if (string.length == 0) stringIsEmpty;

马克的回答是正确的。但我想借此机会引用Wil Shipley在他的博客上分享的一般化的isEmpty:

static inline BOOL IsEmpty(id thing) {
return thing == nil
|| ([thing respondsToSelector:@selector(length)]
&& [(NSData *)thing length] == 0)
|| ([thing respondsToSelector:@selector(count)]
&& [(NSArray *)thing count] == 0);
}

第一种方法是有效的，但如果字符串中有空格(@" ")则无效。所以在测试之前必须清除这些空白。

这段代码清除了字符串两边的所有空格:

[stringObject stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet] ];

一个好主意是创建一个宏，这样你就不必输入这一行怪物:

#define allTrim( object ) [object stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet] ]

现在你可以使用:

NSString *emptyString = @"   ";

if ( [allTrim( emptyString ) length] == 0 ) NSLog(@"Is empty!");

//Different validations:
 NSString * inputStr = @"Hey ";

//Check length
[inputStr length]

//Coming from server, check if its NSNull
[inputStr isEqual:[NSNull null]] ? nil : inputStr

//For validation in allowed character set
-(BOOL)validateString:(NSString*)inputStr
{
    BOOL isValid = NO;
    if(!([inputStr length]>0))
    {
        return isValid;

    }

    NSMutableCharacterSet *allowedSet = [NSMutableCharacterSet characterSetWithCharactersInString:@".-"];
    [allowedSet formUnionWithCharacterSet:[NSCharacterSet decimalDigitCharacterSet]];
    if ([inputStr rangeOfCharacterFromSet:[allowedSet invertedSet]].location == NSNotFound)
    {
        // contains only decimal set and '-' and '.'

    }
    else
    {
        // invalid
        isValid = NO;

    }
    return isValid;
}

- (BOOL)isEmpty:(NSString *)string{
    if ((NSNull *) string == [NSNull null]) {
        return YES;
    }
    if (string == nil) {
        return YES;
    }
    if ([string length] == 0) {
        return YES;
    }
    if ([[string stringByTrimmingCharactersInSet: [NSCharacterSet whitespaceAndNewlineCharacterSet]] length] == 0) {
        return YES;
    }
    if([[string stringByStrippingWhitespace] isEqualToString:@""]){
        return YES;
    }
    return NO;
}

if (string.length == 0) stringIsEmpty;