps/api/geocode/json?"
"address=googleplex&sensor=false")
print(get_jsonparsed_data(url))
请参见:JSON的读写示例
你需要导入请求并使用from json()方法:
source = requests.get("url").json()
print(source)
当然，这个方法也适用:
import json,urllib.request
data = urllib.request.urlopen("url").read()
output = json.loads(data)
print (output)
json。load将使用此表将其解码为Python对象，例如JSON对象将成为Python dict。
对于python>=3.6，您可以使用:
import dload
j = dload.json(url)
安装dload:
pip3 install dload
