如果您希望只显示两位数的时间，这可能会帮助您：

var now = new Date();
var cHour = now.getHours();
var cMinuts = now.getMinutes();
var cSeconds = now.getSeconds();

var outStr = (cHour <= 0 ? ('0' + cHour) : cHour) + ':' + (cMinuts <= 9 ? ('0' + cMinuts) : cMinuts) + ':' + (cSeconds <= 9 ? '0' + cSeconds : cSeconds);

DateJS当然是功能齐全的，但我推荐这种非常简单的库（JavaScript日期格式），我更喜欢它，因为它只有120行左右。

许多框架（您可能已经在使用）具有您可能不知道的日期格式。jQueryUI已经被提及，但其他框架如Kendo UI（全球化）、Yahoo UI（Util）和AngularJS也有。

// 11/6/2000
kendo.toString(new Date(value), "d")

// Monday, November 06, 2000
kendo.toString(new Date(2000, 10, 6), "D")

如果您不需要Moment.js这样的库提供的所有功能，那么可以使用我的strftime端口。它是轻量级的（与Moment.js 2.15.0相比，减少了1.35 KB和57.9 KB），并提供了strftime（）的大部分功能。

/* Port of strftime(). Compatibility notes:
 *
 * %c - formatted string is slightly different
 * %D - not implemented (use "%m/%d/%y" or "%d/%m/%y")
 * %e - space is not added
 * %E - not implemented
 * %h - not implemented (use "%b")
 * %k - space is not added
 * %n - not implemented (use "\n")
 * %O - not implemented
 * %r - not implemented (use "%I:%M:%S %p")
 * %R - not implemented (use "%H:%M")
 * %t - not implemented (use "\t")
 * %T - not implemented (use "%H:%M:%S")
 * %U - not implemented
 * %W - not implemented
 * %+ - not implemented
 * %% - not implemented (use "%")
 *
 * strftime() reference:
 * http://man7.org/linux/man-pages/man3/strftime.3.html
 *
 * Day of year (%j) code based on Joe Orost's answer:
 * http://stackoverflow.com/questions/8619879/javascript-calculate-the-day-of-the-year-1-366
 *
 * Week number (%V) code based on Taco van den Broek's prototype:
 * http://techblog.procurios.nl/k/news/view/33796/14863/calculate-iso-8601-week-and-year-in-javascript.html
 */
function strftime(sFormat, date) {
  if (!(date instanceof Date)) date = new Date();
  var nDay = date.getDay(),
    nDate = date.getDate(),
    nMonth = date.getMonth(),
    nYear = date.getFullYear(),
    nHour = date.getHours(),
    aDays = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday'],
    aMonths = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'],
    aDayCount = [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334],
    isLeapYear = function() {
      if (nYear&3!==0) return false;
      return nYear%100!==0 || year%400===0;
    },
    getThursday = function() {
      var target = new Date(date);
      target.setDate(nDate - ((nDay+6)%7) + 3);
      return target;
    },
    zeroPad = function(nNum, nPad) {
      return ('' + (Math.pow(10, nPad) + nNum)).slice(1);
    };
  return sFormat.replace(/%[a-z]/gi, function(sMatch) {
    return {
      '%a': aDays[nDay].slice(0,3),
      '%A': aDays[nDay],
      '%b': aMonths[nMonth].slice(0,3),
      '%B': aMonths[nMonth],
      '%c': date.toUTCString(),
      '%C': Math.floor(nYear/100),
      '%d': zeroPad(nDate, 2),
      '%e': nDate,
      '%F': date.toISOString().slice(0,10),
      '%G': getThursday().getFullYear(),
      '%g': ('' + getThursday().getFullYear()).slice(2),
      '%H': zeroPad(nHour, 2),
      '%I': zeroPad((nHour+11)%12 + 1, 2),
      '%j': zeroPad(aDayCount[nMonth] + nDate + ((nMonth>1 && isLeapYear()) ? 1 : 0), 3),
      '%k': '' + nHour,
      '%l': (nHour+11)%12 + 1,
      '%m': zeroPad(nMonth + 1, 2),
      '%M': zeroPad(date.getMinutes(), 2),
      '%p': (nHour<12) ? 'AM' : 'PM',
      '%P': (nHour<12) ? 'am' : 'pm',
      '%s': Math.round(date.getTime()/1000),
      '%S': zeroPad(date.getSeconds(), 2),
      '%u': nDay || 7,
      '%V': (function() {
              var target = getThursday(),
                n1stThu = target.valueOf();
              target.setMonth(0, 1);
              var nJan1 = target.getDay();
              if (nJan1!==4) target.setMonth(0, 1 + ((4-nJan1)+7)%7);
              return zeroPad(1 + Math.ceil((n1stThu-target)/604800000), 2);
            })(),
      '%w': '' + nDay,
      '%x': date.toLocaleDateString(),
      '%X': date.toLocaleTimeString(),
      '%y': ('' + nYear).slice(2),
      '%Y': nYear,
      '%z': date.toTimeString().replace(/.+GMT([+-]\d+).+/, '$1'),
      '%Z': date.toTimeString().replace(/.+\((.+?)\)$/, '$1')
    }[sMatch] || sMatch;
  });
}

示例用法：

strftime('%F'); // Returns "2016-09-15"
strftime('%A, %B %e, %Y'); // Returns "Thursday, September 15, 2016"

// You can optionally pass it a Date object...

strftime('%x %X', new Date('1/1/2016')); // Returns "1/1/2016 12:00:00 AM"

此处提供最新代码：https://github.com/thdoan/strftime

确保在JavaScript中处理日期时签出Datejs。正如您在toString函数的例子中看到的那样，它非常令人印象深刻，并且有很好的文档记录。

编辑：Tyler Forsyth指出，datejs已经过时了。我在当前的项目中使用了它，并没有遇到任何问题，但您应该意识到这一点，并考虑其他选择。

我做了一个非常简单的格式化程序，它是cut/n/postable（更新了更整洁的版本）：

function DateFmt(fstr) {
  this.formatString = fstr

  var mthNames = ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"];
  var dayNames = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"];
  var zeroPad = function(number) {
     return ("0"+number).substr(-2,2);
  }

  var dateMarkers = {
    d:['getDate',function(v) { return zeroPad(v)}],
    m:['getMonth',function(v) { return zeroPad(v+1)}],
    n:['getMonth',function(v) { return mthNames[v]; }],
    w:['getDay',function(v) { return dayNames[v]; }],
    y:['getFullYear'],
    H:['getHours',function(v) { return zeroPad(v)}],
    M:['getMinutes',function(v) { return zeroPad(v)}],
    S:['getSeconds',function(v) { return zeroPad(v)}],
    i:['toISOString']
  };

  this.format = function(date) {
    var dateTxt = this.formatString.replace(/%(.)/g, function(m, p) {
      var rv = date[(dateMarkers[p])[0]]()

      if ( dateMarkers[p][1] != null ) rv = dateMarkers[p][1](rv)

      return rv

    });

    return dateTxt
  }

}

fmt = new DateFmt("%w %d:%n:%y - %H:%M:%S  %i")
v = fmt.format(new Date())

http://snipplr.com/view/66968.82825/