考虑在Python中使用print的以下示例:

>>> for i in range(4): print('.')
.
.
.
.
>>> print('.', '.', '.', '.')
. . . .

在每个值之间添加换行符或空格。我怎样才能避免这种情况,从而使输出。。。。相反换句话说,如何将字符串“附加”到标准输出流?


当前回答

这里有三个代码供您选择:

print("".join(["." for i in range(4)]))

or

print("." + "." + "." + ".")

or

print(".", ".", ".", ".", sep="")

其他回答

为Python 2.6+使用Python 3样式打印函数(它还将打破同一文件中任何现有的带关键字的打印语句)。

# For Python 2 to use the print() function, removing the print keyword
from __future__ import print_function
for x in xrange(10):
    print('.', end='')

为了不破坏所有Python 2打印关键字,请创建一个单独的printf.py文件:

# printf.py

from __future__ import print_function

def printf(str, *args):
    print(str % args, end='')

然后,在文件中使用它:

from printf import printf
for x in xrange(10):
    printf('.')
print 'done'
#..........done

显示printf样式的更多示例:

printf('hello %s', 'world')
printf('%i %f', 10, 3.14)
#hello world10 3.140000

如何在同一行打印:

import sys
for i in xrange(0,10):
   sys.stdout.write(".")
   sys.stdout.flush()

您可以在Python 3中执行以下操作:

#!usr/bin/python

i = 0
while i<10 :
    print('.', end='')
    i = i+1

并使用python filename.py或python3 filename.py。

注意:这个问题的标题以前类似于“How to printf in Python”

由于人们可能会根据标题来这里寻找它,Python也支持printf样式替换:

>>> strings = [ "one", "two", "three" ]
>>>
>>> for i in xrange(3):
...     print "Item %d: %s" % (i, strings[i])
...
Item 0: one
Item 1: two
Item 2: three

而且,您可以方便地相乘字符串值:

>>> print "." * 10
..........

Python 3:

print('.', end='')

Python 2.6+:

from __future__ import print_function # needs to be first statement in file
print('.', end='')

Python<=2.5:

import sys
sys.stdout.write('.')

如果每次打印后都有多余的空间,在Python 2中:

print '.',

Python 2中的误导-避免:

print('.'), # Avoid this if you want to remain sane
# This makes it look like print is a function, but it is not.
# This is the `,` creating a tuple and the parentheses enclose an expression.
# To see the problem, try:
print('.', 'x'), # This will print `('.', 'x') `