下面是@ program作为UIViewController类别的解决方案:

// UIViewController+Additions.h

@interface UIViewController (Additions)

- (BOOL)isVisible;

@end


// UIViewController+Additions.m

#import "UIViewController+Additions.h"

@implementation UIViewController (Additions)

- (BOOL)isVisible {
    return [self isViewLoaded] && self.view.window;
}

@end

你可以通过window属性来检查

if(viewController.view.window){

// view visible

}else{

// no visible

}

对于那些正在寻找Swift 2.2版本的答案的人:

if self.isViewLoaded() && (self.view.window != nil) {
     // viewController is visible
}

Swift 3:

if self.isViewLoaded && (self.view.window != nil) {
         // viewController is visible
}

下面是@ program作为UIViewController类别的解决方案:

// UIViewController+Additions.h

@interface UIViewController (Additions)

- (BOOL)isVisible;

@end


// UIViewController+Additions.m

#import "UIViewController+Additions.h"

@implementation UIViewController (Additions)

- (BOOL)isVisible {
    return [self isViewLoaded] && self.view.window;
}

@end

我需要这个来检查是否视图控制器是当前的视图控制器，我通过检查是否有任何呈现的视图控制器或通过导航器推送，我张贴它以防有人需要这样的解决方案:

if presentedViewController != nil || navigationController?.topViewController != self {
      //Viewcontroller isn't viewed
}else{
     // Now your viewcontroller is being viewed 
}

我在Swift 5中使用这个小扩展，它使它保持简单和容易检查UIView成员的任何对象。

extension UIView {
    var isVisible: Bool {
        guard let _ = self.window else {
            return false
        }
        return true
    }
}

然后，我只是用它作为一个简单的if语句检查…

if myView.isVisible {
    // do something
}

我希望这能有所帮助!:)