给定files.txt中的文件列表,我可以得到它们的大小列表,如下所示:
cat files.txt | xargs ls -l | cut -c 23-30
这会产生这样的结果:
151552
319488
1536000
225280
我怎样才能得到所有这些数字的总数呢?
给定files.txt中的文件列表,我可以得到它们的大小列表,如下所示:
cat files.txt | xargs ls -l | cut -c 23-30
这会产生这样的结果:
151552
319488
1536000
225280
我怎样才能得到所有这些数字的总数呢?
当前回答
sizes=( $(cat files.txt | xargs ls -l | cut -c 23-30) )
total=$(( $(IFS="+"; echo "${sizes[*]}") ))
或者你可以一边看大小一边把它们加起来
declare -i total=0
while read x; total+=x; done < <( cat files.txt | xargs ls -l | cut -c 23-30 )
如果你不关心咬的大小和块是可以的,那么
declare -i total=0
while read s junk; total+=s; done < <( cat files.txt | xargs ls -s )
其他回答
我喜欢使用....
echo "
1
2
3 " | sed -e 's,$, + p,g' | dc
它们会显示每一行的和…
适用于这种情况:
ls -ld $(< file.txt) | awk '{print $5}' | sed -e 's,$, + p,g' | dc
Total是最后一个值…
打印ksh:
echo " 0 $(ls -l $(<files.txt) | awk '{print $5}' | tr '\n' '+') 0" | bc
#
# @(#) addup.sh 1.0 90/07/19
#
# Copyright (C) <heh> SjB, 1990
# Adds up a column (default=last) of numbers in a file.
# 95/05/16 updated to allow (999) negative style numbers.
case $1 in
-[0-9])
COLUMN=`echo $1 | tr -d -`
shift
;;
*)
COLUMN="NF"
;;
esac
echo "Adding up column .. $COLUMN .. of file(s) .. $*"
nawk ' OFMT="%.2f" # 1 "%12.2f"
{ x = '$COLUMN' # 2
neg = index($x, "$") # 3
if (neg > 0) X = gsub("\\$", "", $x)
neg = index($x, ",") # 4
if (neg > 1) X = gsub(",", "", $x)
neg = index($x, "(") # 8 neg (123 & change
if (neg > 0) X = gsub("\\(", "", $x)
if (neg > 0) $x = (-1 * $x) # it to "-123.00"
neg = index($x, "-") # 5
if (neg > 1) $x = (-1 * $x) # 6
t += $x # 7
print "x is <<<", $x+0, ">>> running balance:", t
} ' $*
# 1. set numeric format to eliminate rounding errors
# 1.1 had to reset numeric format from 12.2f to .2f 95/05/16
# when a computed number is assigned to a variable ( $x = (-1 * $x) )
# it causes $x to use the OFMT so -1.23 = "________-1.23" vs "-1.23"
# and that causes my #5 (negative check) to not work correctly because
# the index returns a number >1 and to the neg neg than becomes a positive
# this only occurs if the number happened to b a "(" neg number
# 2. find the field we want to add up (comes from the shell or defaults
# to the last field "NF") in the file
# 3. check for a dollar sign ($) in the number - if there get rid of it
# so we may add it correctly - $12 $1$2 $1$2$ $$1$$2$$ all = 12
# 4. check for a comma (,) in the number - if there get rid of it so we
# may add it correctly - 1,2 12, 1,,2 1,,2,, all = 12 (,12=0)
# 5. check for negative numbers
# 6. if x is a negative number in the form 999- "make" it a recognized
# number like -999 - if x is a negative number like -999 already
# the test fails (y is not >1) and this "true" negative is not made
# positive
# 7. accumulate the total
# 8. if x is a negative number in the form (999) "make it a recognized
# number like -999
# * Note that a (-9) (neg neg number) returns a postive
# * Mite not work rite with all forms of all numbers using $-,+. etc. *
我发现自己会用jq来做这样的事情,即使不使用JSON:
$ echo -e '1\n2\n3' | jq --slurp add
6
它已经成为我最近编写的几乎每个脚本的标准依赖项。
TMTWWTDI: Perl有一个文件大小操作符(-s)
perl -lne '$t+=-s;END{print $t}' files.txt