如何在不使用存储库的情况下将Docker映像从一台机器传输到另一台机器,无论是私有还是公共的?

我在VirtualBox中创建了自己的映像,完成后,我尝试部署到其他机器上以获得实际使用。

由于它基于我自己的镜像(如Red Hat Linux),因此无法从Dockerfile中重新创建。我的dockerfile不容易移植。

有没有简单的命令可以使用?还是另一种解决方案?


当前回答

要将图像从本地Docker安装传输到minikube VM:

docker save <image> | (eval $(minikube docker-env) && docker load)

其他回答

对于容器文件系统的扁平导出,请使用;

docker导出CONTAINER_ID>my_CONTAINER.tar

使用cat my_container.tar | docker import-导入所述图像。

真实世界示例

#host1
systemctl stop docker
systemctl start docker
docker commit -p 1d09068ef111 ubuntu001_bkp3
#create backup
docker save -o ubuntu001_bkp3.tar ubuntu001_bkp3

#upload ubuntu001_bkp3.tar to my online drive
aws s3 cp ubuntu001_bkp3.tar s3://mybucket001/


#host2
systemctl stop docker
systemctl start docker
cd /dir1

#download ubuntu001_bkp3.tar from my online drive
aws s3 cp s3://mybucket001/ubuntu001_bkp3.tar /dir1

#restore backup
cat ./ubuntu001_bkp3.tar  | docker load
docker run --name ubuntu001 -it ubuntu001_bkp3:latest bash
docker ps -a
docker attach ubuntu001




要将图像从本地Docker安装传输到minikube VM:

docker save <image> | (eval $(minikube docker-env) && docker load)

您可以使用sshfs:

$ sshfs user@ip:/<remote-path> <local-mount-path>
$ docker save <image-id> > <local-mount-path>/myImage.tar

执行Docker保存和加载功能的脚本(已试用):

Docker保存:

#!/bin/bash

#files will be saved in the dir 'Docker_images'
mkdir Docker_images
cd Docker_images
directory=`pwd`
c=0
#save the image names in 'list.txt'
doc= docker images | awk '{print $1}' > list.txt
printf "START \n"
input="$directory/list.txt"
#Check and create the image tar for the docker images
while IFS= read -r line
do
     one=`echo $line | awk '{print $1}'`
     two=`echo $line | awk '{print $1}' | cut -c 1-3`
     if [ "$one" != "<none>" ]; then
             c=$((c+1))
             printf "\n $one \n $two \n"
             docker save -o $two$c'.tar' $one
             printf "Docker image number $c successfully converted:   $two$c \n \n"
     fi
done < "$input"

Docker加载:

#!/bin/bash

cd Docker_images/
directory=`pwd`
ls | grep tar > files.txt
c=0
printf "START \n"
input="$directory/files.txt"
while IFS= read -r line
do
     c=$((c+1))
     printf "$c) $line \n"
     docker load -i $line
     printf "$c) Successfully created the Docker image $line  \n \n"
done < "$input"