给定files.txt中的文件列表,我可以得到它们的大小列表,如下所示:

cat files.txt | xargs ls -l | cut -c 23-30

这会产生这样的结果:

  151552
  319488
 1536000
  225280

我怎样才能得到所有这些数字的总数呢?


当前回答

sizes=( $(cat files.txt | xargs ls -l | cut -c 23-30) )
total=$(( $(IFS="+"; echo "${sizes[*]}") ))

或者你可以一边看大小一边把它们加起来

declare -i total=0
while read x; total+=x; done < <( cat files.txt | xargs ls -l | cut -c 23-30 )

如果你不关心咬的大小和块是可以的,那么

declare -i total=0
while read s junk; total+=s; done < <( cat files.txt | xargs ls -s )

其他回答

我喜欢使用....

echo "
1
2
3 " | sed -e 's,$, + p,g' | dc 

它们会显示每一行的和…

适用于这种情况:

ls -ld $(< file.txt) | awk '{print $5}' | sed -e 's,$, + p,g' | dc 

Total是最后一个值…

打印ksh:

echo " 0 $(ls -l $(<files.txt) | awk '{print $5}' | tr '\n' '+') 0" | bc
#
#       @(#) addup.sh 1.0 90/07/19
#
#       Copyright (C) <heh> SjB, 1990
#       Adds up a column (default=last) of numbers in a file.
#       95/05/16 updated to allow (999) negative style numbers.


case $1 in

-[0-9])

        COLUMN=`echo $1 | tr -d -`

        shift

;;

*)

        COLUMN="NF"

;;

esac

echo "Adding up column .. $COLUMN .. of file(s) .. $*"

nawk  ' OFMT="%.2f"                                       # 1 "%12.2f"

        { x = '$COLUMN'                                   # 2

          neg = index($x, "$")                            # 3

          if (neg > 0) X = gsub("\\$", "", $x)

          neg = index($x, ",")                            # 4

          if (neg > 1) X = gsub(",", "", $x)

          neg = index($x, "(")                            # 8 neg (123 & change

          if (neg > 0) X = gsub("\\(", "", $x)

          if (neg > 0) $x = (-1 * $x)                     # it to "-123.00"

          neg = index($x, "-")                            # 5

          if (neg > 1) $x = (-1 * $x)                     # 6

          t += $x                                         # 7

          print "x is <<<", $x+0, ">>> running balance:", t

        } ' $*


# 1.  set numeric format to eliminate rounding errors
# 1.1 had to reset numeric format from 12.2f to .2f 95/05/16
#     when a computed number is assigned to a variable ( $x = (-1 * $x) )
#     it causes $x to use the OFMT so -1.23 = "________-1.23" vs "-1.23"
#     and that causes my #5 (negative check) to not work correctly because
#     the index returns a number >1 and to the neg neg than becomes a positive
#     this only occurs if the number happened to b a "(" neg number
# 2.  find the field we want to add up (comes from the shell or defaults
#     to the last field "NF") in the file
# 3.  check for a dollar sign ($) in the number - if there get rid of it
#     so we may add it correctly - $12 $1$2 $1$2$ $$1$$2$$ all = 12
# 4.  check for a comma (,) in the number - if there get rid of it so we
#     may add it correctly - 1,2 12, 1,,2 1,,2,, all = 12   (,12=0)
# 5.  check for negative numbers
# 6.  if x is a negative number in the form 999- "make" it a recognized
#     number like -999 - if x is a negative number like -999 already
#     the test fails (y is not >1) and this "true" negative is not made
#     positive
# 7.  accumulate the total
# 8.  if x is a negative number in the form (999) "make it a recognized
#     number like -999
# * Note that a (-9) (neg neg number) returns a postive
# * Mite not work rite with all forms of all numbers using $-,+. etc. *

我发现自己会用jq来做这样的事情,即使不使用JSON:

$ echo -e '1\n2\n3' | jq --slurp add
6

它已经成为我最近编写的几乎每个脚本的标准依赖项。

TMTWWTDI: Perl有一个文件大小操作符(-s)

perl -lne '$t+=-s;END{print $t}' files.txt